If a simple pendulum is brought deep inside a mine from earth surface, its time period of oscillation will
Increase
Decrease
Remain the same
Any of the above depending on the length of the pendulum
The amplitude of a simple harmonic oscillator is A and speed at the mean position is v0. The speed of the oscillator at the position x = A√3 is:
2v0√3
√2v03
23v0
√2v0√3
The initial phase of the particle executing SHM with y = 4 sin ωt + 3 cos ωt is
53°
37°
90°
45°
A spring-block system is brought from the earth's surface to deep inside mine. Its period of oscillation will:
May increase or decrease depending on the mass of the block
A particle executes S.H.M with amplitude A. If the time taken by the particle to travel from -A to A/2 is 4 seconds, its time period is
4s
8s
12 s
18 s
Two simple harmonic motions are represented by y1 = 6 sin(2πt + π3) and y2 = 3(sin 2πt + cos 2πt). The ratio of their amplitudes is
√2
23
12
2√2
A disc executes S.H.M. about the axis XX' in the plane of the disc as shown in the figure. Its time period of oscillation is:
π√6Rg
2π√Rg
2π√2Rg
π√3R2g
A spring-block system shown in figure oscillates with a certain time period. If charge q is given to the block and a uniform field E is switched on, then its time period of oscillation is
Increases
Decreases
May increase or decrease
Remains the same
The period of oscillation of the spring block system shown in the figure is: (assume pulleys and spring to be ideal)
2π√m3k
2π√4m3k
2π√3m4k
2π√mk
The graph between velocity and acceleration of a particle executing S.H.M. can be
A circle
An ellipse
A straight line
Both (1) & (2)
The potential energy of a particle of mass m executing SHM is given by U = A(1 - cos2x), where x is the instantaneous displacement of the particle. The time period of oscillation is
π√mA
2π√mA
π√m2A
2π√m2A
A uniform rod of length l is suspended at l4 from one end and made to undergo small oscillations. The time period of oscillation is:
2π√7l12g
2π√3l7g
2π√7l3g
2π√4l5g
A simple pendulum with a metallic bob has a time period T. The bob is now immersed in a nonviscous liquid and the time period is found to be √5T. The ratio of the density of the metal to that of liquid is
1/4
4/3
5/4
7/3
A particle executes S.H.M. with time period T. The time period of oscillation of total energy is:
T
2T
T2
Infinite
A particle is executing linear simple harmonic motion with an amplitude a and an angular frequency ω. Its average speed for its motion from extreme to mean position will be
The time period of oscillation of a simple pendulum of length equal to half of the diameter of the earth is about
60 minute
84.6 minute
42.3 minute
24 hour
The time period of the given spring-mass system is
2π√m2k
2π√2m√3k
π√mk
The equation of simple harmonic motion is given by X = (4 cm)sin(6.28 t + 5π3), then maximum velocity of the particle in simple harmonic motion is:
25.12 m/s
25.12 cm/s
12.56 m/s
12.56 cm/s
A spring pendulum is on the rotating table. The initial angular velocity of the table is ω0 and the time period of the pendulum is T0. Now the angular velocity of the table becomes 2ω0, then the new time period will be:
2T0
T0√2
If vertical spring-mass system dipped in a non-viscous liquid, then:
Only mean position is changed
Only time period is changed
Time period and mean position both are changed
Time period and mean position both remain the same
The displacement x of a particle varies with time t as x = A sin(2πTt + π3). Time taken by particle to reach from x = A2 to x = -A2 will be
T3
T12
T6
Force on a particle F varies with time t as shown in the given graph. The displacement x vs time t graph corresponding to the force-time graph will be
The time period of a simple pendulum in a stationary trolley is T1. If the trolley is moving with a constant speed, then time period is T2, then
T1 > T2
T1 < T2
T1 = T2
T2 = ∞
A particle executes S.H.M with a frequency of 20 Hz. The frequency with which its potential energy oscillates is:
5 Hz
20 Hz
10 Hz
40 Hz
Two simple pendulums of lengths 1.44 m and 1 m start S.H.M. together in the same phase. They will be in the same phase again after
6 vibrations of the longer pendulum
6 vibrations of the smaller pendulum
5 vibrations of the smaller pendulum
4 vibrations of the longer pendulum
A particle is moving along the x-axis. The speed of particle v varies with position x as v2144 + x29 = 1. The time period of S.H.M is
π unit
3π2 unit
π2 unit
π4 unit
A block of mass m is attached to a massless spring having a spring constant k. The other end of the spring is fixed from the wall of a trolley, as shown in the figure. Spring is initially unstretched and the trolley starts moving toward the direction shown. Its velocity-time graph is also shown.
The energy of oscillation, as seen from the trolley is:
32m26k
9m28k
9m232k
8m29k
A body of mass 20 g is executing S.H.M with amplitude 5 cm. When it passes through equilibrium position its speed is 20 cm/s. Find the distance from equilibrium when its speed becomes 10 cm/s.
5√34 cm
5√32 cm
25√72 cm
5√3 cm
For a simple harmonic oscillator, a velocity-time diagram is shown. The angular frequency of oscillation is:
242 rad/s
25π4 rad/s
25 rad/s
25π rad/s
In an S.H.M, when the displacement is one-fourth of the amplitude, the ratio of total energy to the potential energy is
16: 1
1: 16
1: 8
8: 1
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