MCQ Questions for Class 9 Maths Coordinate Geometry Quiz 3

Observe the given figure and complete the following statement.

The

$x$ -coordinate and

$y$ -coordinate of the point

$S$ are ______ and ______ respectively. Hence the coordinate of

$S$ is ______.

0%
$3,-5,(3,-4)$
0%
$3,-6,(3,-4)$
0%
$3,4,(3,-4)$
0%
$3,-4,(3,-4)$

Explanation

The point

$S$ is at a distance of

$4$ units from the

$x$ - axis and

$3$ units from the

$y$ - axis., and it lies in the

$4^{th}$ quadrant.

So, the abscissa or the

$x$ -coordinate is

$3$ and ordinate or the

$y$ -coordinate is

$-4$ .

Thus, the coordinate of the point

$S$ is

$(3,-4)$ .

Hence,

$Op-D$ is correct.

The point

$(0,3)$ lies on:

0%
$+$ ve $x$ -axis
0%
$+$ ve $y$ -axis
0%
$-$ ve $x$ -axis
0%
$-$ ve $y$ -axis

Explanation

Given, the point is

$(0,3)$

Since the

$x$ -coordinate being

$0$ , the point clearly lies on the

$y$ -axis.

The

$y$ -coordinate

$3$ being positive, the point lies on the

$+$ ve

$y$ -axis.

Therefore, option

$B$ is correct.

The coordinates of a point on ____ are of the form

$(0, y).$

0%
$Y\;-\;\text{axis}$
0%
$X\;-\;\text{axis}$
0%
Both $A$ and $B$
0%
None of the Above

Explanation

Since the

$x$ coordinate of the point is

$0$ , this implies that for any value of

$y$ the point

$(0,y)$ will lie on the

$Y\;-\;\text{axis}.$

The horizontal axis is called ______ axis.

0%
y-axis
0%
x-axis
0%
Ambiguous
0%
Data insufficient

Which of the following statements is true?

0%
The $x-$ axis is a vertical line.
0%
The $y-$ axis is a horizontal line.
0%
The scale on both axes must be the same in a Cartesian plane.
0%
The point of intersection between the $x-$ axis and $y-$ axis is called the origin.

Explanation

Let us investigate the options.

Option A:

$\longrightarrow$ Any point on the

$x-$ axis is

$(x,0)$ .

$x-$ axis is horizontal.

So, option A is incorrect.

Option B:

$\longrightarrow$ Any point on the

$y-$ axis is

$(0,y)$ .

$y-$ axis is vertical.

So, option B is incorrect.

Option C:

$\longrightarrow$ We can choose any convenient scale on

$x-$ axis and

$y-$ axis.

So, option C is incorrect.

Option D:

$X-$ axis &

$Y-$ axis are perpendicular to each other and they intersect at O which is the origin.

The point (-6, 0) lies on _______ axis.

0%
$y$ -axis
0%
$x$ -axis
0%
Both axes
0%
None of these

Explanation

Given point

$(-6,0)$ .

Here, the abscissa or

$x$ -coordinate is

$-6$ and the ordinate or

$y$ -coordinate is

$0$ .

We know, any point on the

$x$ -axis has the form

$(a,0)$ and any point on the

$y$ -axis has the form

$(0,a)$ , where

$a$ is any number.

Clearly, the given point is of the form

$(a,0)$ .

Hence, it lies on the

$x$ -axis.

Therefore, option

$B$ is correct.

The point

$(0, 0)$ lies on ______ axis.

0%
$X$ -axis
0%
$Y$ -axis
0%
Both axes
0%
None of these

Explanation

We know, the co-ordinates of the point of intersection of

$x$ -axis and

$y$ -axis is called the origin.

Also, the two axes intersect each other when

$x=0$ and

$y=0$ .

That is, the co-ordinates of the origin is

$(0,0)$ .

Hence, the given point is the origin.

Then, the origin lies in both the axes

$x$ and

$y$ .

Therefore, option

$C$ is correct.

State the quadrant in which the coordinate

$(15, -2)$ lies:

0%
$I$
0%
$IV$
0%
$II$
0%
$III$
0%
none of these

Explanation

Given point is

$(15,-2)$ .

