MCQ Questions for Class 9 Maths Coordinate Geometry Quiz 6

The coordinates of a point which lies on x and y axes both is (0,0)

0%
TRUE
0%
FALSE
0%
can't say
0%
none of these

In the diagram, K, L, M & N are points on a

cartesian plane.

Which of the following points lie on both the

perpendicular bisectors of KL and MN?

0%
(4, 0)
0%
(4, 4)
0%
(0, 4)
0%
(4, 0)

A Cartesian plane consists of two mutually _____ lines intersecting at their zeros.

0%
perpendicular
0%
parallel
0%
at angle of $60^o$
0%
at angle of $30^o$

0%
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
0%
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
0%
Assertion is correct but Reason is incorrect
0%
Both Assertion and Reason are incorrect

Explanation

Obviously, by using graph, we can easily locate

$(0,4)$ on the

$y$ -axis,

as any point on the

$y$ -axis has the form

$(0,a)$ , where

$a$ is any number. Hence, it is correct.

Also, a point whose

$y$ -coordinate is zero lies on the

$x$ -axis,

as any point on the

$x$ -axis has the form

$(a,0)$ , where

$a$ is any number. Hence, it is correct.

But clearly, the reason is not the correct explanation for the assertion.

Therefore, option

$B$ is correct.

The co-ordinates of the three vertices of a rectangle

$ABCD$ are given. By plotting the given points, find the co-ordinates of the fourth vertex:

$B(10,4), C(0,4)$ and

$D(0,-2)$

0%
$(-10, 2)$
0%
$(-10,-2)$
0%
$(10,2)$
0%
$(10,-2)$

Explanation

The given co-ordinates of the vertices of the rectangle

$ABCD$ are

$B(10,4),\ C(0,4),\ D(0,-2)$ .

We need to plot

$A$ on the graph.

Since,

$ABCD$ is rectangle,

$\therefore$ The abscissa of

$A$ will be same as that of

$B$ and ordinate of

$A$ will be same as that of

$D$ .

$\therefore$ Co-ordinates of

$A$ are

$(10,-2)$ .

Hence, option

$D$ is correct.

Find the coordinates with ordinate as

$3$ .

0%
$C (-4, 3)$
0%
$E (6, 3)$
0%
$F (-4, -3)$
0%
$G (5, -3)$

Explanation

Since the ordinate or the

$y$ -coordinate is

$3$ , we need to look for the points lying on the horizontal line passing through

$y=3$ or the points which have

$y$ - coordinate

$=3$ .

Observing the graph, both the points $C$ and $E$ are the points which have $y$ - coordinate $=3.$

As the $x$ -coordinate of $C$ is $-4$ , $C=(-4, 3)$ .
As the $x$ -coordinate of $E$ is $6$ , $E=(6, 3)$ .

Hence, the ccordinates $C=(-4, 3)$ and $E=(6, 3)$ have ordinate equal to $3.$

Therefore, options $A$ and $B$ are correct.

In which of the following quadrant, the ordinate of a point is equal to its abscissa?

0%
$I$
0%
$II$
0%
$III$
0%
$IV$

Explanation

A point on the cartesian plane is of the form

$(x,y)$ . If the ordinate of the point is equal to its abscissa, then

$x = y$ .

This means, if

$x$ is positive, then

$y$ too is positive. Point =

$(+x,+y)$

Similarly, if

$x$ is negative, then

$y$ too is negative. Point =

$(-x,-y)$

Hence, the point lies lies either in the first quadrant or in the third quadrant as can be observed from the graph.

In rectangle

$OABC$ ; point

$O$ is the origin,

$OA=10$ units along

$x$ -axis and

$AB= 8$ units. Find the co-ordinates of vertices

$A, B$ and

$C$ .

0%
$A = ( 10,0 ), B =( 10, 8)$ and $C = (0, 8)$
0%
$A = ( 10,0 ), C =( 10, 8)$ and $B = (0, 8)$
0%
$B = ( 10,0 ), A=( 10, 8)$ and $C = (0, 8)$
0%
$B = ( 10,0 ), C =( 10, 8)$ and $A = (0, 8)$

Explanation

We plot the point Origin

$O$ . Now, we move

$10$ units to the right on the

$x$ -axis and mark it as point

$A(10,0)$ .

Since

$OABC$ is a rectangle,

$AB$ will be perpendicular to

$OA$ . So, we move

$8$ units upwards from

$A$ , and mark the point as

$B(10,8)$ .

