MCQ Questions for Class 9 Maths Coordinate Geometry Quiz 5

The point

$(0,6)$ lies on:

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x-axis
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y-axis
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Origin
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None

Explanation

The given point is

$(0,6)$ .

Hence, its x-coordinate is

$0$ and y-coordinate is

$6$ .

We know that, x-coordinate of a point is the perpendicular distance of the point from

$y-axis$ and y-coordinate is the perpendicular distance from the

$x-axis$ .

Hence, the given point is at

$0$ units distance from

$y-axis$ and

$6$ units distance from the

$x-axis$ .

Therefore, the point lies on

$y-axis$ .

Point

$\left(-3,5\right)$ lies in the

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First quadrant
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Second quadrant
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Third quadrant
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Fourth quadrant

Explanation

Every point on second quadrant has value of abscissa negative and its ordinate is positive.

Point

$\left(-3,5\right)$ has abscissa is negative and ordinate is positive. So, it lies in the second quadrant.

Hence,

$\left(B\right)$ second quadrant, is the correct answer.

In the given figure, the point identified by the coordinates

$\left(-5,3\right)$ is

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T
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R
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L
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S

Explanation

Clearly, point T lies in the fourth quadrant. The distance of T from the y-axis is

$3$ unit and from the x-axis is

$5$ units below the x-axis. So, the point identified by the coordinate

$\left(-5,3\right)$ is T.

A point both of whose coordinates are negative will lie in

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$I$ quadrant
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$II$ quadrant
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$III$ quadrant
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$IV$ quadrant

Explanation

A point both of whose coordinates are whose coordinates are negative will lie in

$III$ quadrant because, in

$III$ quadrant x - coordinates and y - coordinate both are negative.
Hence,

$\left(C\right)$ is the correct answer.

In order to give the precise location of a point in a piece of paper, the no. of independent elements info. required are?

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1
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2
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3
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4

A point is at a 3 ut. distance from the bottom and 4 ut. distance from the edge. So, the precise location of the point would be P(3,4)

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True
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False

Abscissa of a point is positive in

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$I \, and \, II$ quadrants
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$I \, and \, IV$ quadrants
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$I$ quadrant only
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$II$ quadrant only

Explanation

$\textbf{Step -1: Observing the X-Y graph.}$

$\text{We can divide the X-Y graph into 4 quadrants where }$

$\text{x- +ve and y-+ve}\implies \text{1st quadrant}$

$\text{x- -ve and y- +ve}\implies \text{2nd quadrant}$

$\text{x- -ve and y- -ve}\implies \text{3rd quadrant}$

$\text{x-+ve and y- - ve}\implies \text{4th quadrant}$

$\textbf{Step -2: Finding points with positive abscissa}$

$\text{On observing the graph we can see that the x-coordinate of a point is positive in the }I$

$\text{ and }IV \text{ quadrants}$

$\textbf{Hence, the abscissa of a point is positive in the }\mathbf{I \text{ and } IV \text{ quadrants .} }$

Which of the points

$P \left(0,3\right), Q \left(1,0\right),R \left(0,-1\right),S \left(-5,0\right),T \left(1,2\right)$ do not lie on the x - axis ?

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P and R only
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Q and S only
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P,R and T
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Q,S and T

Explanation

We know that a point on the a-axis has always its ordinate equal to

$0$ . So, the points which do not lies the x - axis are

$P \left(0,3\right),R \left(0,-1\right) \, and\, T \left(1,2\right)$ .

Hence,

$\left(C\right)$ is the correct answer.

If y - coordinate of a point is zero, then this point always lies

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in $I$ quadrant
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in $II$ quadrant
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on x- axis
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on y - axis

Explanation

We know that if y - coordinate of a point, i.e ...., ordinate is zero, then this point always lies on x - axis.
Hence,

$\left(C\right)$ is the correct answer.

$P \left(-1,1\right), Q \left(3,-4\right), R \left(1,-1\right), S \left(-2,-3\right)$ and

$T \left(-4,4\right)$ are plotted on the graph paper, then the points in the fourth quadrant are:

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P and T
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Q and R
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Only S
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P and R

Explanation

We know that quadrant

$IV$ consists of all the points

$\left(x,y\right)$ for which x is positive and y negative, So, the points in the fourth quadrants are

$Q \left(3,-4\right) \, and \, R \left(1, -1\right)$ .

