What will be the angular width of central maxima in Fraunhoffer diffraction when light of wavelength 6000 Å is used and slit width is 12×10–5 cm
2 rad
3 rad
1 rad
8 rad
The direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by:(a is the width of the slit)
asinθ=λ2
acosθ=3λ2
asinθ=λ
asinθ=3λ2
A parallel monochromatic beam of light is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the first minimum of the diffraction pattern, the phase difference between the rays coming from the edges of the slit is:
0
π2
π
2π
A parallel beam of monochromatic light of wavelength 5000 Å is incident normally on a single narrow slit of width 0.001 mm. The light is focused by a convex lens on a screen placed on the focal plane. The first minimum will be formed for the angle of diffraction equal to:
0o
15o
30o
60o
In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength λ1 is found to be coincident with the third maximum at λ2. So
3λ1=0.3λ2
3λ1=λ2
λ1=3.5λ2
0.3λ1=3λ2
The angle of polarisation for any medium is 60o, what will be critical angle for this
sin−13
tan−13
cos−13
sin−113
A beam of light AO is incident on a glass slab (μ = 1.54) in a direction as shown in figure. The reflected ray OB is passed through a Nicol prism on viewing through a Nicole prism, we find on rotating the prism that
The intensity is reduced down to zero and remains zero
The intensity reduces down some what and rises again
There is no change in intensity
The intensity gradually reduces to zero and then again increases
In the propagation of electromagnetic waves, the angle between the direction of propagation and plane of polarisation is:
45o
90o
180o
Light passes successively through two polarimeters tubes each of length 0.29m. The first tube contains dextro rotatory solution of concentration 60kgm–3 and specific rotation 0.01rad m2kg–1. The second tube contains laevo rotatory solution of concentration 30kg/m3 and specific rotation 0.02 radm2kg–1. The net rotation produced is
15°
0°
20°
10°
Unpolarized light of intensity 32Wm–2 passes through three polarizers such that transmission axes of the first and second polarizer makes and angle 30° with each other and the transmission axis of the last polarizer is crossed with that of the first. The intensity of final emerging light will be
32 Wm–2
3 Wm–2
8 Wm–2
4 Wm–2
In the visible region of the spectrum the rotation of the place of polarization is given by θ=a+bλ2. The optical rotation produced by a particular material is found to be 30° per mm at λ=5000Å and 50° per mm at λ=4000Å. The value of constant a will be
+50°9per mm
−50°9per mm
+9°50per mm
−9°50per mm
When an unpolarized light of intensity I0 is incident on a polarizing sheet, the intensity of the light which does not get transmitted is
Zero
I0
12I0
(3) 14I0
Two polaroids are placed in the path of unpolarized beam of intensity I0 such that no light is emitted from the second polaroid. If a third polaroid whose polarization axis makes an angle θ with the polarization axis of first polaroid, is placed between these polaroids then the intensity of light emerging from the last polaroid will be:
I08sin22θ
I04sin22θ
I02cos4θ
I0cos4θ
In the adjacent diagram, CP represents a wavefront and AO & BP, the corresponding two rays. What would be the condition on θ for constructive interference at P between the ray BP and reflected ray OP?
cosθ = 3λ/2d
cosθ = λ/4dθ
secθ – cosθ = λ/d
secθ – cosθ = 4λ/d
In the Young's double slit experiment, if the phase difference between the two waves interfering at a point is ϕ, the intensity at that point can be expressed by the expression-
(where A and B depend upon the amplitudes of the two waves)
I=A2+B2cos2ϕ
I=ABcosϕ
I=A+Bcosϕ2
I=A+Bcosϕ
When one of the slits of Young’s experiment is covered with a transparent sheet of thickness 4.8 mm, the central fringe shifts to a position originally occupied by the 30th bright fringe. What should be the thickness of the sheet if the central fringe has to shift to the position occupied by 20th bright fringe
3.8 mm
1.6 mm
7.6 mm
3.2 mm
In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength λ), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is
2λ
2λ3
λ3
λ
In the figure is shown Young’s double-slit experiment, Q is the position of the first bright fringe on the right side of O. P is the 11th bright fringe on the other side, as measured from Q. If the wavelength of the light used is 6000 × 10–10 m, then S1B will be equal to:
6 × 10–6 m
6. 6 × 10–6 m
3.138 × 10–7 m
3.144 × 10–7 m
In Young’s double-slit experiment, the two slits act as coherent sources of equal amplitude A and wavelength λ. In another experiment with the same set up, the two slits are of equal amplitude A and wavelength λ but are incoherent. The ratio of the intensity of light at the mid-point of the screen in the first case to that in the second case is:
1 : 2
2 : 1
4 : 1
1 : 1
A monochromatic beam of light falls on the YDSE apparatus at some angle (say θ) as shown in the figure. A thin sheet of glass is inserted in front of the lower slit S2. The central bright fringe (path difference = 0) will be obtained:
At O
Above O
Below O
Anywhere depending on angle θ, the thickness of plate t and refractive index of glass μ
Two ideal slits S1 and S2 are at a distance d apart and illuminated by the light of wavelength λ passing through an ideal source slit S placed on the line through S2 as shown. The distance between the planes of slits and the source slit is D. A screen is held at a distance D from the plane of the slits. The minimum value of d for which there is darkness at O is:
3λD2
λD
λD2
3λD
Two point sources X and Y emit waves of same frequency and speed but Y lags in phase behind X by 2πl radian. If there is a maximum in direction D the distance XO using n as an integer is given by
λ2(n−l)
λ(n+l)
λ2(n+l)
λ(n−l)
A beam with wavelength λ falls on a stack of partially reflecting planes with separation d. The angle θ that the beam should make with the planes so that the beams reflected from successive planes may interfere constructively is (where n =1, 2, ……)
sin−1nλd
tan−1nλd
sin−1nλ2d
cos−1nλ2d
Two coherent sources separated by distance d are radiating in a phase having wavelength λ. A detector moves in a big circle around the two sources in the plane of the two sources. The angular position of n = 4 interference maxima is given as:
cos−14λd
tan−1d4λ
cos−1λ4d
In a single slit diffraction of light of wavelength λ by a slit of width e, the size of the central maximum on a screen at a distance b is
2bλ+e
2bλe
2bλe+e
2bλe−e
In a YDSE bi-chromatic light of wavelengths, 400 nm and 560 nm are used. The distance between the slits is 0.1 mm and the distance between the plane of the slits and the screen is 1 m. The minimum distance between two successive regions of complete darkness is:
14 mm
28 mm
4 mm
5.6 mm
Unpolarised light is incident from the air on a plane surface of a material of refractive index 'μ'. At a particular angle of incidence 'i', it is found that the reflected and refracted rays are perpendicular to each other. Which of the following options is correct for this situation?
The reflected light is polarised with its electric vector parallel to the plane of incidence.
The reflected light is polarised with its electric vector perpendicular to the plane of incidence.
i=sin-11μ
i=tan-11μ
In Young's double-slit experiment, the separation d between the slits is 2 mm, the wavelength λ of the light used is 5896 Å and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0.20°. To increase the fringe angular width to 0.21° (with same λ and D) the separation between the slits needs to be changed to:-
1.8 mm
1.9 mm
2.1 mm
3. 1.7 mm
For a parallel beam of monochromatic light of wavelength 'λ', diffraction is produced by a single slit whose width 'a' is much greater than the wavelength of the light. If 'D' is the distance of the screen from the slit, the width of the central maxima will be
2Dλa
Dλa
Daλ
2Daλ
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