The potential energy of a molecule on the surface of liquid compared to one inside the liquid is  -

Two droplets merge with each other and forms a large droplet. In this process

Work done in splitting a drop of water of 1 mm radius into ${10}^6$ droplets is (Surface tension of water $=72\times {10}^{-3} \mathrm{J}/{\mathrm{m}}^2$)

The amount of work done in blowing a soap bubble such that its diameter increases from d to D is (T= surface tension of the solution)

A spherical drop of oil of radius 1 cm is broken into 1000 droplets of equal radii. If the surface tension of oil is 50 dynes/cm, the work done is 

If the surface tension of a liquid is T, the gain in surface energy for an increase in liquid surface by A is

The surface tension of a liquid at its boiling point

The surface tension of liquid is 0.5 N/m. If a film is held on a ring of area 0.02 ${\mathrm{m}}^2$, its surface energy is

(a) $5\times {10}^{-2} \mathrm{joule}$                         (b) $2\times {10}^{-2} \mathrm{joule}$

(c) $4\times {10}^{-4} \mathrm{joule}$                         (d) $0.8\times {10}^{-1} \mathrm{joule}$

A liquid drop of diameter D breaks upto into 27 small drops of equal size. If the surface tension of the liquid is $\mathrm{\sigma }$, then change in surface energy is 

(a) ${\mathrm{\pi D}}^2\mathrm{\sigma }$                          (b) $2{\mathrm{\pi D}}^2\mathrm{\sigma }$

(c) $3{\mathrm{\pi D}}^2\mathrm{\sigma }$                         (d) $4{\mathrm{\pi D}}^2\mathrm{\sigma }$

One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is 

A big drop of radius R is formed by 1000 small droplets of water, then the radius of small drop is

A film of water is formed between two straight parallel wires of length 10cm each separated by 0.5 cm. If their separation is increased by 1 mm while still maintaining their parallelism, how much work will have to be done (Surface tension of water =$7.2\times {10}^{-2} \mathrm{N}/\mathrm{m}$)

A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. (Surface tension of mercury is $0.465 \mathrm{J}/{\mathrm{m}}^2$) 

If two soap bubbles of equal radii r coalesce then the radius of curvature of interface between two bubbles will be

The angle of contact between glass and mercury is

A mercury drop does not spread on a glass plate because the angle of contact between glass and mercury is

The liquid meniscus in the capillary tube will be convex if the angle of contact is

The value of contact angle for kerosene with a solid surface.

Nature of meniscus for liquid of $0^0$ angle of contact

A liquid wets a solid completely. The meniscus of the liquid in a sufficiently long tube is 

For which of the two pairs, the angle of contact is same

If the surface of a liquid is plane, then the angle of contact of the liquid with the walls of the container is -

If two soap bubbles of different radii are in communication with each other

The surface tension of the soap solution is $25\times {10}^{-3} {\mathrm{Nm}}^{-1}$ . The excess pressure inside a soap bubble of diameter 1 cm is 

When two soap bubbles of radius ${\mathrm{r}}_1$ and ${\mathrm{r}}_2$ (${\mathrm{r}}_2$>${\mathrm{r}}_1$) coalesce, the radius of curvature of the common surface is

A long cylindrical glass vessel has a small hole of radius 'r' at its bottom. The depth to which the vessel can be lowered vertically in the deep water bath (surface tension T) without any water entering inside is

The excess of pressure inside a soap bubble than that of the outer pressure is

The pressure of air in a soap bubble of 0.7cm diameter is 8 mm of water above the pressure outside. The surface tension of the soap solution is

The pressure inside two soap bubbles are 1.01 and 1.02 atmospheres. The ratio between their volumes is

The radii of two soap bubbles are ${\mathrm{r}}_1$ and ${\mathrm{r}}_2$ . In isothermal conditions, two meet together in a vacuum. Then the radius of the resultant bubble is given by