MCQ Questions for Class 10 Chemistry Carbon And Its Compounds Quiz 6

The total no. of electrons that take part in forming a bond in

N_{2}

$N_2$ is :

0%
2
0%
4
0%
6
0%
10

Covalent bonds are formed when electrons are ____________. Covalent compounds have ____________ electrical conductivity.

0%
shared, high
0%
shared, low
0%
transferred, high
0%
transferred, low

Graphite differs from diamond because graphite is:

0%
greyish black in colour and bad conductor of electricity
0%
slippery to touch and good conductor of electricity
0%
greyish black in colour and bad conductor of heat
0%
slippery to touch and good conductor of heat

Which one of the following is not a property of carbon?

0%
It exhibits catenation.
0%
It forms multiple bonds.
0%
Its melting points and boiling points are very high.
0%
It is a metalloid.

In the Earth's crust, Carbon is found in the form of_________.

0%
carbonates
0%
hydrogen carbonates
0%
petroleum
0%
All of the above

Due to the weak Van der Waals' forces and less distance between the layers, graphite:

0%
show lubricating property.
0%
has lusture.
0%
is hexagonal.
0%
is a good conductor of electricity.

The property of catenation is seen maximum in ____________ element.

0%
cadmium
0%
chlorine
0%
carbon
0%
copper

In double covalent bond, there is sharing of :

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2 electrons
0%
4 electrons
0%
6 electrons
0%
3 electrons

Following are the uses of a substance.

(i) It is used as an abrasive for cutting glass.

(ii) It is used as a tip of deep boring drills.

(iii) It is used for making dies for drawing wires.

(iv) It is used in generating laser beams in electronics.

What is the name of this substance?

0%
Diamond
0%
Buckminsterfullerene
0%
Lampblack
0%
Graphite

Explanation

Diamond is an allotropic form of carbon. It is the hardest substance known. Uses of a diamond are:

It is used as an abrasive in cutting glass.
It is used for making dies for drawing wires.
It is used in generating laser beams in electronics.
It is used as a tip of deep boring drills.
It is ideal for grinding, cutting, drilling and polishing.

Hence, the correct option is

A

$\text{A}$

Which of the following are members of same homologous series?

0%
$HCOOCH_3$ and $CH_3COOCH_3$
0%
$HCOOH$ and $HCOOCH_3$
0%
$CH_3COCH_3$ and $CH_3CH_2CHO$
0%
$C_2H_5OH$ and $CH_3OCH_3$

Explanation

H i n t :

$\bf{Hint:}$ It is a series of compounds with similar chemical properties and some functional groups differing by methylene group (

- C H_{2}

$-CH_2$ )

$\bf{Correct \ answer:}$ Option

$A$

$\bf{Explanation \ for \ correct \ option:}$

A homologous series is a family of hydrocarbons with similar chemical properties that share the same general formula.

Both given compound

$HCOOCH_{3}$ and

$CH_{3}COOCH_{3}$ are homologous series of a simple ester group

$RCOOH$ , where a successive methyl group

$-CH_{3}$ added to previous one.

$\bf{Explanation \ for \ incorrect \ options:}$

Compound $CH_3COOH$ is a second homologous compound for $HCOOH$ . It is not a successive member, therefore, it is not a member of the same homologous series.

In both compounds, $CH_{3}COCH_{3}$ and $CH_{3}CH_{2}CHO$ the functional group are different, hence it could not be homologous members.

In both compounds, $C_{2}H_{5}OH$ and $CH_{3}OCH_{3}$ the functional group are different, hence it could not be homologous members.