Hence,

$\left(B\right)$ is the correct answer.

Point

$\left(0, -7\right)$ lies

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On the x -axis
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in the second quadrant
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on the y-axis
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in the forth quadrant

Explanation

In Point

$\left(0,-7\right)$ co-ordinate of x - axis is zero so it lies on y - axis.
Hence,

$\left( C\right)$ is the correct answer.

$P \left(5, 1 \right), Q \left(8,0\right), R \left(0,4\right), S \left(0,5\right)$ and

$O \left(0,0 \right)$ are plotted on the graph paper, then the point

$\left(s\right)$ on the x - axis are

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P and R
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R and S
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Only Q
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Q and O

The point which lies on y - axis at a distance of

$5$ units in the negative direction of y - axis is:

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$\left(0,5\right)$
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$\left(5,0\right)$
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$\left(0,-5\right)$
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$\left(-5,0\right)$

Explanation

Given the point lies on Y-axis this shows that its x - coordinate is zero. Also, it is at a distance of

$5$ units in the negative direction of Y - axis, so its y - coordinate is negative. Hence, the required point is

$\left(0,-5\right)$ .

Hence,

$\left(A\right)$ is the correct answer.

Write whether the following statements are True or False ? Justify your answer.
The coordinates of a point whose ordinate is

$-\dfrac{1}{2}$ and abscissa is

$1$ are

$\left[-\dfrac{1}{2},1\right]$ .

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True
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False

Explanation

We know that in the coordinates of a point, the abscissa comes first and then the ordinate.

So, the coordinate of a point are

$\left[1, -\dfrac{1}{2}\right]$ and not,

$\left[-\dfrac{1}{2}, 1\right]$ . Hence, the given statement is False.

Write whether the following statements are True or False ? Justify your answer.
Points

$\left(1,-1\right)$ and

$\left(-1,1\right)$ lie in the same quadrant.

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True
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False

Explanation

Because in point

$\left(1,-1\right)$ x - coordinate is positive and y - coordinative is negative, so it lies in

$IV$ quadrant and in

$\left(-1,1\right)$ , x - coodinate is negative and y - coordinative is positive, so it lies in

$II$ quadrant, Hence the given statement is False.

Write whether the following statements are True or False ? Justify your answer.

$\left(-1,7\right)$ is a point in the

$II$ quadrant.

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True
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False

Explanation

In the

$II$ quadrant, signs of abscissa is

$-$ and ordinate is ,

$+$ respectively.

$\left(-1,7\right)$ is a point lies in the

$II$ quadrant Hence, the given statement is True.

Which of the points

$P(0, 3), Q(1, 0), R(0, 1), S(5, 0), T(1, 2)$ do not lie on the

$x$ -axis?

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$P$ and $R$ only
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$Q$ and $S$ only
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$P, R$ and $T$
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$Q, S$ and $T$

Explanation

Any point which do not lie on the

$x-$ axis has coordinates of the form

$(x,y)$ , where

$y\neq0$

From the given points,

$P(0,3),$

$y=3\neq 0$ ,

$Q(1,0),$

$y=0$ ,

$R(0,1),$

$y=1\neq 0$ ,

$S(5,0),$

$y=0$

and in

$T(1,2),$

$y=2\neq 0$ .

We can see that, the coordinates of points

$P,R$ and

$T$ have

$y\neq 0$ .

Thus,

$P,R$ and

$T$ do not lie on the

$x-$ axis.

Hence, option

$C$ is correct.

$P (1, 1), Q (-3,- 4), R(-1,- 1), S(2, 3)$ and

$T ( 4, 4)$ are plotted on the graph paper, then the point(s) in the third quadrant are:

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$P$ and $T$
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$Q$ and $R$
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Only $S$
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$P$ and $R$

Explanation

We know that in third quadrant both the coordinates i.e,

$x,y$ are negative.

Now the given points are

$P(1,1), Q(-3,-4), R(-1,-1), S(2,3)$ and

$T(4,4)$ .

Among them,

$Q$ and

$R$ have both the coordinates negative.

