Electric field at a point varies as r 0 for

A plane infinite sheet of charge

A line charge of infinite length

An electrostatic line of force in the xy plane is given by equation x 2 + y 2 = 1. A particle with unit positive charge, initially at rest at the point x = 1, y = 0 in the xy plane will -

The data given in the question is contradictory

Will move along the circular line of force

Physics - Electric Charges Fields - Quiz-3

Electric field at a point varies as r⁰ for

0%

An electric dipole
0%

A point charge
0%

A plane infinite sheet of charge
0%

A line charge of infinite length

Total electric flux coming out of a unit positive charge put in air is

0%

$ε_{0}$
0%

$ε_{0}^{- 1}$
0%

${(4 p ε_{0})}^{- 1}$
0%

$4 π ε_{0}$

A cube of side l is placed in a uniform field E, where $E = E \hat{i}$ . The net electric flux through the cube is

0%

Zero
0%

l²E
0%

4l²E
0%

6l²E

Eight dipoles of charges of magnitude e are placed inside a cube. The total electric flux coming out of the cube will be

0%

$\frac{8 e}{ε_{0}}$
0%

$\frac{16 e}{ε_{0}}$
0%

$\frac{e}{ε_{0}}$
0%

Zero

A charge q is placed at the centre of the open end of the cylindrical vessel. The flux of the electric field through the surface of the vessel is

0%

Zero
0%

$\frac{q}{ε_{0}}$
0%

$\frac{q}{2 ε_{0}}$
0%

$\frac{2 q}{ε_{0}}$

Electric charge is uniformly distributed along a long straight wire of radius 1mm. The charge per cm length of the wire is Q coulomb. Another cylindrical surface of radius 50 cm and length 1m symmetrically encloses the wire as shown in the figure. The total electric flux passing through the cylindrical surface is

0%

$\frac{Q}{ε_{0}}$
0%

$\frac{100 Q}{ε_{0}}$
0%

$\frac{10 Q}{(π ε_{0})}$
0%

$\frac{100 Q}{(π ε_{0})}$

The S.I. unit of electric flux is

0%

Weber
0%

Newton per coulomb
0%

Volt × metre
0%

Joule per coulomb

Shown below is a distribution of charges. The flux of electric field due to these charges through the surface S is

0%

$3 q / ε_{0}$
0%

$2 q / ε_{0}$
0%

$q / ε_{0}$
0%

Zero

Consider the charge configuration and spherical Gaussian surface as shown in the figure. While calculating the flux of the electric field over the spherical surface, the electric field will be due to:

0%

q₂ only
0%

Only the positive charges
0%

All the charges
0%

+q₁ and – q₁ only

An electric dipole is put in north-south direction in a sphere filled with water. Which statement is correct ?

0%

Electric flux is coming towards sphere
0%

Electric flux is coming out of sphere
0%

Electric flux entering into sphere and leaving the sphere are same
0%

Water does not permit electric flux to enter into sphere

The electric flux for Gaussian surface A that encloses the charged particles in free space is (given q₁ = –14 nC, q₂ = 78.85 nC, q₃ = – 56 nC)

0%

10³ Nm² C^–1
0%

10³ CN^-1 m^–2
0%

6.32 × 10³ Nm² C^–1
0%

6.32 × 10³ CN^-1 m^–2

Two equal negative charges of charge – q are fixed at the points (0, a) and (0, –a) on the Y-axis. A positive charge Q is released from rest at the point (2a, 0) on the X-axis. The charge Q will:

0%

execute simple harmonic motion about the origin.
0%

move to the origin and remain at rest.
0%

move to infinity.
0%

execute the oscillatory but not simple harmonic motion.

An electrostatic line of force in the xy plane is given by equation x² + y² = 1. A particle with unit positive charge, initially at rest at the point x = 1, y = 0 in the xy plane will -

0%

Not move at all
0%

Will move along straight line
0%

Will move along the circular line of force
0%

The data given in the question is contradictory

A positively charged ball hangs from a silk thread. We put a positive test charge q₀ at a point and measure F/q₀, then it can be predicted that the electric field strength E

0%

> F/q₀
0%

= F/q₀
0%

< F/q₀
0%

Cannot be estimated

A solid metallic sphere has a charge +3Q. Concentric with this sphere is a conducting spherical shell having charge –Q. The radius of the sphere is a and that of the spherical shell is b (b > a). What is the electric field at a distance R(a < R < b) from the centre

0%

$\frac{Q}{2 π ε_{0} R}$
0%

$\frac{3 Q}{2 π ε_{0} R}$
0%

$\frac{3 Q}{4 π ε_{0} R^{2}}$
0%

$\frac{4 Q}{4 π ε_{0} R^{2}}$

A point charge q is placed at a distance a/2 directly above the centre of a square of side a. The electric flux through the square is

