Kirchhoff’s first and second laws for electrical circuits are consequences of:
conservation of energy.
conservation of electric charge and energy respectively.
conservation of electric charge.
conservation of energy and electric charge respectively.
If you are provided three resistances 2 Ω, 3 Ω and 6 Ω. How will you connect them so as to obtain the equivalent resistance of 4 Ω
None of these
The equivalent resistance and potential difference between A and B for the circuit is respectively
4 Ω, 8 V
8 Ω, 4 V
2 Ω, 2 V
16 Ω, 8 V
Five equal resistances each of resistance R are connected as shown in the figure. A battery of V volts is connected between A and B. The current flowing in AFCEB will be
3VR
VR
V2R
2VR
For the network shown in the figure the value of the current i is
9V35
5V18
5V9
18V5
When a wire of uniform cross-section a, length l and resistance R is bent into a complete circle, the resistance between any two of diametrically opposite points will be :
R4
R8
4R
R2
In the circuit given E = 6.0 V, R1 = 100 ohms, R2 = R3 = 50 ohms, R4 = 75 ohms. The equivalent resistance of the circuit, in ohms, is
(1) 1875
(2) 26.31
(3) 118.75
(4) None of these
By using only two resistance coils-singly, in series, or in parallel one should be able to obtain resistances of 3, 4, 12, and 16 ohms. The separate resistances of the coil are :
3 and 4
4 and 12
12 and 16
16 and 3
In the adjoining circuit, the battery E1 has an e.m.f. of 12 volts and zero internal resistance while the battery E has an e.m.f. of 2 volts. If the galvanometer G reads zero, then the value of the resistance X in ohm is
10
100
500
200
The magnitude and direction of the current in the circuit shown will be
73A from a to b through e
73A from b to a through e
1A from b to a through e
1A from a to b through e
The e.m.f. of a cell is E volts and internal resistance is r ohm. The resistance in external circuit is also r ohm. The p.d. across the cell will be
E/2
2E
4E
E/4
Kirchhoff's first law i.e. Σi=0 at a junction is based on the law of conservation of :
Charge
Energy
Momentum
Angular momentum
The figure below shows currents in a part of electric circuit. The current i is
(1) 7 amp
(2) 3.7 amp
(3) 1.3 amp
(4) 1 amp
In the circuit shown, A and V are ideal ammeter and voltmeter respectively. Reading of the voltmeter will be
2 V
1 V
0.5 V
Zero
The terminal potential difference of a cell when short-circuited is (E = E.M.F. of the cell)
E
E/3
The potential difference in open circuit for a cell is 2.2 volts. When a 4-ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be :
1 ohm
0.2 ohm
2.5 ohm
0.4 ohm
A cell whose e.m.f. is 2 V and internal resistance is 0.1 Ω, is connected with a resistance of 3.9 Ω. The voltage across the cell terminal will be :
0.50 V
1.90 V
1.95 V
2.00 V
n identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is
nER+nr
nEnR+r
ER+nr
nER+r
A cell of internal resistance r is connected to an external resistance R. The current will be maximum in R, if
R = r
R < r
R > r
Two identical cells send the same current in 2 Ω resistance, whether connected in series or in parallel. The internal resistance of the cell should be
1 Ω
2 Ω
12Ω
2.5 Ω
The internal resistances of the two cells shown are 0.1 Ω and 0.3 Ω. If R = 0.2 Ω, the potential difference across the cell :
B will be zero
A will be zero
A and B will be 2V
A will be > 2V and B will be < 2V
The figure shows a network of currents. The magnitude of currents is shown here. The current i will be
3 A
13 A
23 A
– 3 A
A battery of e.m.f. E and internal resistance r is connected to a variable resistor R as shown here. Which one of the following is true?
Potential difference across the terminals of the battery is maximum when R = r.
Power delivered to the resistor is maximum when R = r.
Current in the circuit is maximum when R = r.
Current in the circuit is maximum when R >> r.
Consider the circuit given here with the following parameters E.M.F. of the cell = 12 V. Internal resistance of the cell = 2 Ω. Resistance R = 4 Ω. Which one of the following statements is true.
Rate of energy loss in the source is = 8 W
Rate of energy conversion in the source is 16 W
Power output in R is = 8 W
Potential drop across R is = 16 V
The current in the arm CD of the circuit will be
i1+i2
i2+i3
i1+i3
i1−i2+i3
Two non-ideal identical batteries are connected in parallel. Consider the following statements :
(i) The equivalent e.m.f. is smaller than either of the two e.m.f.s
(ii) The equivalent internal resistance is smaller than either of the two internal resistances
Both (i) and (ii) are correct
(i) is correct but (ii) is wrong
(ii) is correct but (i) is wrong
Both (i) and (ii) are wrong
Consider the circuit shown in the figure. The current I3 is equal to :
5 amp
3 amp
–3 amp
–5/6 amp
If VAB=4V in the given figure, then resistance X will be :
5 Ω
10 Ω
15 Ω
20 Ω
The number of dry cells, each of e.m.f. 1.5 volt and internal resistance 0.5 ohm that must be joined in series with a resistance of 20 ohms, so as to send a current of 0.6 amperes through the circuit is
2
8
12
For driving a current of 2 A for 6 minutes in a circuit, 1000 J of work is to be done. The e.m.f. of the source in the circuit is
(1) 38 V
(2) 1.68 V
(3) 2.04 V
(4) 3.10 V
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