With the usual notations, the following equation S t = u + 1 2 a ( 2 t − 1 ) is

Both numerically and dimensionally correct

Neither numerically nor dimensionally correct

Physics - Units Measurement - Quiz-8

The density of a liquid in the CGS system is 0.625 g/cm³. What is its magnitude in the SI system?

0%

0.625
0%

0.0625
0%

0.00625
0%

625

The period of oscillation of a simple pendulum is given by $T = 2 π \sqrt{\frac{l}{g}}$ where l is about 100 cm and is known to have 1 mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stopwatch of least count 0.1 s. The percentage error in g is:

0%

0.1%
0%

1%
0%

0.2%
0%

0.8%

The percentage errors in the measurement of mass and speed are 2% and 3% respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed:

0%

11%
0%

8%
0%

5%
0%

1%

What is the number of significant figures in 0.310×10³?

0%

2
0%

3
0%

4
0%

6

Error in the measurement of radius of a sphere is 1%. The error in the calculated value of its volume is

0%

1%
0%

3%
0%

5%
0%

7%

The mean time period of second's pendulum is 2.00s and mean absolute error in the time period is 0.05s. To express maximum estimate of error, the time period should be written as

0%

(2.00 ± 0.01) s
0%

(2.00 + 0.025) s
0%

(2.00 ± 0.05) s
0%

(2.00 ± 0.10) s

A body travels uniformly a distance of (13.8 $\pm$ 0.2) m in a time (4.0 ± 0.3) sec. The velocity of the body within error limits is:

0%

(3.45 ± 0.2) ms^-1
0%

(3.45 ± 0.3) ms^-1
0%

(3.45 ± 0.4) ms^-1
0%

(3.45 ± 0.5) ms^-1

The unit of percentage error is

0%

Same as that of physical quantity
0%

Different from that of physical quantity
0%

Percentage error is unit less
0%

Errors have got their own units which are different from that of physical quantity measured

The decimal equivalent of 1/20 up to three significant figures is:

0%

0.0500
0%

0.05000
0%

0.0050
0%

5.0 × 10^-2

Accuracy of measurement is determined by

0%

Absolute error
0%

Percentage error
0%

Both
0%

None of these

A thin copper wire of length l metre increases in length by 2% when heated through 10ºC. What is the percentage increase in area when a square copper sheet of length l metre is heated through 10ºC

0%

4%
0%

8%
0%

16%
0%

None of the above

A physical parameter a can be determined by measuring the parameters b, c, d and e using the relation a = $b^{α} c^{β} / d^{γ} e^{δ}$ . If the maximum errors in the measurement of b, c, d and e are b₁%, c₁%, d₁% and e₁%, then the maximum error in the value of a determined by the experiment is

0%

( $b_{1} + c_{1} + d_{1} + e_{1}$ )%
0%

( $b_{1} + c_{1} - d_{1} - e_{1}$ )%
0%

( $α b_{1} + β c_{1} - γ d_{1} - δ e_{1}$ )%
0%

( $α b_{1} + β c_{1} + γ d_{1} + δ e_{1}$ )%

The resistance R = $\frac{V}{i}$ where V= 100 ± 5 volts and i = 10 ± 0.2 amperes. What is the total error in R

0%

5%
0%

7%
0%

5.2%
0%

$\frac{5}{2}$ %

The periods of oscillation of a simple pendulum in an experiment are recorded as 2.63 s, 2.56 s, 2.42 s, 2.71 s and 2.80 s respectively. The average absolute error will be:

0%

0.1 s
0%

0.11 s
0%

0.01 s
0%

1.0 s

The length of a cylinder is measured with a meter rod having least count 0.1 cm. Its diameter is measured with vernier calipers having least count 0.01 cm. Given that length is 5.0 cm and radius is 2.0 cm. The percentage error in the calculated value of the volume will be

0%

1%
0%

2%
0%

3%
0%

4%

In an experiment, the following observation's were recorded: initial length L = 2.820 m, mass M = 3.00 kg, change in length l = 0.087 cm, diameter D = 0.041 cm. Taking g = 9.81 m/s² and using the formula, Y = $\frac{4 M g L}{π D^{2} l}$ , the maximum permissible error in Y will be:

0%

7.96%
0%

4.56%
0%

6.50%
0%

8.42%

According to Joule's law of heating, heat produced H = I²Rt, where I is current, R is resistance and t is time. If the errors in the measurement of I, R and t are 3%, 4% and 6% respectively then error in the measurement of H is