0%

$\frac{q}{ε_{0}}$
0%

$\frac{q}{π ε_{0}}$
0%

$\frac{q}{4 ε_{0}}$
0%

$\frac{q}{6 ε_{0}}$

Two infinitely long parallel wires having linear charge densities λ₁ and λ₂ respectively are placed at a distance of R meters. The force per unit length on either wire will be $(K = \frac{1}{4 π ε_{0}})$

0%

$K \frac{2 λ_{1} λ_{2}}{R^{2}}$
0%

$K \frac{2 λ_{1} λ_{2}}{R}$
0%

$K \frac{λ_{1} λ_{2}}{R^{2}}$
0%

$K \frac{λ_{1} λ_{2}}{R}$

The charge on 500 cc of water due to protons will be:

0%

6.0 × 10²⁷ C
0%

2.67 × 10⁷ C
0%

6 × 10²³ C
0%

1.67 × 10²³ C

In the given figure two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that θ is so small that $\tan θ \approx \sin θ$ , then for equilibrium x is equal to

0%

${(\frac{q^{2} L}{2 π ε_{0} m g})}^{\frac{1}{3}}$
0%

${(\frac{q L^{2}}{2 π ε_{0} m g})}^{\frac{1}{3}}$
0%

${(\frac{q^{2} L^{2}}{4 π ε_{0} m g})}^{\frac{1}{3}}$
0%

${(\frac{q^{2} L}{4 π ε_{0} m g})}^{\frac{1}{3}}$

Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in

Two equal charges are separated by a distance d. A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force when

0%

$x = \frac{d}{\sqrt{2}}$
0%

$x = \frac{d}{2}$
0%

$x = \frac{d}{2 \sqrt{2}}$
0%

$x = \frac{d}{2 \sqrt{3}}$

An electric dipole is situated in an electric field of uniform intensity E whose dipole moment is p and moment of inertia is I. If the dipole is displaced slightly from the equilibrium position, then the angular frequency of its oscillations is?

0%

${(\frac{p E}{I})}^{1 / 2}$
0%

${(\frac{p E}{I})}^{3 / 2}$
0%

${(\frac{I}{p E})}^{1 / 2}$
0%

${(\frac{p}{I E})}^{1 / 2}$

An infinite number of electric charges each equal to 5 nano-coulomb (magnitude) are placed along x-axis at x = 1 cm, x = 2 cm, x = 4 cm, x = 8 cm ………. and so on. In the setup if the consecutive charges have opposite sign, then the electric field in Newton/Coulomb at x = 0 is $(\frac{1}{4 π ε_{0}} = 9 \times 10^{9} N - m^{2} / c^{2})$

0%

12 × 10⁴
0%

24 × 10⁴
0%

36 × 10⁴
0%

48 × 10⁴

Three charges –q₁, +q₂ and –q₃ are placed as shown in the figure. The x-component of the force on –q₁ is proportional to

0%

$\frac{q_{2}}{b^{2}} - \frac{q_{3}}{a^{2}} \sin θ$
0%

$\frac{q_{2}}{b^{2}} - \frac{q_{3}}{a^{2}} \cos θ$
0%

$\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}} \sin θ$
0%

$\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}} \cos θ$

Two-point charges +q and –q are held fixed at (–d, 0) and (d, 0) respectively of a (x, y) coordinate system. Then

0%

E at all points on the y-axis is along $\hat{i}$
0%

The electric field $\vec{E}$ at all points on the x-axis has the same direction
0%

Dipole moment is 2qd directed along $\hat{i}$
0%

Work has to be done in bringing a test charge from infinity to the origin

A point charge of 40 stat coulomb is placed 2 cm in front of an earthed metallic plane plate of large size. Then the force of attraction on the point charge is

0%

100 dynes
0%

160 dynes
0%

1600 dynes
0%

400 dynes

Which of the following graphs shows the variation of electric field E due to a hollow spherical conductor of radius R as a function of distance from the centre of the sphere

The electric field due to a uniformly charged solid sphere of radius R as a function of the distance from its centre is represented graphically by -

The electric field inside a spherical shell of uniform surface charge density is -

0%

Zero
0%

Constant, less than zero
0%

Directly proportional to the distance from the centre
0%

None of the above

The distance between charges 5 × 10^–11 C and –2.7 × 10^–11 C is 0.2 m. The distance at which a third charge should be placed in order that it will not experience any force along the line joining the two charges is

0%

0.44 m
0%

0.65 m
0%

0.556 m
0%

0.350 m

0:0:1

Practice Physics Quiz Questions and Answers

0:0:1

Practice Physics Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.