CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 6 - MCQExams.com

Observing the graph, both the points $$C$$ and $$E$$ are the points which have $$y$$ - coordinate $$=3.$$

As the $$x$$-coordinate of $$C$$ is $$-4$$, $$C=(-4, 3)$$ .
As the $$x$$-coordinate of $$E$$ is  $$6$$, $$E=(6, 3)$$.

Hence, the ccordinates $$C=(-4, 3)$$ and $$E=(6, 3)$$ have ordinate equal to $$3.$$

Therefore, options $$A$$ and $$B$$ are correct.

Given, the point $$(0,-6)$$.
 any point whose $$x$$-coordinate is $$0$$ and $$y$$-coordinate is non-zero will lie on the $$y$$-axis.
Here, $$x=0$$ and $$y=-6$$.Clearly, the point lies on the negative $$y$$-axis.
Hence, option $$D$$ is correct.

The required point is $$Q$$.

Here, the point lies on the $$IV$$th quadrant.

The point is at a distance of $$3$$ units right of the $$y$$-axis.

So, its abscissa will be $$3$$.

Also, the point is at a distance of $$2$$ unit below the $$x$$-axis.

So, its ordinate will be $$-2$$.

Hence, the co-ordinates of the required point are $$Q(3,-2)$$.

Therefore, option $$B$$ is correct.

Since the abscissa or the $$x$$-coordinate is $$+5$$, we check the points which lies in the first or fourth quadrant with $$x$$ -coordinate $$=5$$.

Observing the graph points $$B, H$$ and $$G$$ are the points which have $$x$$ -coordinate $$= 5$$.

As the y-coordinate of $$B$$ is $$0$$, $$B=(5, 0)$$
As the y-coordinate of $$H$$ is $$5$$, $$H= (5, 5) $$
As the y-coordinate of $$G$$ is $$-3$$, $$G= (5, -3)$$

Hence, the answer is $$B= (5, 0)$$, $$H= (5, 5)$$ and $$ G= (5, -3)$$.

Therefore, options $$A, C$$ and $$D$$ are correct.

The required point is $$P$$.

Here, the point lies on the $$I$$st quadrant.

The point is at a distance of $$2$$ units right of the $$y$$-axis.

So, its abscissa will be $$2$$.

Also, the point is at a distance of $$1$$ unit above the $$x$$-axis.

So, its ordinate will be $$1$$.
Hence, the co-ordinates of the required point are $$P(2,1)$$.

Therefore, option $$D$$ is correct.

Consider point is $$P$$.

Here, the ordinate is $$0$$ or $$y = 0$$.

Also, the point is at a distance of $$2$$ units right of the $$y$$-axis.

So, its abscissa will be $$+2$$.

Therefore, the point lies on the $$x$$-axis.

Hence, the co-ordinates of the required point are $$P(2,0)$$.

Consider point is $$Q$$.

Here, the abscissa is $$0$$ or $$x = 0$$.

Also, the point is at a distance of $$3$$ units above the $$x$$-axis

So, its ordinate will be $$+3$$.

Therefore, the point lies on the $$y$$-axis.

Hence, the co-ordinates of the required point are $$Q(0,3)$$.

Consider point is $$R$$.

Here, the point is at a distance of $$2$$ units left of the $$y$$-axis.

So, its abscissa will be $$-2$$.

Also, the point is at a distance of $$1$$ unit above the $$x$$-axis.

So, its ordinate will be $$1$$.

Therefore, the point lies in the $$\text{II}^{nd}$$ quadrant.

Hence, the co-ordinates of the required point are $$R(-2,1)$$.

Consider point is $$S$$.

Here, the point is at a distance of $$3$$ units left of the $$y$$-axis.

So, its abscissa will be $$-3$$.

Also, the point is at a distance of $$2$$ unit below the $$x$$-axis.

So, its ordinate will be $$-2$$.

Therefore, the point lies on the $$\text{III}^{rd}$$ quadrant.

Hence, the co-ordinates of the required point are $$S(-3,-2)$$.

Therefore, the only point that lies on the $$x$$-axis is $$P(2,0)$$.

Hence, option $$A$$ is correct.

The required point is $$S$$.

Here, the point lies on the $$III$$rd quadrant.

The point is at a distance of $$2$$ unit left of the $$y$$-axis.

So, its abscissa will be $$-2$$.

Also, the point is at a distance of $$2$$ unit below the $$x$$-axis.

So, its ordinate will be $$-2$$.

Hence, the co-ordinates of the required point are $$S(-2,-2)$$.

Therefore, option $$A$$ is correct.

The required point is $$I$$.

Here, the point is at a distance of $$3$$ units right of the $$y$$-axis $$\implies x=3$$.

Also, the point is at a distance of $$4$$ unit below the $$x$$-axis$$\implies y=-4$$.

Therefore, the co-ordinates of the required point are $$I(3,-4)$$.

Hence, option $$B$$ is correct.

The required point is $$R$$.

Here, the point lies on the $$II$$nd quadrant.

The point is at a distance of $$1$$ unit left of the $$y$$-axis.

So, its abscissa will be $$-1$$.

Also, the point is at a distance of $$1$$ unit above the $$x$$-axis.

So, its ordinate will be $$1$$.

Hence, the co-ordinates of the required point are $$R(-1,1)$$.

Therefore, option $$C$$ is correct.