0%

± 17%
0%

± 16%
0%

± 19%
0%

± 25%

If there is a positive error of 50% in the measurement of the velocity of a body, then the error in the measurement of kinetic energy is:

0%

25%
0%

50%
0%

100%
0%

125%

From the equation $\tan θ = \frac{r g}{v^{2}}$ , one can obtain the angle of banking θ for a cyclist taking a curve (the symbols have their usual meanings). Then say, it is

0%

Both dimensionally and numerically correct
0%

Neither numerically nor dimensionally correct
0%

Dimensionally correct only
0%

Numerically correct only

A physical quantity P is given by P = $\frac{A^{3} B^{\frac{1}{2}}}{C^{- 4} D^{\frac{3}{2}}}$ . The quantity which contributes the maximum percentage error in P is:

0%

A
0%
B
0%
C
0%
D

If L = 2.331 cm, B = 2.1 cm, then L + B =?

0%

4.431 cm
0%

4.43 cm
0%

4.4 cm
0%

4 cm

If the length of rod A is 3.25 ± 0.01 cm and that of B is 4.19 ± 0.01 cm then the rod B is longer than rod A by

(1) 0.94 ± 0.00 cm

0%

(2) 0.94 ± 0.01 cm
0%

(3) 0.94 ± 0.02 cm
0%
3
0%

(4) 0.94 ± 0.005 cm

A physical quantity is given by $X = M^{a} L^{b} T^{c}$ . The percentage error in measurement of M, L and T are $α, β$ and $γ$ respectively. Then maximum percentage error in the quantity X is

0%

$a α + b β + c γ$
0%

$a α + b β - c γ$
0%

$\frac{a}{α} + \frac{b}{β} + \frac{c}{γ}$
0%

None of these

A physical quantity A is related to four observable quantities a, b, c and d as follows, $A = \frac{a^{2} b^{3}}{c \sqrt{d}}$ , the percentage errors of measurement in a, b, c and d are 1%, 3%, 2% and 2% respectively. The percentage error in quantity A will be:

0%
12%
0%
7%
0%
5%
0%
14%

If the acceleration due to gravity is 10 ms^–2 and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is

0%

360000
0%

72,000
0%

36,000
0%

129600

If L, C and R represent inductance, capacitance and resistance respectively, then which of the following does not represent dimensions of frequency? [This question includes concepts from the 12th syllabus]

0%

$\frac{1}{R C}$
0%

$\frac{R}{L}$
0%

$\frac{1}{\sqrt{L C}}$
0%

$\frac{C}{L}$

Number of particles crossing a unit area perpendicular to X-axis in unit time is given by $n = - D \frac{n_{2} - n_{1}}{x_{2} - x_{1}}$ , where n₁ and n₂ are the number of particles per unit volume for the value of x equal to x₁ and x₂ respectively. The dimensions of D, known as diffusion constant, will be:

0%

$M^{0} L T^{2}$
0%

$M^{0} L^{2} T^{- 4}$
0%

$M^{0} L T^{- 3}$
0%

$M^{0} L^{2} T^{- 1}$

With the usual notations, the following equation $S_{t} = u + \frac{1}{2} a (2 t - 1)$ is

0%

Only numerically correct
0%

Only dimensionally correct
0%

Both numerically and dimensionally correct
0%

Neither numerically nor dimensionally correct

If the dimensions of length are expressed as $G^{x} c^{y} h^{z}$ ; where G, c and h are the universal gravitational constant, speed of light and Planck's constant respectively, then

0%

$x = \frac{1}{2}, y = \frac{1}{2}$
0%

$x = \frac{1}{2}, z = \frac{1}{2}$
0%

$y = \frac{1}{2}, z = \frac{3}{2}$
0%

$y = - \frac{3}{2}, z = - \frac{1}{2}$

A highly rigid cubical block A of small mass M and side L is fixed rigidly onto another cubical block B of the same dimensions and of low modulus of rigidity $η$ such that the lower face of A completely covers the upper face of B. The lower face of B is rigidly held on a horizontal surface. A small force F is applied perpendicular to one of the side faces of A. After the force is withdrawn block A executes small oscillations. The time period of which is given by

0%

$2 π \sqrt{\frac{M η}{L}}$
0%

$2 π \sqrt{\frac{L}{M η}}$
0%

$2 π \sqrt{\frac{M L}{η}}$
0%

$2 π \sqrt{\frac{M}{η L}}$

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Practice Physics Quiz Questions and Answers

0:0:1

Practice Physics Quiz Questions and Answers

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