$\therefore$ points

$Q$ and

$R$ are in third quadrant.

The point

$(3, 5)$ lies in which quadrant in the Cartesian coordinate plane?

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first quadrant
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second quadrant
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third quadrant
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fourth quadrant

Explanation

Since, the

$x$ -coordinate and the

$y$ -coordinate are both positive, the point

$(3,5)$ lies in the first quadrant of the Cartesian plane.

Therefore, option

$A$ is correct.

The point

$(0, 7)$ lies:

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On the $x$ -axis
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In the second quadrant
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On the $y$ -axis
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In the fourth quadrant

The points whose abscissa and ordinate have different signs will lie in:

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$I$ and $II$ quadrants
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$II$ and $III$ quadrants
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$I$ and $III$ quadrants
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$II$ and $IV$ quadrants

Explanation

A coordinate is an ordered pair of numbers in which the first number is the abscissa i.e. the measurement along the

$X$ axis and the second number is the ordinate i.e, the measurement along the

$Y$ axis.

The signs of the coordinates in the first quadrant is

$(+,+)$ ,

the second quadrant is

$(-,+)$ ,

the third quadrant is

$(-,-)$ ,

fourth quadrant is

$(+,-)$ .

So, the points whose abscissa and ordinate have different signs are

$2^{nd}$ and

$4^{th}$ quadrants.

State whether the following statement is True or False.

Point

$(3,0)$ lies in the first quadrant.

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True
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False

Abscissa of a point is positive in

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$I$ and $II$ quadrants
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$I$ and $IV$ quadrants
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$I$ quadrant only
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$II$ quadrant only

Explanation

${\textbf{Step -1: The signs of the quadrants are as follows:}}$

${\text{As we know that, }}$

${\text{Coordinate is an ordered pair of number in which the first number is the abscissa}}$

${\text{i.e}}{\text{. the measurement along the X - axis}}{\text{.}}$

${\text{So, from the above diagram we can observe that abscissa is positive in }}$ ${1^{{\text{st}}}}$ ${\text{and}}$ ${{\text{4}}^{{\text{th}}}}$ ${\text{quadrants}}{\text{.}}$

${\textbf{Hence, option B is the correct answer. }}$

Signs of the abscissa and ordinate of a point in the second quadrant are respectively:

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$+, +$
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$-,-$
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$- , +$
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$+,-$

Explanation

$\textbf{Step -1: Drawing coordinate plane.}$

$\textbf{Step -2: Finding the signs in second quadrant.}$

$\text{As in the figure, we can clearly see that the second quadrant lies between the postive }y\text{-axis }$

$\text{and the negative }x\text{-axis.}$

$\text{So, in the quadrant, abscissa is negative and ordinate is positive, i.e., }(-,+)$

$\textbf{Hence, The correct option is C.}$

State whether the given statement is True or False,

Points

$(1, 1)$ and

$(1, -1)$ lie in the same quadrant.

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True
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False

Explanation

The coordinate of a point P having abscissa x and ordinate y may be P(+x,+y) in the

${ I }^{ st }$ quadrant, P(-x,+y) in the

${ II }^{ nd }$ quadrant, P(-x,-y) in the

${ III }^{ rd }$ quadrant, P(+x,-y) in the

${IV}^{ th }$ quadrant.

So, the point

$(1,1)$ will lie in the

${ I }^{ st }$ quadrant.

The point

$(-1,1)$ will lie in the

${II}^{nd}$ quadrant.

$\therefore$

The statement that points

$(1,1)$ &

$(-1,1)$ lie in the same quadrant is False.

Ans- Option B.

In which quadrant or on which axis each of the following points lie?

$(- 3, 5), (4, -1), (2, 0), (2, 2), ( -3, -6)$

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$IV, II, x$ -axis $, I, III$
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$II, IV, x$ -axis $, I, III$
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$IV, III, I, I, III$
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$II, IV, y$ -axis $, I, III$

Explanation

$Ans-\quad P\quad lies\quad in\quad the\quad II\quad quadrant.\\ \quad \quad \quad \quad Q\quad lies\quad in\quad the\quad IV\quad quadrant.\quad \\ \quad \quad \quad \quad R\quad lies\quad on\quad the\quad X-axis.\\ \quad \quad \quad \quad S\quad lies\quad in\quad the\quad I\quad quadrant.\quad \\ \quad \quad \quad \quad T\quad lies\quad in\quad the\quad III\quad quadrant.\\ \\ \\ \\$

From the given figure, write the points whose abscissa is

$0$ .

