The length of two open organ pipes are l and (l+Δl) respectively. Neglecting end correction, the frequency of beats between them will be approximate :

(Here v is the speed of sound)

  • v2l

  • v4l

  • vΔl2l2

  • vΔll

A tube closed at one end and containing air is excited. It produces the fundamental note of frequency of 512 Hz. If the same tube is open at both the ends the fundamental frequency that can be produced is :

  • 1024 Hz

  • 512 Hz

  • 256 Hz

  • 128 Hz

A closed pipe and an open pipe have their first overtones identical in frequency.Their lengths are in the ratio :

  • 1 : 2

  • 2 : 3

  • 3 : 4

  • 4 : 5

An empty vessel is getting filled with water, then the frequency of vibration of the air column in the vessel 

  • Remains the same

  • Decreases

  • Increases

  • First increases then decrease

If the velocity of sound in air is 350 m/s. Then the fundamental frequency of an open organ pipe of length 50 cm, will be

  • 350 Hz

  • 175 Hz

  • 900 Hz

  • 750 Hz

The fundamental note produced by a closed organ pipe is of frequency f. The fundamental note produced by an open organ pipe of same length will be of frequency

  • f2

  • f

  • 2f

  • 4f

If the velocity of sound in air is 336 m/s. The maximum length of a closed pipe that would produce a just audible sound will be : 

  • 3.2 cm

  • 4.2 m

  • 4.2 cm

  • 3.2 m

A cylindrical tube, open at both ends, has a fundamental frequency f0 in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of the air column now is

  • 3 f0/4

  • f0

  • f0/2

  • 2 f0

If the length of a closed organ pipe is 1.5 m and the velocity of sound is 330 m/s, then the frequency for the second note is

  • 220 Hz

  • 165 Hz

  • 110 Hz

  • 55 Hz

A pipe 30 cm long is open at both ends. Which harmonic mode of the pipe is resonantly excited by a 1.1 kHz source? (Take the speed of sound in air = 330 ms–1) 

  • First

  • Second

  • Third

  • Fourth

Two closed pipe produce 10 beats per second when emitting their fundamental nodes. If their length are in ratio of 25 : 26. Then their fundamental frequency in Hz, are :

  • 270, 280

  • 260, 270

  • 260, 250

  • 260, 280

If v is the speed of sound in the air then the shortest length of the closed pipe which resonates to a frequency n :

  • v4n

  • v2n

  • 2nv

  • 4nv

The frequency of fundamental tone in an open organ pipe of length 0.48 m is 320 Hz. The speed of sound is 320 m/sec. Frequency of fundamental tone in closed organ pipe will be : 

  • 153.8 Hz

  • 160.0 Hz

  • 320.0 Hz

  • 143.2 Hz

What is the minimum length of a tube, open at both ends, that resonates with tuning fork of frequency 350 Hz? [velocity of sound in air = 350 m/s] 

  • 50 cm

  • 100 cm

  • 75 cm

  • 25 cm

The harmonics which are present in a pipe open at one end are :

  • Odd harmonics

  • Even harmonics

  • Even as well as odd harmonics

  • None of these

The stationary wave y=2asinkxcosω t in a closed organ pipe is the result of the superposition of y=asin(ω t−kx) and

  • y=−acos(ω t+kx)

  • y=−asin(ω t+kx)

  • y=asin(ω t+kx)

  • y=acos(ω t+kx)

An open pipe of length l vibrates in the fundamental mode. The pressure variation is maximum at :

  • l/4 from ends

  • The middle of the pipe

  • The ends of the pipe

  • At l/8 from ends of pipe

The fundamental frequency of pipe is 100 Hz and the other two frequencies are 300 Hz and 500 Hz then :

  • The pipe is open at both the ends

  • The pipe is closed at both the ends

  • One end open and another end is closed

  • None of the above

The fundamental frequency of an open pipe of length 0.5 m is equal to the frequency of the first overtone of a closed pipe of length l. The value of lc is (m) :

  • (1) 5

  • (2) 0.75

  • (3) 2

  • (4) 1

In a closed organ pipe, the frequency of the fundamental note is 50 Hz. The note of which of the following frequencies will not be emitted by it :

  • 50 Hz

  • 100 Hz

  • 150 Hz

  • None of the above

On producing the waves of frequency 1000 Hz in a Kundt's tube, the total distance between 6 successive nodes is 85 cm. Speed of sound in the gas filled in the tube is 

  • 330 m/s

  • 340 m/s

  • 350 m/s

  • 300 m/s

What is the base frequency if a pipe gives notes of frequencies 425, 255 and 595 and decide whether it is closed at one end or open at both ends :

  • 17, closed

  • 85, closed

  • 17, open

  • 85, open

A student determines the velocity of sound with the help of a closed organ pipe. If the observed length for fundamental frequency is 24.7 cm, the length for third harmonic will be :

  • 74.1 cm

  • 72.7 cm

  • 75.4 cm

  • 73.1 cm

In a resonance tube the first resonance with a tuning fork occurs at 16 cm and second at 49 cm. If the velocity of sound is 330 m/s, the frequency of tuning fork is :

  • 500

  • 300

  • 330

  • 165

Two closed organ pipes of length 100 cm and 101 cm 16 beats in 20 sec. When each pipe is sounded in its fundamental mode calculate the velocity of sound 

  • 303 ms–1

  • 332 ms–1

  • 323.2 ms–1

  • 300 ms–1

An organ pipe, open from both end produces 5 beats per second when vibrated with a source of frequency 200 Hz. The second harmonic of the same pipe produces 10 beats per second with a source of frequency 420 Hz. The frequency of source is 

  • 195 Hz

  • 205 Hz

  • 190 Hz

  • 210 Hz

In one metre long open pipe what is the harmonic of resonance obtained with a tuning fork of frequency 480 Hz : (Velocity of sound: 320 m/s)

  • First

  • Second

  • Third

  • Fourth

In a resonance pipe the first and second resonances are obtained at depths 22.7 cm and 70.2 cm respectively. What will be the end correction 

  • (1) 05 cm

  • (2) 115.5 cm

  • (3) 92.5 cm

  • (4) 113.5 cm

An open tube is in resonance with string (frequency of vibration of the tube is n0). If the tube is dipped in water so that 75% of the length of the tube is inside water, then the ratio of the frequency of tube to string now will be :

  • 1

  • 2

  • 23

  • 32

A source of sound of frequency 450 cycles/sec is moving towards a stationary observer with 34 m/sec speed. If the speed of sound is 340 m/sec, then the apparent frequency will be 

  • 410 cycles/sec

  • 500 cycles/sec

  • 550 cycles/sec

  • 450 cycles/sec

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