Which of the following is not true for this progressive wave y = 4 sin 2 π t 0 .02 − x 100 where y and x are in cm and t in sec

Its propagation velocity is 50 × 10 3 cm/sec

Physics - Waves - Quiz-4

Two waves are given by $y_{1} = a \sin (ω t - k x)$ and $y_{2} = a \cos (ω t - k x)$ . The phase difference between the two waves is :

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$\frac{π}{4}$
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π
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$\frac{π}{8}$
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$\frac{π}{2}$

If the amplitude of waves at distance r from a point source is A, the amplitude at a distance 2r will be :

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2A
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A
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A/2
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A/4

A wave is reflected from a rigid support. The change in phase on reflection will be :

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π/4
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π/2
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π
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2π

A plane wave is represented by $x = 1 .2 \sin (314 t + 12 .56 y)$

Where x and y are distances measured along in x and y direction in meters and t is time in seconds. This wave has

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A wavelength of 0.25 m and travels in + ve x-direction
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A wavelength of 0.25 m and travels in + ve y-direction
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A wavelength of 0.5 m and travels in – ve y-direction
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A wavelength of 0.5 m and travels in – ve x-direction

The equation of a wave traveling in a string can be written as $y = 3 \cos π (100 t - x)$ . Its wavelength is :

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100 cm
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2 cm
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5 cm
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None of the above

A transverse wave is described by the equation $y = Y_{0} \sin (2 πft - \frac{2 π}{λ} x)$ . The maximum particle velocity is four times the wave velocity if :

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$λ = \frac{π Y_{0}}{4}$
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$λ = \frac{π Y_{0}}{2}$
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$λ = π Y_{0}$
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$λ = 2 π Y_{0}$

A transverse wave of amplitude 0.5 m and wavelength 1 m and frequency 2 Hz is propagating in a string in the negative x-direction. The expression for this wave is :

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$y (x, t) = 0 .5 \sin (2 π x - 4 π t)$
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$y (x, t) = 0 .5 \cos (2 π x + 4 π t)$
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$y (x, t) = 0 .5 \sin (π x - 2 π t)$
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$y (x, t) = 0 .5 \cos (2 π x + 2 π t)$

The displacement of a particle is given by $y = 5 \times 10^{- 4} \sin (100 t - 50 x)$ ,where x is in metres and t is in seconds. The velocity of the wave is:

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5000 m/sec
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2 m/sec
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0.5 m/sec
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300 m/sec

Which one of the following does not represent a traveling wave :

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$y = \sin (x - v t)$
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$y = y_{m} \sin k (x + v t)$
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$y = y_{m} \sin (x - v t)$
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$y = f (x^{2} - v t^{2})$

The wave equations of two particles are given by $y_{1} = a \sin (ω t - k x)$ , $y_{2} = a \sin (k x + ω t)$ , then:

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they are moving in the opposite direction.
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the phase between them is 90°.
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the phase between them is 45°.
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the phase between them is 0°.

A transverse wave is represented by the equation $y = y_{0} \sin \frac{2 π}{λ} (v t - x)$

For what value of λ, the maximum particle velocity equal to two times the wave velocity?

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$λ = 2 π y_{0}$
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$λ = π y_{0} / 3$
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$λ = π y_{0} / 2$
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$λ = π y_{0}$

A wave travels in a medium according to the equation of displacement given by $y (x, t) = 0 .03 \sin π (2 t - 0 .01 x)$ where y and x are in metres and t in seconds. The wavelength of the wave is :

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200 m
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100 m
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20 m
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10 m

The equation of a progressive wave is given by $y = 4 \sin \{π (\frac{t}{5} - \frac{x}{9}) + \frac{π}{6}\}$ .
Which of the following is correct?