We know,

$I^{st}$ quadrant, both

$x$ and

$y$ are positive,
In

$II^{nd}$ quadrant,

$x$ is negative and

$y$ is positive,
In

$III^{rd}$ quadrant, both

$x$ and

$y$ are negative
and in

$IV^{th}$ quadrant,

$x$ is positive and

$y$ is negative.

$(15,-2)$ ,

$x$ is positive and

$y$ is negative.
Therefore,

$(15,-2)$ lies in

$IV^{th}$ quadrant.
Option

$B$ is correct.

In which quadrant does the point

$(2, 7)$ lie?

0%
$I$ quadrant
0%
$II$ quadrant
0%
$III$ quadrant
0%
$IV$ quadrant

Explanation

Given, $(2,7)$ .

Here, both the $x$ -coordinate and $y$ -coordinate are positive.

Therefore, $(2,7)$ lies in $1$ st quadrant.

Hence, option $A$ is correct.

If abscissa and ordinate of a point are

$-$ ve and

$+$ ve respectively, then in which quadrant does this point lie?

0%
$II$ quadrant.
0%
$I$ quadrant.
0%
$III$ quadrant.
0%
$IV$ quadrant.

The point

$(0,8)$ lies on ______ axis.

0%
$X$ -axis
0%
$Y$ -axis
0%
Both axes
0%
None of these

Explanation

We know, in the $xy$ -plane, any point on the $y$ -axis will have $x =0$ .
Hence, any point on the $y$ -axis is of the form $(0,y)$ , where $y$ can be any non-zero number.

Therefore, any point whose $x$ -coordinate is $0$ and $y$ -coordinate is non-zero will lie on the $y$ -axis.

Here, the given point is $(0,8)$ is of the form $(0,y)$ , where $y=8$ .

and therefore lies on the $y$ -axis.

Hence, option $B$ is correct.

Point

$(0, -3)$ lies on:

0%
$+$ ve $X$ -axis
0%
$-$ ve $X$ -axis
0%
$+$ ve $Y$ -axis
0%
$-$ ve $Y$ -axis

The perpendicular distance of point

$P(3, 4)$ from

$x$ -axis is:

0%
$3$
0%
$4$
0%
$0$
0%
$5$

Explanation

Given,

$P(3,4)$ .

Here, ordinate of

$P = 4$ , which is its perpendicular distance from

$x$ -axis.

Therefore, option

$B$ is correct.

Ordinate of all points on

$x$ -axis is:

0%
$0$
0%
$1$
0%
$2$
0%
$3$

Explanation

Coordinate of all points on

$x$ -axis is of the form

$(x,0)$ .
Therefore, clearly the ordinate will be

$0$ .

Hence, option

$A$ is correct.

Which of the following point lies in

$II$ quadrant?

0%
$A$
0%
$D$
0%
$G$
0%
$H$

Explanation

Consider point is $A$ .

Here, the point is at a distance of $2$ units right of the $y$ -axis.

So, its abscissa will be $2$ .

Also, the point is at a distance of $2$ unit above the $x$ -axis.

So, its ordinate will be $2$ .

Therefore, the co-ordinates of the required point are $A(2,2)$ .

Hence, the point lies on the $I$ st quadrant.

Consider point is $D$ .

Here, the point is at a distance of $6$ units left of the $y$ -axis.

So, its abscissa will be $-6$ .

Also, the point is at a distance of $4$ unit above the $x$ -axis.

So, its ordinate will be $4$ .

Therefore, the co-ordinates of the required point are $D(-6,4)$ .

Hence, the point lies on the $II$ nd quadrant.

Consider point is $G$ .

Here, the point is at a distance of $7$ units left of the $y$ -axis.

So, its abscissa will be $-7$ .

Also, the point is at a distance of $5$ unit below the $x$ -axis.

So, its ordinate will be $-5$ .

Therefore, the co-ordinates of the required point are $G(-7,-5)$ .

Hence, the point lies on the $III$ rd quadrant.

Consider point is $H$ .

Here, the point is at a distance of $5$ units right of the $y$ -axis.

So, its abscissa will be $5$ .

Also, the point is at a distance of $3$ unit below the $x$ -axis.

