Explanation
As bob B is of same material and same mass as the bob A, therefore, on elastic collision,their velocities are exchanged. Bob A comes to rest and B moves with the velocity of A.
Gravitational field is a conservative field. Therefore, work done in moving a particle from A to B is independent of path chosen. ∴ W1 = W2 = W3
W = Fdcosθ
ΔK = cosFdKθ = w
W = Fd = (Mg)(d); where M = m1 + m2.
W = Area under curve of F → x graph.
W = F x = max = (m) (Area covered by curve of a → x graph).
Work W = Area covered by curve of F → x graph.
Gravitational force is a conservative force and work done against it is a point function i.e. does not depends on the path.
Work done = gain in potential energy Area under curve = mgh
Work = Area under (F – d) graph
Energy U ∝ x2 ( k constant).
F. Δt = momentum, The resulatant fore is zero, therefore F. Δt = 0.
Kinetic Energy (K.E) ∝ v2 and v2 ∝ t2 ....
P.E (U) ∝ h and E = K + U = constant.
Loss of potential energy = Kinetic energy gained.
Work done = Area under F → X graph with proper sign.
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