Two wires of equal diameters, of resistivities ρ 1 and ρ 2 and lengths l 1 and l 2 , respectively, are joined in series. The equivalent resistivity of the combination is :

ρ 1 l 2 + ρ 2 l 1 l 1 − l 2

ρ 1 l 1 − ρ 2 l 2 l 1 − l 2

Physics - Current Electricity - Quiz-3

The equivalent resistance of the arrangement of resistances shown in adjoining figure between the points A and B is

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6 ohm
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8 ohm
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16 ohm
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24 ohm

In the network of resistors shown in the adjoining figure, the equivalent resistance between A and B is

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54 ohm
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18 ohm
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36 ohm
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9 ohm

A wire is broken in four equal parts. A packet is formed by keeping the four wires together. The resistance of the packet in comparison to the resistance of the wire will be

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Equal
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One fourth
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One eight
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$\frac{1}{16} t h$

Four resistances are connected in a circuit in the given figure. The electric current flowing through 4 ohm and 6 ohm resistance is respectively

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2 amp and 4 amp
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1 amp and 2 amp
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1 amp and 1 amp
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2 amp and 2 amp

In the given figure, when key K is opened, the reading of the ammeter A will be

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50 A
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2 A
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0.5 A
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$\frac{10}{9} A$

In the given circuit, the potential of the point E is

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Zero
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–8 V
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–4/3 V
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4/3 V

If a resistance R₂ is connected in parallel with the resistance R in the circuit shown, then possible value of current through R and the possible value of R₂ will be

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$\frac{I}{3}, R$
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$I, 2 R$
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$\frac{I}{3}, R$
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$\frac{I}{2}, R$

A battery of e.m.f. 10 V is connected to resistance as shown in figure. The potential difference $V_{A} - V_{B}$ between the points A and B is

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–2 V
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2 V
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5 V
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$\frac{20}{11} V$

A student has 10 resistors of resistance ‘r’. The minimum resistance made by him from given resistors is :

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10 r
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$\frac{r}{10}$
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$\frac{r}{100}$
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$\frac{r}{5}$

Two wires of same metal have the same length but their cross-sections are in the ratio 3 : 1. They are joined in series. The resistance of the thicker wire is 10 Ω. The total resistance of the combination will be

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40 Ω
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$\frac{40}{3} Ω$
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$\frac{5}{2} Ω$
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100 Ω

The equivalent resistance of the following infinite network of resistances is

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Less than 4 Ω
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4 Ω
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More than 4 Ω but less than 12 Ω
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12 Ω

In the figure given below, the current passing through 6 Ω resistor is

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0.40 ampere
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0.48 ampere
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0.72 ampere
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0.80 ampere

The equivalent resistance between points A and B of an infinite network of resistances each of 1 Ω connected as shown, is

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Infinite
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2 Ω
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$\frac{1 + \sqrt{5}}{2} Ω$
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Zero

In the circuit shown, the point ‘B’ is earthed. The potential at the point ‘A’ is :

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14 V
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24 V
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26 V
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50 V

In the circuit shown below, the cell has an e.m.f. of 10 V and internal resistance of 1 ohm. The other resistances are shown in the figure. The potential difference $V_{A} - V_{B}$ is :

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6 V
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4 V
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2 V
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–2 V

A wire of resistance R is cut into ‘n’ equal parts. These parts are then connected in parallel. The equivalent resistance of the combination will be :

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nR
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$\frac{R}{n}$
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$\frac{n}{R}$
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$\frac{R}{n^{2}}$

The current in the given circuit is

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8.31 A
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6.82 A
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4.92 A
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2 A

What is the current (i) in the circuit as shown in figure

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2 A
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1.2 A
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1 A
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0.5 A

n equal resistors are first connected in series and then connected in parallel. What is the ratio of the maximum to the minimum resistance

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n
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$\frac{1}{n^{2}}$
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n²
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$\frac{1}{n}$

In the figure, current through the 3 Ω resistor is 0.8 ampere, then potential drop through 4 Ω resistor is

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9.6 V
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2.6 V
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4.8 V
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1.2 V

What is the equivalent resistance between A and B in the figure below if R = 3 Ω

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9 Ω
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12 Ω
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15 Ω
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None of these

What is the equivalent resistance between A and B

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$\frac{2}{3} R$
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$\frac{3}{2} R$
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$\frac{R}{2}$
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2 R

What is the equivalent resistance of the circuit?

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6 Ω
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7 Ω
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8 Ω
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9 Ω

The equivalent resistance of the circuit shown in the figure is :

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8 Ω
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6 Ω
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5 Ω
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4 Ω

In the given figure, the equivalent resistance between the points A and B is :

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8 Ω
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6 Ω
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4 Ω
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2 Ω

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be

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19 Ω
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17 Ω
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10 Ω
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12 Ω

The potential drop across the 3Ω resistor is

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1 V
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1.5 V
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2 V
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3 V

If each resistance in the figure is 9 Ω, then the reading of the ammeter is:

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5 A
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8 A
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2 A
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9 A

Two wires of equal diameters, of resistivities ρ₁and ρ₂ and lengths l₁ and l₂, respectively, are joined in series. The equivalent resistivity of the combination is :

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$\frac{ρ_{1} l_{1} + ρ_{2} l_{2}}{l_{1} + l_{2}}$
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$\frac{ρ_{1} l_{2} + ρ_{2} l_{1}}{l_{1} - l_{2}}$
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$\frac{ρ_{1} l_{2} + ρ_{2} l_{1}}{l_{1} + l_{2}}$
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$\frac{ρ_{1} l_{1} - ρ_{2} l_{2}}{l_{1} - l_{2}}$

Four resistances of 100 Ω each are connected in the form of square. Then, the effective resistance along the diagonal points is :

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200 Ω
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400 Ω
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100 Ω
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150 Ω

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Practice Physics Quiz Questions and Answers

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Practice Physics Quiz Questions and Answers

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