So, its ordinate will be $-3$ .

Therefore, the co-ordinates of the required point are $H(5,-3)$ .

Hence, the point lies on the $IV$ th quadrant.

Therefore, the only point that lies in the $II$ nd quadrant is $D(-6,4)$ .

Hence, option $B$ is correct.

The coordinates of a point lying on the

$x$ -axis and its distance from

$+$ ve

$y$ -axis is

$3$ are:

0%
$(3, 0)$
0%
$(-3, 0)$
0%
$(0, 3)$
0%
$(0, -3)$

Explanation

Here,

Abscissa

$= +3,-3$

$(\because$ Distance from

$+$ ve

$y$ -axis).
Ordinate

$= 0$

$(\because$ The point lie on the

$x$ -axis).

Hence, the points are

$(3,0)$ and

$(-3,0)$ .

Therefore, options

$A$ and

$B$ are correct.

What are the co-ordinates of

$O$ ?

0%
$(1,1)$
0%
$(1,0)$
0%
$(0,0)$
0%
$(0,1)$

Explanation

We know, the coordinates of the point of intersection of $x$ - axis and $y$ - axis is called the origin.

That is, the co-ordinates of the origin is $(0,0)$ .

Therefore, option $C$ is correct.

Among all the points which has the largest abscissa in terms of magnitude?

0%
$B$
0%
$D$
0%
$C$
0%
$G$

Explanation

Consider point is $B$ .

Here, the point is at a distance of $6$ units right of the $y$ -axis $\implies x=6$ .

Also, the point is at a distance of $1$ unit above the $x$ -axis $\implies y=1$ .

Therefore, the co-ordinates of the required point are $B(6,1)$ .

the abscissa is $6$ .

Hence, the magnitude of abscissa is $6$ .

Consider point is $D$ .

Here, the point is at a distance of $6$ units left of the $y$ -axis $\implies x=-6$ .

Also, the point is at a distance of $4$ unit above the $x$ -axis $\implies y=4$ .

Therefore, the co-ordinates of the required point are $D(-6,4)$ .

the abscissa is $-6$ .

Hence, the magnitude of abscissa is $6$ .

Consider point is $C$ .

Here, the point is at a distance of $4$ units right of the $y$ -axis $\implies x=4$ .

Also, the point is at a distance of $5$ unit above the $x$ -axis $\implies y=5$ .

Therefore, the co-ordinates of the required point are $G(4,5)$ .

the abscissa is $4$ .

Hence, the magnitude of abscissa is $4$ .

Consider point is $G$ .

Here, the point is at a distance of $7$ units left of the $y$ -axis $\implies x=-7$ .

Also, the point is at a distance of $5$ unit below the $x$ -axis $\implies y=-5$ .

Therefore, the co-ordinates of the required point are $G(-7,-5)$ .

the abscissa is $-7$ .

Hence, the magnitude of abscissa is $7$ .

Therefore, the only point which has the largest abscissa in terms of magnitude is $G(-7,-5)$ .

Hence, option $D$ is correct.

What are the coordinates of

$\text{P}$ ?

0%
$(0,2)$
0%
$(2,0)$
0%
$(-2,0)$
0%
$(0,-2)$

Explanation

The required point is $\text{P}$ .

Here, the point lies on $x$ -axis.

Then, its ordinate is $0$ i.e. $y = 0$ .

Also, the point is at a distance of $2$ units right of the $y$ -axis.

So, its abscissa will be $+2$ .

Hence, the coordinates of the required point are $\text{P}(2,0)$ .

Therefore, option $\text{B}$ is correct.

Which of the given points lie in quadrant

$\text{IV}$ :

$P (-2, 2), Q (3, -3), R (1, -1), S (-2, -3)$ and

$T (-5, 5)$

0%
$P$ and $T$
0%
$Q$ and $R$
0%
Only $S$
0%
$P$ and $R$

Explanation

For points in quadrant $\text{IV}$ :

$x$ co-ordinate is positive

$y$ co-ordinate is negative

Points

$Q(3,-3)$ and

$R(1,-1)$ have positive

$x$ coordinate and negative

$y$ coordinate.

So, option

$B$ is correct.