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v = 5 m / sec
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λ = 18 m
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a = 0.04 m
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n = 50 Hz

The frequency of the sinusoidal wave $y = 0 .40 \cos [2000 t + 0 .80 x]$ would be :

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1000 π Hz
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2000 Hz
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20 Hz
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$\frac{1000}{π} H z$

The equation of a plane progressive wave is given by $y = 0 .025 \sin (100 t + 0 .25 x)$ . The frequency of this wave would be :

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$\frac{50}{π} H z$
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$\frac{100}{π} H z$
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100 Hz
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50 Hz

In the given progressive wave equation, what is the maximum velocity of particle $Y = 0 .5 \sin (10 π t - 5 x)$ cm

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5 cm/s
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5π cm/s
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10 cm/s
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10.5 cm/s

Two waves of frequencies 20 Hz and 30 Hz travel out from a common point. The phase difference between them after 0.6 sec is :

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Zero
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$\frac{π}{2}$
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π
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$\frac{3 π}{4}$

A simple harmonic progressive wave is represented by the equation : $y = 8 \sin 2 π (0 .1 x - 2 t)$ where x and y are in cm and t is in seconds. At any instant the phase difference between two particles separated by 2.0 cm in the x-direction is :

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18°
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36°
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54°
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72°

The equation of progressive wave is $y = a \sin (200 t - x)$ . where x is in meter and t is in second. The velocity of wave is :

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200 m/sec
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100 m/sec
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50 m/sec
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None of these

A wave equation that gives the displacement along y-direction is given by $y = 0 .001 \sin (100 t + x)$ where x and y are in meter and t is time in seconds. This represented a wave :

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Of frequency $\frac{100}{π}$ Hz
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Of wavelength one metre
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Traveling with a velocity of $\frac{50}{π}$ ms^–1 in the positive X-direction
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Traveling with a velocity of 100 ms^–1 in the negative X-direction

A wave travelling in positive X-direction with A = 0.2 m has a velocity of 360 m/sec. if λ = 60 m, then the correct expression for the wave is :

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$y = 0 .2 \sin [2 π (6 t + \frac{x}{60})]$
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$y = 0 .2 \sin [π (6 t + \frac{x}{60})]$
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$y = 0 .2 \sin [2 π (6 t - \frac{x}{60})]$
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$y = 0 .2 \sin [π (6 t - \frac{x}{60})]$

Two waves are represented by $y_{1} = a \sin (ω t + \frac{π}{6})$ and $y_{2} = a \cos ω t$ . What will be their resultant amplitude :

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a
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$\sqrt{2} a$
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$\sqrt{3} a$
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2a

Two waves represented by the following equations are travelling in the same medium $y_{1} = 5 \sin 2 π (75 t - 0 .25 x)$ , $y_{2} = 10 \sin π (150 t - 0 .50 x)$

The intensity ratio I₁/I₂ of the two waves is :

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1 : 2
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1 : 4
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1 : 8
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1 : 16

Which of the following is not true for this progressive wave $y = 4 \sin 2 π (\frac{t}{0 .02} - \frac{x}{100})$ where y and x are in cm and t in sec

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Its amplitude is 4 cm
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Its wavelength is 100 cm
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Its frequency is 50 cycles/sec
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Its propagation velocity is 50 × 10³ cm/sec

A transverse progressive wave on a stretched string has a velocity of 10 ms^–1 and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be :

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$\frac{π}{8}$
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$\frac{π}{4}$
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$\frac{3 π}{8}$
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$\frac{π}{2}$

The phase difference between two waves represented by $y_{1} = 10^{- 6} \sin [100 t + (x / 50) + 0 .5] m,$ $y_{2} = 10^{- 6} \cos [100 t + (x / 50)] m$ where x is expressed in metres and t is expressed in seconds, is approximately:

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(1) 5 rad
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(2) 1.07 rad
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(3) 2.07 rad
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(4) 0.5 rad

A particle on the trough of a wave at any instant will come to the mean position after a time (T = time period)

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T/2
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T/4
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T
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2T

When two sound waves with a phase difference of π/2, and each having amplitude A and frequency ω, are superimposed on each other, then the maximum amplitude and frequency of the resultant wave is :

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$\frac{A}{\sqrt{2}} : \frac{ω}{2}$
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$\frac{A}{\sqrt{2}} : ω$
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$\sqrt{2} A : \frac{ω}{2}$
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$\sqrt{2} A : ω$

Two waves are propagating to the point P along a straight line produced by two sources, A and B, of simple harmonic and equal frequency. The amplitude of every wave at P is ‘a’ and the phase of A is ahead by π/3 than that of B, and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter is

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2a
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$a \sqrt{3}$
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$a \sqrt{2}$
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a

The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when :

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Two sources are vibrating in opposite phase
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The amplitude of the two sources are equal
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At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line
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Both the sources are in the same phase

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Practice Physics Quiz Questions and Answers

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Practice Physics Quiz Questions and Answers

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