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$I, O$ and $G$
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$A, L$ and $O$
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$A, I$ and $O$
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$L, K ,O$ and $M$

Explanation

The abscissa of the points, which lie on the

$y$ -axis are

$0$ .

Here, from the given graph, the points

$A,O$ and

$L$ lies on

$y$ -axis and have coordinates

$A(0,3), L(0,-4)$ and

$O(0,0)$ , and their abscissae are

$0$ .

Therefore, the points

$A,O$ and

$L$ lie on

$y$ -axis and have abscissa

$0$ .

Therefore, option

$B$ is correct.

The diagram shows the four quadrants P, Q R and S on a Cartesian plane.
Which of the following points lie in quadrant S?
I (-1, 2)
II (-1, -2)
III (1, -2)
IV (2,-1)

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I and II only
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I and IV only
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II and III only
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III and IV only

Students of a school are standing in rows and columns in their playground for a drill practice. A, B, C and D are the positions of four students as shown in figure 7.Is it possible to place Jaspal in the drill in such a way that he is equidistant from each of the four students A, B, C and D? If so, what should be his position?

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$(7, 5)$
0%
$(5, 7)$
0%
$(4, 6)$
0%
$(6, 4)$

Explanation

$Given\quad that\quad ABCD\quad is\quad a\quad square\quad with\quad A\left( { x }_{ 1 },y_{ 1 } \right) =\left( 3,5 \right) ,\quad B\left( { x }_{ 2 },y_{ 2 } \right) =\left( 7,8 \right) \\ C\left( { x }_{ 3 },y_{ 3 } \right) =\left( 11,5 \right) \quad and\quad D\left( { x }_{ 4 },y_{ 4 } \right) =\left( 7,2 \right) .\\ \therefore \quad The\quad position\quad of\quad Jaspal\quad will\quad be\quad the\quad mid\quad point\quad M(x,y)\\ between\quad AC\quad or\quad BD.\quad (AC=BD\quad \because \quad ABCD\quad is\quad a\quad square).\\ By\quad the\quad section\quad formula\quad for\quad the\quad mid\quad point\quad \\ M(x,y)=\left( \frac { { x }_{ 1 }+{ x }_{ 3 } }{ 2 } ,\frac { { y }_{ 1 }+{ y }_{ 3 } }{ 2 } \right) \quad or\quad M(x,y)=\left( \frac { { x }_{ 2 }+{ x }_{ 4 } }{ 2 } ,\frac { { y }_{ 2 }+{ y }_{ 4 } }{ 2 } \right) .\\ \Longrightarrow M(x,y)=\left( \frac { 3+11 }{ 2 } ,\frac { 5+5 }{ 2 } \right) \quad or\quad M(x,y)=\left( \frac { 7+7 }{ 2 } ,\frac { 8+2 }{ 2 } \right) \\ \Longrightarrow M(x,y)=\left( 7,5 \right) .\\ So\quad the\quad position(co-ordinates)\quad of\quad Jaspal\quad is\quad (7,5).\\ Ans-\quad The\quad position(co-ordinates)\quad of\quad Jaspal\quad is\quad (7,5).\\$

From the figure, write the points whose ordinate is

$0$ .

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$G, I$ and $O$
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$A, L$ and $O$
0%
$A, I$ and $O$
0%
$K, L, O$ and $M$

Explanation

The ordinate of the points, which lies on the

$x$ -axis are

$0$ .

Here, from the given graph, the points

$I,O$ and

$G$ lies on

$x$ -axis and have coordinates

$I(-2,0), G(5,0)$ and

$O(0,0)$ , respectively and their ordinates are

$0$ .

Therefore, the points

$I,O$ and

$G$ lies on

$x$ -axis and have ordinate

$0$ .

Therefore, option

$A$ is correct.

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 5 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 5 - MCQExams.com

0:0:2

Practice Class 9 Maths Quiz Questions and Answers

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