Ordinate of a point is negative in _____ quadrant

0%
$I$ and $II$
0%
$II$ and $III$
0%
$III$ and $IV$
0%
$IV$ and $I$

Explanation

Points that lie below the

$X$ -axis, have their

$y$ co-ordinates negative.

Hence,

$III$ and

$IV$ quadrants have negative ordinates.

So, option

$C$ is correct.

A point both of whose co-ordinates are negative will lie in _____ quadrant

0%
$I$
0%
$II$
0%
$III$
0%
$IV$

Explanation

$XY$ plane is divided into four quadrants.

$1^{st}$ quadrant has both coordinates positive,

$2^{nd}$ quadrant has

$x$ negative and

$y$ positive.

$3^{rd}$ quadrant has both the coordinates negative.

Hence, the answer is

$3^{rd}$ quadrant.

What is the ordinate of point

$D$ ?

0%
$-6$
0%
$4$
0%
$-2$
0%
$10$

Explanation

The required point is $D$ .

Here, the point is at a distance of $6$ units left of the $y$ -axis $\implies x=-6$ .

Also, the point is at a distance of $4$ units above the $x$ -axis $\implies y=4$ .

Therefore, the co-ordinates of the required point are $D(-6,4)$ .

the ordinate is $4$ .

Hence, option $B$ is correct.

Abscissa of a point is positive in _____ quadrant

0%
$I$ and $II$
0%
$II$ and $III$
0%
$III$ and $IV$
0%
$IV$ and $I$

Explanation

Abscissa of a point means the

$x$ co-ordinate of the point.

Points that lie in the

$I$ and

$IV$ quadrants have their

$x$ co-ordinates positive.

So, option

$D$ is correct,

The point

$(-11, 0)$ lies:

0%
On the negative direction of $y$ -axis
0%
In the $III$ quadrant
0%
On the negative direction of $x$ -axis
0%
In the $IV$ quadrant

Explanation

Given, the point $(-11,0)$ .

That is, $x$ is $-11$ , which is negative and $y$ is $0$ , i.e. the point lies on the $x$ -axis.

Hence, the given point $(-11,0)$ lies on the negative direction of $x$ -axis.

Therefore, option $C$ is correct.

Signs of abscissa and ordinate of a point in the

$III$ quadrant, respectively are

0%
$+, +$
0%
$-, -$
0%
$-, +$
0%
$+, -$

Explanation

$III$ quadrant, both

$x$ and

$y$ co-ordinates are negative.

So, option

$B$ is correct.

Point

$(0, -9)$ lies

0%
On the $X$ -axis
0%
In the $II$ quadrant
0%
On the $Y$ -axis
0%
In the $IV$ quadrant

Point

$(-3, 7)$ lies in the _____ quadrant

0%
$I$
0%
$II$
0%
$III$
0%
$IV$

Explanation

$II$ quadrant only

$x$ -coordinate is negative.

So, option

$B$ is correct.

Write the following based on the graph.

The ordinate of L is

0%
$-7$
0%
$7$
0%
$-5$
0%
None of these

Explanation

It is clear from the dotted line that ordinate of point

$L$ is

$-7$

1074572_571159_ans_110ae663a3cd45b681153f21441e602a.png

$P (-2, 2), Q (3, -3), R (1, -1), S (-2, -3)$ and

$T (-5, 5)$ are plotted on the graph paper, then which points lie on

$II$ quadrant?

0%
$P$ and $T$
0%
$Q$ and $R$
0%
Only $S$
0%
$P$ and $R$

Explanation

We know, in the $xy$ -plane, any point is of the form $(x,y)$ , where $x,y$ can be any real number.

Also, for the point $(x,y)$ ,

$I$ quadrant both

$x$ and

$y$ are positive,
in

$II$ quadrant

$x$ is negative and

$y$ is positive,
in

$III$ quadrant both

$x$ and

$y$ are negative
and in

$IV$ quadrant

$x$ is positive and

$y$ is negative.

From the given points, only

$P(-2,2)$ and

$T(-5,5)$ has its

$x$ -coordinate negative and

$y$ -coordinate positive, and therefore these two points lie in the

$II$ nd quadrant.

Therefore, option

$A$ is correct.

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 3 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 3 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

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