Identify the unsaturated compounds from the following :

$(i)$ Propane

$(ii)$ Propene

$(iii)$ Propyne

$(iv)$ 2-Chloropropane

0%
$(i)$ & $(ii)$
0%
$(ii)$ & $(iv)$
0%
$(iii)$ & $(iv)$
0%
$(ii)$ & $(iii)$

Explanation

(i) Propane

$CH_3-CH_2-CH_3$
(ii) Propene

$CH_3-CH=CH_2$

(iii) Propyne

$CH_3-C \equiv CH$

(iv) 2-Chloropropane

$CH_3-CH(Cl)-CH_3$

Propene and propyne are unsaturated compound as they contain carbon-carbon multiple bonds.

Which general formula represents the homologous series of hydrocarbons that includes the compound 1-heptyne?

0%
$C_nH_{2n-6}$
0%
$C_nH_{2n}$
0%
$C_nH_{2n-2}$
0%
$C_nH_{2n+2}$

Explanation

1-heptyne is alkyne. The general formula for alkyne is

$C_nH_{2n-2}$ .

How can we get compound X back from Y? Name the process.

0%
Saponification
0%
Hydrogenation
0%
Carbonation
0%
None of these

Explanation

The molecular formula of a given organic compound is

$C_2H_4O_2$ and it is also used as preservatives in pickles means it is acetic acid.

When acetic acid

$(X)$ reacts with ethanol it forms sweet-smelling compound ester

$(Y)$ .

$CH_3COOH + CH_3CH_2OH \rightarrow CH_3COOC_2H_5 + H_2O$

$X$

$Ethanol$

$Y$

To get back

$X$ (acetic acid) from

$Y$ (ester),

$Y$ is treated with sodium hydroxide, then ester is converted back into ethanol, and sodium salt of carboxylic acid(acetic acid) is formed.

$CH_3COOC_2H_5+NaOH\rightarrow C_2H_5OH+CH_3COONa$

The process is known as saponification.

All members of a homologous series differ by a:

0%
methyl group
0%
methylene group
0%
methane group
0%
None of these

Explanation

Homologous series differ by a

$CH_2$ group known as the methylene group.

Which of the following statements are usually correct for carbon compounds?

(i) They are good conductors of electricity.
(ii) They are poor conductors of electricity.
(iii) They have strong forces of attraction between their molecules.
(iv) They do not have strong forces of attraction between their molecules.

0%
(i) and (iii)
0%
(ii) and (iii)
0%
(i) and (iv)
0%
(ii) and (iv)

Explanation

Usually, the statements (ii) and (iv) are correct for carbon compounds.

(ii) They are poor conductors of electricity. They contain covalent bonds. Free electrons are not present which can conduct electricity.

(iv) They do not have strong forces of attraction between their molecules.

So, the correct option is

$D$

Identify the substance which is:
(i) Used in making leads of pencils.
(ii) Used as a dry lubricant.
(iii) Used in making black paint and printers ink.
(iv) Used in nuclear reactors as a moderator.

0%
Diamond
0%
Buckminsterfullerene
0%
Lampblack
0%
Graphite

What is not true about homologous series?

0%
All members have similar chemical properties
0%
They have identical physical properties
0%
They can be represented by a general formula
0%
None of the above

Explanation

Homologous series differ by a $CH_2$ group. They have similar chemical properties as they have a common functional group.
They can be represented by a general formula for alkanes, alkenes, alkynes, and other functional groups.
However, as the molecular mass increases in a homologous series, a gradation in physical properties is observed. So, they do not have identical physical properties.

The characteristic chemical reaction shown by alkanes is :

0%
substitution reaction
0%
addition reaction
0%
subtraction reaction
0%
none of these

Explanation

The characteristic chemical reaction shown by alkanes is a substitution reaction. The H atom of alkanes is substituted with some other atom.

For example, when methane reacts with chlorine in presence of UV rays, it gives methyl chloride. H is replaced with Cl.

$CH_4 + Cl_2 \xrightarrow { \text { U . V rays}} CH_3Cl + HCl$

As alkane does not contain any double or triple bond so they do not undergo additional reactions.

Option A is correct.

