Physics - Motion Plane - Quiz-3

A stone is just released from the window of a train moving along a horizontal straight track. The stone will hit the ground following

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Straight path
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Circular path
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Parabolic path
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Hyperbolic path

An aeroplane is flying at a constant horizontal velocity of 600 km/hr at an elevation of 6 km towards a point directly above the target on the earth's surface. At an appropriate time, the pilot releases a ball so that it strikes the target at the earth. The ball will appear to be falling

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On a parabolic path as seen by pilot in the plane
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Vertically along a straight path as seen by an observer on the ground near the target
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On a parabolic path as seen by an observer on the ground near the target
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On a zig-zag path as seen by pilot in the plane

A bomb is dropped from an aeroplane moving horizontally at constant speed. When air resistance is taken into consideration, the bomb

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Falls to earth exactly below the aeroplane
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Fall to earth behind the aeroplane
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Falls to earth ahead of the aeroplane
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Flies with the aeroplane

An aeroplane is flying horizontally with a velocity u = 600 km/h at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is:

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1200 m
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0.33 km
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3.33 km
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33 km

An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket while flying at a height of 396.9 m. The time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/sec²)

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3 sec and 2000 m
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5 sec and 500 m
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8 sec and 1500 m
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9 sec and 1800 m

A particle (A) is dropped from a height and another particle (B) is thrown in the horizontal direction with a speed of 5 m/sec from the same height. The correct statement is:

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Both particles will reach at ground simultaneously
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Both particles will reach at ground with same speed
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Particle (A) will reach at ground first with respect to particle (B)
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Particle (B) will reach at ground first with respect to particle (A)

A bomber plane moves horizontally with a speed of 500 m/s and a bomb is released from it. The bomb strikes the ground in 10 sec. Angle at which it strikes the ground will be (g = 10 m/s²)

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$\tan^{- 1} (\frac{1}{5})$
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$\tan (\frac{1}{5})$
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tan^–1(1)
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tan^–1(5)

A projectile fired with initial velocity u at some angle θ has a range R. If the initial velocity be doubled at the same angle of projection, then the range will be

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2 R
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R/2
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R
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4 R

If the initial velocity of a projectile be doubled, keeping the angle of projection same, the maximum height reached by it will

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Remain the same
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Be doubled
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Be quadrupled
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Be halved

In the motion of a projectile freely under gravity, its

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Total energy is conserved
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Momentum is conserved
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Energy and momentum both are conserved
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None is conserved

The range of a projectile for a given initial velocity is maximum when the angle of projection is 45°. The range will be minimum, if the angle of projection is

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90°
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180°
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60°
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75°

A ball is thrown upwards and it returns to the ground describing a parabolic path. Which of the following remains constant?

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Kinetic energy of the ball
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Speed of the ball
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Horizontal component of velocity
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Vertical component of velocity

At the top of the trajectory of a projectile, the directions of its velocity and acceleration are

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Perpendicular to each other
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Parallel to each other
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Inclined to each other at an angle of 45°
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Antiparallel to each other

An object is thrown along a direction inclined at an angle of 45° with the horizontal direction. The horizontal range of the particle is equal to

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Vertical height
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Twice the vertical height
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Thrice the vertical height
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Four times the vertical height

The height y and the distance x along the vertical plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8 t - 5 t^{2})$ meter and x = 6t meter, where t is in second. The velocity with which the projectile is projected is

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8 m/sec
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6 m/sec
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10 m/sec
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Not obtainable from the data

The range of a particle when launched at an angle of 15° with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of 45° to the horizontal

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(1) 5 km
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(2) 3.0 km
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(3) 6.0 km
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(4) 0.75 km

A projectile thrown with a speed v at an angle θ has a range R on the surface of earth. For same v and θ, its range on the surface of moon will be (acceleration due to gravity on moon= $\frac{g}{6}$ ):

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R/6
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6 R
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R/36
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36 R

A ball is projected with kinetic energy E at an angle of 45° to the horizontal. At the highest point during its flight, its kinetic energy will be

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Zero
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$\frac{E}{2}$
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$\frac{E}{\sqrt{2}}$
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E

At the top of the trajectory of a projectile, the magnitude of the acceleration is

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Maximum
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Minimum
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Zero
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g

A body is projected at such an angle that the horizontal range is three times the greatest height. The angle of projection is

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$25^{o} 8^{'}$
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$33^{o} 7^{'}$
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$42^{o} 8^{'}$
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$53^{o} 8^{'}$

A ball is falling freely strikes to ground with velocity
60 m/s. Height fallen in last one second before
hitting the ground is

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55 m
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70 m
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60 m
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80 m

If a body A of mass M is thrown with a velocity v at an angle of 30° to the horizontal and another body B of the same mass is thrown with the same speed at an angle of 60° to the horizontal. The ratio of horizontal range of A to B will be

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1 : 3
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1 : 1
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$1 : \sqrt{3}$
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$\sqrt{3} : 1$

Four bodies P, Q, R and S are projected with equal velocities having angles of projection 15^o, 30^o, 45^o and 60^o with the horizontal respectively. The body having the shortest range is

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P
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Q
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R
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S

A stone projected with a velocity u at an angle θ with the horizontal reaches maximum height H₁. When it is projected with velocity u at an angle $(\frac{π}{2} - θ)$ with the horizontal, it reaches maximum height H₂. The relation between the horizontal range R of the projectile, H₁ and H₂is

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$R = 4 \sqrt{H_{1} H_{2}}$
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R = 4(H₁ – H₂)
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R = 4(H₁ + H₂)
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$R = \frac{{H_{1}}^{2}}{{H_{2}}^{2}}$

Which of the following sets of factors will affect the horizontal distance covered by an athlete in a long–jump event

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Speed before he jumps and his weight
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The direction in which he leaps and the initial speed
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The force with which he pushes the ground and his speed
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None of these

In a projectile motion, velocity at maximum height is

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$\frac{u \cos θ}{2}$
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$u \cos θ$
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$\frac{u \sin θ}{2}$
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None of these

The equation of motion of a projectile is given by x = 36 t metre and 2y = 96 t – 9.8 t² metre. The angle of projection is:

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$\sin^{- 1} (\frac{4}{5})$
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$\sin^{- 1} (\frac{3}{5})$
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$\sin^{- 1} (\frac{4}{3})$
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$\sin^{- 1} (\frac{3}{4})$

For a given velocity, a projectile has the same range of R for two angles of projection. If t₁ and t₂ are the times of flight in the two cases then:

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$t_{1} t_{2} \propto R^{2}$
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$t_{1} t_{2} \propto R$
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$t_{1} t_{2} \propto \frac{1}{R}$
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$t_{1} t_{2} \propto \frac{1}{R^{2}}$

A body of mass m is thrown upwards at an angle θ with the horizontal with velocity v. While rising up the velocity of the mass after t seconds will be

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$\sqrt{{(v \cos θ)}^{2} + {(v \sin θ)}^{2}}$
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$\sqrt{{(v \cos θ - v \sin θ)}^{2} - g t}$
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$\sqrt{v^{2} + g^{2} t^{2} - (2 v \sin θ) g t}$
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$\sqrt{v^{2} + g^{2} t^{2} - (2 v \cos θ) g t}$

A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same effort, he throws the ball vertically upwards. The maximum height attained by the ball is

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100 m
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80 m
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60 m
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50 m

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Practice Physics Quiz Questions and Answers

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Practice Physics Quiz Questions and Answers

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