Two planets have the same density but different radii. The acceleration due to gravity would be:
same on both planets.
greater on the smaller planet.
greater on the larger planet.
dependent on the distance of the planet from the sun.
If the radius of the earth shrinks by 1.5% (mass remaining the same), then the value of the gravitational acceleration changes by:
2%
-2%
3%
-3%
If the density of a planet is double that of the earth and the radius is 1.5 times that of the earth, the acceleration due to gravity on the surface of the planet is:
34 times that on the surface of the earth.
3 times that on the surface of the earth.
43 times that on the surface of the earth.
6 times that on the surface of the earth.
The gravitational force on a body of mass 1.5 kg situated at a point is 45 N. The gravitational field intensity at that point is:
30 N/kg
67.5 N/kg
46.5 N/kg
43.5 N/kg
At what height above the surface of the earth, the value of "g" decreases by 2%?
[radius of the earth is 6400 km]
32 km
64 km
128 km
1600 km
During the motion of a man from the equator to the pole of the earth, its weight will (neglect the effect of change in the radius of the earth)
increase by 0.34%.
decrease by 0.34%.
increase by 0.52%.
decrease by 0.52%.
If R is the radius of earth and g is the acceleration due to gravity on the earth's surface, then mean density of the earth is:
4πG3gR
3πR4gG
3g4πRG
πRg12G
The value of g at the surface of the earth is 9.8 m/s2. Then the value of 'g' at a place 480 km above the surface of the earth will be nearly (radius of the earth is 6400 km):
9.8 m/s2
7.2 m/s2
8.5 m/s2
4.2 m/s2
If the change in the value of 'g' at a height 'h' above the surface of the earth is the same as at a depth x below it, then: (x and h being much smaller than the radius of the earth)
x=h
x=2h
x=h2
As we go from the equator to the poles, the value of 'g':
Remains the same
Decreases
Increases
First increase and then decrease
What should be the angular speed with which the earth has to rotate on its axis so that a person on the equator would weigh 35th as much as he weighs at present?
2g5R
2R5g
The acceleration due to gravity on a planet is 1.96 m/s2. If it is safe to jump from a height of 3 m on the earth, the corresponding height on the planet will be:
3 m
6 m
9 m
15 m
An object is taken to height 2R above the surface of the earth, the increase in potential energy is: [R is the radius of the earth]
mgR2
mgR3
2mgR3
2 mgR
The change in potential energy when a body of mass m is raised to height nR from the earth's surface is: (R is the radius of the earth)
mgR nn-1
nmgR
mgRnn+1
mgRn2n2+1
If an object is projected vertically upward with a speed equal to half the escape velocity on earth, then the maximum height attained by it is: [R is radius of earth]
R
R2
2R
R3
If a satellite of mass 400 kg revolves around the earth in an orbit with a speed of 200 m/s, then its potential energy is:
-1.2 MJ
-8.0 MJ
-16 MJ
-2.4 MJ
The escape velocity of a body from the earth is about 11.2 km/s. Assuming the mass and radius of the earth to be about 81 and 4 times the mass and radius of the moon respectively, the escape velocity in km/s from the surface of the moon will be:
0.54
2.48
11
49.5
If M is the mass of a planet and R is its radius, then in order to become black hole:
[c is speed of light]
GMR≤c
GM2R≥c
2GMR≥c
2GMR≤c
The atmosphere on a planet is possible only if: [where vrms is root mean square speed of gas molecules on planet and ve is escape speed on its surface]
vrms=ve
vrms>ve
vrms≤ve
vrms<ve
When the speed of a satellite is increased by x percentage, it will escape from its orbit where the value of x is:
11.2%
41.4%
27.5%
34.4%
In an orbit if the time of revolution of a satellite is T, then P.E. is proportional to:
T1/3
T3
T-2/3
T-4/3
A small satellite is revolving near earth's surface. Its orbital velocity will be nearly:
8 km/s
11.2 km/s
4 km/s
6 km/s
If the potential energy of a satellite is -2 MJ, then the binding energy of the satellite is:
1 MJ
2 MJ
8 MJ
4 MJ
The time period of a polar satellite is about:
24 hr
100 min
84.6 min
6 hr
The mean radius of the earth is R and its angular speed on its axis is ω. What will be the radius of orbit of a geostationary satellite?
Rgω21/3
R2gω21/3
R2gω1/3
R2ω2g1/3
A satellite of the earth is revolving in a circular orbit with a uniform speed v. If the gravitational force suddenly disappears, the satellite will:
continue to move with velocity v along the original orbit.
move with a velocity v tangentially to the orbit.
fall down with increasing velocity.
ultimately come to rest somewhere on the original orbit.
The relay satellite transmits the television signals continuously from one part of the world to another because its:
period is greater than the period of rotation of the earth.
period is less than the period of rotation of the earth.
period has no relation with the period of the earth about its axis.
period is equal to the period of rotation of the earth about its axis.
If the height of a satellite from the surface of the earth is increased, then its:
potential energy will increase.
kinetic energy will decrease.
total energy will increase.
All of these
Which of the following diagrams most closely shows the variation in kinetic energy of the Earth as it moves once around the Sun in its elliptical orbit ?
Starting from the centre of the Earth having radius R, the variation of g (acceleration due to gravity) is shown by:
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