One unified atomic mass represents a mass of magnitude

A far off planet is estimated to be at a distance D from the earth. lf its diametrically opposite extremes subtend an angle at $\theta$ an observation situated on the earth, the approximate diameter of the planet is 

lf the average life of a person is taken as 100 s. the age of the universe on this scale is of the order 

The order of the magnitude of speed of light in Sl units is 

Two resistors ${\mathrm{R}}_1 = (3.0 \pm 0.3) \mathrm{\Omega } \mathrm{and} {\mathrm{R}}_{2 }= (5.0 \pm 0.1) \mathrm{\Omega }$ are connected in parallel. The equivalent resistance is :

$\begin{array}{}\end{array}\begin{array}{rl}1. & 1.9\pm 0.07 \mathrm{\Omega }\\ 2. & 1.9\pm 0.1 \mathrm{\Omega }\\ 3. & 1.9\pm 0.2 \mathrm{\Omega }\\ 4. & 1.9\pm 0.3 \mathrm{\Omega }\end{array}$

Consider a dimensionally consistent equation given as :

$\mathrm{P} = \mathrm{ab} + \frac{\mathrm{cd}}{\mathrm{e}+\mathrm{f}}$

Select the correct alternative.

$\begin{array}{rl}1. & \left[ab\right]=\left[cd\right]\\ 2. & \left[a\right]=\left[\frac{cd}{be}\right]\\ 3. & \left[Pab\right]=\left[\frac{cd}{e+f}\right]\\ 4. & \left[b\right]=\left[P\right][e+f]\end{array}$

The main scale of a vernier calliper has n divisions/cm. n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count of the vernier callipers is:

A particle of mass 'm' is executing oscillations about the origin on the x-axis. Its potential energy is U(x) = k|x| where k is a positive constant. If the amplitude of oscillation is a, then its time period T is directly proportional to:

The dimension of ${\int }_u^{v}mvdv$ is

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is:

Taking into account the significant figures, what is the value of (9.99m - 0.0099m)?

The energy required to  break one bond in DNA is 10${}^{-20}$ J. This value in eV is nearly : 

Dimensions of stress are:

The dimensions of pressure are the same as that of

Time intervals measured by a clock give the following readings: 1.25 s, 1.24 s, 1.27 s, 1.21 s, and 1.28 s. What is the percentage relative error of the observations?

The most precise reading of the mass of an object, among the following is 

The most accurate reading of the length of  6.28 cm long fibre is 

Which of the following is the most precise measurement?

The values of a number of quantities are used in a mathematical formula. The quantity that should be most precise and accurate in measurement is the one 

The thickness of a pencil measured by using a screw gauge (least count 0.001 cm) comes out to be 0.802 cm. The percentage error in the measurement is:

The percentage error in the measurement of the voltage V is 3% and in the measurement of the current is 2%. The percentage error in the measurement of the resistance is 

The relative error in the measurement of the side of cube is 0.027. The relative error in the measurement of its volume is 

Zero error in an instrument introduces 

A calorie is a unit of heat (energy in transit) and it equals about 4.2 J where$1 J=1 kg m^2{s}^{-2}$.  Suppose we employ a system of units in which the unit of mass equals $\alpha kg$, the unit of length equals β m, the unit of time is γ s. Then the magnitude of calorie in terms of new units is:

$$\begin{gathered} 1. 4.2{\alpha }^{-2}{\beta }^{-2}{\gamma }^2 \\ 2. 4.2{\alpha }^2{\beta }^{-2}{\gamma }^2 \\ 3. 4.2{\alpha }^{-1}{\beta }^{-2}{\gamma }^2 \\ 4. 4.2{\alpha }^{-1}{\beta }^2{\gamma }^{-2} \end{gathered}$$

The number of significant figure in 0.0006032 $m^2$ is:

$$\begin{gathered} \left(1\right) 4 \\ \left(2\right) 5 \\ \left(3\right) 7 \\ \left(4\right) 3 \end{gathered}$$

A physical quantity P is related to four observables a, b, c, and d as follows :

$\mathrm{P}=\frac{{\mathrm{a}}^3{\mathrm{b}}^2}{\sqrt{\mathrm{c}}\mathrm{d}}$

The percentage errors of measurement in a, b, c, and d are 1%, 3%, 4% and 2%, respectively. Then the percentage error in the quantity P is:

$$\begin{gathered} \left(1\right) 12\% \\ \left(2\right) 13\% \\ \left(3\right) 14\% \\ \left(4\right) 15\% \end{gathered}$$

When the planet Jupiter is at a distance of 824.7 million kilometres from the Earth, its angular diameter is measured to be 35.72” of arc. Then the diameter of Jupiter is:

$$\begin{gathered} \left(1\right) 1.34\times {10}^9 m \\ \left(2\right) 1.43\times {10}^9 m \\ \left(3\right) 1.34\times {10}^8 m \\ \left(4\right) 1.43 \times {10}^8 m \end{gathered}$$

A new unit of length is chosen such that the speed of light in the vacuum is unity. What is the distance between the Sun and the Earth in terms of the new unit if light takes 8 min and 20 sec to cover this distance?