Explanation
In case of perfectly elastic collision ,the relative velocity remains unchanged in magnitude but reversed in direction. So, velocity of heavy body after collision is V
Watt and Horsepower are the units of power.
Because 50% loss in kinetic energy will after its potential energy due to this ball will attain only half of the initial height.
The speed of roller coaster at point D is u as there is no loss of energy. So, final velocity is same as initial velocity.
Graph between potential energy versus distance is positive parabolic.
Momentum of 5kg mass after the collision is 4 kg m/s
At first collision , both particles exchange their velocities . so ,after two collision they will reach at point A ,so option (c) is correct
When the velocity is less than the escape velocity , the missile cannot escape the gravitational field of earth. Within the gravitational field, the sum of potential and kinetic energies of the missile will be negative.
Whatever be the displacement, net work done, W = F(x) + (−F)x = 0
Because water enters into the vessel A, it becomes heavier. Gravity helps it sink. External work required for immersing A is obviously less than that for immersing B.
In going from A to B, object rises through AC = OA – OC= l – l cos θ = l(1 – cos θ ). Work done = gain in P. E = mgl (1 – cosθ ).
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