The acceleration of a body due to the attraction of the earth (radius R) at a distance 2R
from the surface of the earth is (g = acceleration due to gravity at the surface of the
earth)
g9
g3
g4
g
If V, R, and g denote respectively the escape velocity from the surface of the earth, the
radius of the earth, and acceleration due to gravity, then the correct equation is:
V=gR
V=43gR3
V = Rg
V=2gR
The depth at which the effective value of acceleration due to gravity is g4, is:
R
3R4
R2
R4
The value of ‘g’ at a particular point is 9.8 m/s2. Suppose the earth suddenly shrinks uniformly to half its present size without losing any mass then value of ‘g’ at the same point will now become:(assuming that the distance of the point from the centre of the earth does not shrink)
4.9m/sec2
3.1m/sec2
9.8m/sec2
19.6m/sec2
If both the mass and the radius of the earth is decreased by 1%, then the value of the acceleration due to gravity will:
decrease by 1%.
increase by 1%.
increase by 2%.
remain unchanged.
The earth (mass = 6×1024kg ) revolves round the sun with angular velocity
2×10‐7rad/s in a circular orbit of radius 1.5×108km . The force exerted by the sun on
the earth in Newtons, is
18×1025
Zero
27×1039
36×1021
The value of g on the earth's surface is 980 cm/sec2 . Its value at a height of 64 km from
the earth's surface is
(Radius of the earth R = 6400 kilometers)
960.40 cm/sec2
984.90 cm/sec2
982.45 cm/sec2
980.45 cm/sec2
If the earth suddenly shrinks (without changing mass) to half of its present radius, the acceleration due to gravity will be:
g/2
4g
g/4
2g
The gravitational force between two point masses m1 and m2 at separation r is given by F=km1m2r2 The constant k
Depends on system of units only
Depends on medium between masses only
Depends on both 1 and 2
Is independent of both 1 and 2
The density of a newly discovered planet is twice that of earth. The acceleration due to
gravity at the surface of the planet is equal to that at the surface of the earth. If the
radius of the earth is R, the radius of the planet would be
2R
4R
14R
12R
If R is the radius of the earth and g the acceleration due to gravity on the earth's surface,
the mean density of the earth is:
4πG/3gR
3πR/4gG
3g/4πRG
πRG/12G
A planet has twice the radius but the mean density is 14th as compared to earth. What is the ratio of escape velocity from earth to that from the planet ?
3:1
1:2
1:1
2:1
A body weighs 500 N on the surface of the earth. How much would it weigh halfway
below the surface of the earth?
125 N
250 N
500 N
1000 N
Who among the following gave first the experimental value of G?
Cavendish
Copernicus
Brook Taylor
None of these
3 particles each of mass m are kept at vertices of an equilateral triangle of side L. The
gravitational field at centre due to these particles is
zero
3GML2
9GML2
123GML2
The weight of an object in the coal mine, sea level, at the top of the mountain are W1,
W2 and W3 respectively, then
W1≤W2≥W3
W1=W2=W3
W1≤W2≤W3
W1≥W2≥W3
The value of escape velocity on a certain planet is 2 km/s. Then the value of orbital speed
for a satellite orbiting close to its surface is:
12km/s
1km/s
2 km/s
22 km/s
Four particles each of mass M, are located at the vertices of a square with side L. The
gravitational potential due to this at the centre of the square is
-32GML
-64GML2
32GML
The mass of the moon is 7.34×1022kg and the radius is 1.74×106m. The value of
gravitation field will be
1.45 N/kg
1.55 N/kg
1.75 N/kg
1.62 N/kg
The centripetal force acting on a satellite orbiting round the earth and the gravitational
force of earth acting on the satellite both equal F. The net force on the satellite is
F
F2
2 F
Reason of weightlessness in a satellite is:
Zero gravity
Centre of mass
Zero reaction force by satellite surface
None
Mass M is divided into two parts xM and 1-xM . For a given separation, the value of x
for which the gravitational attraction between the two pieces becomes maximum is
12
35
1
2
If earth is supposed to be a sphere of radius R, if g30° is value of acceleration due to gravity at latitude of 30o and g at the pole, the value of g-g30ο is
14 ω2R
34ω2R
ω2R
12ω2R
If M the mass of the earth and R its radius, the ratio of the gravitational acceleration and
the gravitational constant is
R2M
MR2
MR
Two sphere of mass m and M are situated in air and the gravitational force between them
is F. The space around the masses is now filled with a liquid of specific gravity 3. The
gravitational force will now be
F3
F9
3 F
Earth binds the atmosphere because of:
Gravity
Oxygen between earth and atmosphere
Both 1 and 2
4 None of these
The mass of the earth is 81 times that of the moon and the radius of the earth is 3.5
times that of the moon. The ratio of the acceleration due to gravity at the surface of the
moon to that at the surface of the earth is
0.15
0.0
6
Spot the wrong statement :
The acceleration due to gravity ‘g’ decreases if
We go down from the surface of the earth towards its centre
We go up from the surface of the earth
We go from the equator towards the poles on the surface of the earth
The rotational velocity of the earth is increased
Two identical solid copper spheres of radius R were placed in contact with each other. The gravitational attraction between them is proportional to:
R5
Which of the following statements is true?
g is less at the earth's surface than at a height above it or a depth below it
g is the same at all places on the surface of the earth
g has its maximum value at the equator
g is greater at the poles than at the equator
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