Addition reactions occur in :

0%
saturated hydrocarbons
0%
unsaturated hydrocarbons
0%
both A and B
0%
none of these

Explanation

Addition reactions occur in unsaturated hydrocarbons.
A reactant molecule is added to carbon carbon multiple bond.
For example, when ethylene is heated with a molecule of bromine, 1,2-dibromo ethane is obtained.
A molecule of bromine is added across carbon carbon double bond.

$CH_2 = CH_2 + Br-Br \xrightarrow {\Delta } Br-CH_2-CH_2-Br$

What is the name of the compound

$CH_3CH_2CH(CH_3)CH_2OH$ ?

0%
2-methylbutanol
0%
3-methylbutanol
0%
2-methylpentanol
0%
Pentanol

Explanation

The name of the compound is 2-methyl butanol.

Since

$-OH$ is the only functional group in this compound, we will start numbering from carbon nearest to the

$-OH$ group. Then find the longest carbon chain that is 4 carbons means the word root is "but" and methyl is substituted at 2nd position. Hence, the name would be 2-methyl butanol.

All members of a homologous series have the same :

0%
chemical formula.
0%
empirical formula.
0%
boiling point.
0%
melting point.

Explanation

Homologous series differ by a

$CH_2$ group. It has a mass of 14 units. They can be represented by a common general formula for alkanes, alkenes, alkynes, and other functional groups. They can thus, be represented by a common empirical formula.

For example alkanes has empirical formula

$C_nH_{2n+2}$ and for alkenes it is

$C_nH_{2n}$ etc.

Hence, option

$B$ is correct.

What is the name of the compound shown in the figure?

0%
Butene
0%
Propyne
0%
Propyne-2
0%
Butyne

Which is the correct name for

$CH_3CH_2CH_2CH_2CH_2CONH_2$ ?

0%
Hexanamide
0%
6-hexanamide
0%
6-hexanamine
0%
Pentanamide

Explanation

The

$CONH_2$ is an amide group. Longest chain consists of 6 carbon atoms. The correct name of the compound is hexanamide.

Carbon can form a maximum of _____ covalent bonds.

0%
1
0%
2
0%
3
0%
4

Explanation

Carbon has four electrons in its outermost shell, therefore, it can form a maximum of four covalent bonds with other atoms or molecules.

Hence, the correct option is $D$ .

What is the IUPAC name of the compound shown in the image?

0%
1,1,1,1-tetra ethyl methane
0%
2,2-dimethyl pentane
0%
3,3-diethyl pentane
0%
3,3-dimethyl butane

What is the IUPAC name of the compound $CH_3CH_2CH_2CH_2NH_2$ ?

0%
Pentanamine
0%
Aminobutane
0%
Butanamine
0%
Butanamide

Define homologous series.

0%
Compound with same melting point
0%
Compound with same molecular mass
0%
Compounds with different general formula
0%
Compounds with same functional group substitutes for hydrogen in a carbon chain

Explanation

A homologous series is a series of compounds with the same general formula. But they have different melting points (physical properties) and different molecular masses. However, they have the same functional group substitutes for hydrogen in a carbon chain.

Example:

$CH_3OH, C_2H_5OH, C_3H_7OH$

The first step in naming carbon compounds is to:

0%
determine the parent chain
0%
name the substituents
0%
count the number of branched chains
0%
None of these

Addition reaction of alkenes and alkynes leads to:

0%
polymerisation
0%
saturation
0%
unsaturation
0%
catalyzation

On earth, all living cells are _______ based.

0%
carbon
0%
nitrogen
0%
oxygen
0%
helium

CBSE Questions for Class 10 Chemistry Carbon And Its Compounds Quiz 6 - MCQExams.com

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Practice Class 10 Chemistry Quiz Questions and Answers

CBSE Questions for Class 10 Chemistry Carbon And Its Compounds Quiz 6 - MCQExams.com

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Practice Class 10 Chemistry Quiz Questions and Answers

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