Physics - Motion Straight Line - Quiz-3

A particle starts from rest, accelerates at 2 m/s² for 10s and then goes for constant speed for 30s and then decelerates at 4 m/s² till it stops. What is the distance travelled by it?

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750 m
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800 m
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700 m
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850 m

The engine of a motorcycle can produce a maximum acceleration 5 m/s². Its brakes can produce a maximum retardation 10 m/s². What is the minimum time in which it can cover a distance of 1.5 km?

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30 sec
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15 sec
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10 sec
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5 sec

A car, moving with a speed of 50 km/hr, can be stopped by brakes after at least 6m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is

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6m
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12m
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18m
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24m

A student is standing at a distance of 50 metres from the bus. As soon as the bus begins its motion with an acceleration of 1 ms^–2, the student starts running towards the bus with a uniform velocity u. Assuming the motion to be along a straight road, the minimum value of u, so that the student is able to catch the bus is:

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5 ms^–1

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8 ms^–1

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10 ms^–1

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12 ms^–1

A body A moves with a uniform acceleration a and zero initial velocity. Another body B, starts from the same point moves in the same direction with a constant velocity v. The two bodies meet after a time t. The value of t is

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$\frac{2 v}{a}$

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$\frac{v}{a}$

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$\frac{v}{2 a}$

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$\sqrt{\frac{v}{2 a}}$

A particle moves along X-axis in such a way that its coordinate X varies with time t according to the equation $x = (2 - 5 t + 6 t^{2}) m$ . The initial velocity of the particle is

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–5 m/s

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6 m/s

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–3 m/s

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3 m/s

A car starts from rest and moves with uniform acceleration 'a' on a straight road from time t = 0 to t = T. After that, a constant deceleration brings it to rest. In this process the average speed of the car is:

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$\frac{a T}{4}$

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$\frac{3 a T}{2}$

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$\frac{a T}{2}$

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aT

An object accelerates from rest to a velocity of 27.5 m/s in 10 sec . Then find the distance covered by the object in the next 10 sec:

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550 m

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137.5 m

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412.5 m

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275 m

If the velocity of a particle is given by $v = {(180 - 16 x)}^{1 / 2}$ m/s, then its acceleration will be

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Zero

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8 m/s²

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– 8 m/s²

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4 m/s²

The displacement of a particle is proportional to the cube of time elapsed. How does the acceleration of the particle depends on time obtained

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$a \propto t^{2}$

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$a \propto t^{4}$

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$a \propto t^{3}$

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$a \propto t$

Starting from rest, acceleration of a particle is $a = 2 (t - 1) .$ The velocity of the particle at $t = 5 s$ is:

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15 m/sec

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25 m/sec

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5 m/sec

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None of these

Speed of two identical cars are u and 4u at a specific instant. The ratio of the respective distances in which the two cars are stopped from that instant is:

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1 : 1

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1 : 4

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1 : 8

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1 : 16

A body is moving with uniform acceleration describes 40 m in the first 5 sec and 65 m in the next 5 sec. Its initial velocity will be:

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4 m/s

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2.5 m/s

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5.5 m/s

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11 m/s

The displacement x of a particle varies with time $t, x = a e^{- α t} + b e^{β t}$ , where $a, b, α and β$ are positive constants. The velocity of the particle will

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Go on decreasing with time

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Be independent of $α$ and $β$

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Drop to zero when $α$ = $β$

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Go on increasing with time

A car, starting from rest, accelerates at the rate f through a distance S, then continues at a constant speed for time t and then decelerates at the rate $\frac{f}{2}$ to come to rest. If the total distance traversed is 15 S, then,

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$S = \frac{1}{2} f t^{2}$

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$S = \frac{1}{4} f t^{2}$

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$S = \frac{1}{72} f t^{2}$

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$S = \frac{1}{6} f t^{2}$

A man is 45 m behind the bus when the bus starts accelerating from rest with acceleration of 2.5 m/s². With what minimum velocity should the man start running to catch the bus?

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12 m/s

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14 m/s

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15 m/s

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16 m/s

A particle moves along the x-axis as $x = 4 (t - 2) + a {(t - 2)}^{2}$ . Which of the following is true?

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The initial velocity of the particle is 4

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The acceleration of the particle is 2a

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The particle is at the origin at t = 0

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None of these

A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5 sec is

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9/25

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3/5

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25/9

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1/25

Two trains, each 50 m long, are travelling in the opposite direction with velocities 10 m/s and 15 m/s. The time of crossing is:

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10 sec

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4 sec

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$2 \sqrt{3} \sec$

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$4 \sqrt{3} \sec$

A 120 m long train is moving in a direction with speed 20 m/s. A train B moving with 30 m/s in the opposite direction and 130 m long crosses the first train in a time

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4 s

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36 s

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38 s

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5 s

A 210-meter long train is moving due north at a speed of 25 m/s. A small bird is flying due South a little above the train with a speed of 5m/s. The time taken by the bird to cross the train is

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6 s

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7 s

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9 s

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10 s

A police jeep is chasing with a velocity of 45 km/h a thief in another jeep moving with a velocity of 153 km/h. Police fire a bullet with a muzzle velocity of 180 m/s. The velocity with which it will strike the car of the thief is

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150 m/s

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27 m/s

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450 m/s

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250 m/s

A train of 150 meter length is going towards north direction at a speed of 10 m/sec. A parrot flies at the speed of 5 m/sec towards south direction parallel to the railway track. The time taken by the parrot to cross the train is

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12 sec

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8 sec

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15 sec

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10 sec

The distance between two particles is decreasing at the rate of 6 m/sec when they are moving in the opposite directions. If these particles travel with the same initial speeds and in the same direction, then the separation increases at the rate of 4 m/sec. It can be concluded that particles' speeds could be

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5 m/sec, 1 m/sec

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4 m/sec, 1 m/sec

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4 m/sec, 2 m/sec

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5 m/sec, 2 m/sec

An express train is moving with a velocity v₁. Its driver finds another train is moving on the same track in the same direction with velocity v₂. To escape collision, driver applies a retardation 'a' on the train. The minimum time of escaping collision will be

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$t = \frac{v_{1} - v_{2}}{a}$

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$t_{1} = \frac{v_{1}^{2} - v_{2}^{2}}{2}$

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None

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Both

A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The displacement of the stone from the point of release after 10 sec is

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490 m

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510 m

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610 m

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725 m

A ball is dropped on the floor from a height of 10 m. It rebounds to a height of 2.5 m. If the ball is in contact with the floor for 0.01 sec, the average acceleration during contact is

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2100 m/sec² downwards

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2100 m/sec² upwards

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1400 m/sec²

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700 m/sec²

A body A is projected upwards with a velocity of 98 m/s. The second body B is projected upwards with the same initial velocity but after 4 sec. Both the bodies will meet after

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6 sec

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8 sec

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10 sec

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12 sec

Two bodies of different masses m_a and m_b are dropped from two different heights a and b. The ratio of the time taken by the two to cover these distances are

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a : b

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b : a

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$\sqrt{a} : \sqrt{b}$

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$a^{2} : b^{2}$

A body falls freely from rest. It covers as much distance in the last second of its motion as covered in the first three seconds. The body has fallen for a time of

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3 s

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5 s

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7 s

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9 s

0:0:1

0:0:1

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