Since opposite sides of the rectangle are equal ,

$OA=BC$ therefore move

$10$ units to the left parallel to

$OA$

Now we join

$OA, AB$ and

$BC$ with straight lines and complete the rectangle

$OABC$ . Hence, we obtain point

$C(0,8)$ .

Therefore, the coordinates

$A, B$ and

$C$ are

$(10,0), (10,8)$ and

$(0,8)$ , respectively.

Hence, option

$A$ is correct.

The points (-2,0), (3,0), (3,5) and (-2,5) are the vertices of a:

0%
rectangle
0%
square
0%
trapezium
0%
kite

Explanation

Let the given points be

$A = (-2, 0), B = (3, 0), C = (3, 5), D = (-2,5)$ .

Here clearly, the length of each side is equal and adjacent sides are perpendicular.

Therefore, the diagram formed by the given points is a square.

Therefore, option

$B$ is correct.

1294702_379551_ans_e70b1d8064354ea593f652103e0dc66c.bmp

See figure and complete the following statements.

The x-coordinate and y-coordinate of the point

$L$ are _______ and ______ respectively. Hence the coordinate of

$L$ are ______

0%
$-5,-4,(-5,-4)$
0%
$-5,-3,(-5,-4)$
0%
$-5,4,(-5,-4)$
0%
$5,-4,(-5,-4)$

Explanation

The point L is at a distance of

$4$ units from the

$x - axis$ and

$5$ units from the

$y - axis$ .

It lies in the III quadrant

Hence, the abscissa or the

$x-coordinate$ is

$-5$ , ordinate or the

$y-coordinate$ is

$-4$ .

The point

$L$ is

$(-5,-4)$ .

The point

$(0, -6)$ lies on:

0%
$y - axis (+ve)$
0%
$x - axis(+ve)$
0%
$x - axis (-ve)$
0%
$y - axis (-ve)$

Explanation

Given, the point $(0,-6)$ .
any point whose $x$ -coordinate is $0$ and $y$ -coordinate is non-zero will lie on the $y$ -axis.
Here, $x=0$ and $y=-6$ .Clearly, the point lies on the negative $y$ -axis.
Hence, option $D$ is correct.

In the graph, the coordinates of point

$Q$ are _____.

0%
$(3,2)$
0%
$(3,-2)$
0%
$(-3,2)$
0%
$(-2,3)$

Explanation

The required point is $Q$ .

Here, the point lies on the $IV$ th quadrant.

The point is at a distance of $3$ units right of the $y$ -axis.

So, its abscissa will be $3$ .

Also, the point is at a distance of $2$ unit below the $x$ -axis.

So, its ordinate will be $-2$ .

Hence, the co-ordinates of the required point are $Q(3,-2)$ .

Therefore, option $B$ is correct.

The point

$(2,3)$ is at a distance of _________ units from X-axis

0%
$2$ units
0%
$5$ units
0%
$3$ units
0%
None of these

Explanation

For the point

$(2,3)$ , x - coordinate

$= 2$ and y - coordinate

$= 3$ .
The point will lie

$3$ units above the x-axis and

$2$ units to the right of the y-axis.Thus the distance between the point from the x-axis is

$3$ units.

In order to give the precise seating plan of a classroom, how many elements of independent information is needed?

0%
1
0%
2
0%
3
0%
4

Find the coordinates with abscissa is 5.

0%
$B = (5, 0)$
0%
$F=(-4,-3)$
0%
$H = (5, 5)$
0%
$G = (5, -3)$

Explanation

Since the abscissa or the $x$ -coordinate is $+5$ , we check the points which lies in the first or fourth quadrant with $x$ -coordinate $=5$ .

Observing the graph points $B, H$ and $G$ are the points which have $x$ -coordinate $= 5$ .

As the y-coordinate of $B$ is $0$ , $B=(5, 0)$
As the y-coordinate of $H$ is $5$ , $H= (5, 5)$
As the y-coordinate of $G$ is $-3$ , $G= (5, -3)$

Hence, the answer is $B= (5, 0)$ , $H= (5, 5)$ and $G= (5, -3)$ .

Therefore, options $A, C$ and $D$ are correct.

In the above graph, what are coordinates of point

$P$ ?

0%
$(-1,-2)$
0%
$(-1,2)$
0%
$(1,2)$
0%
$(2,1)$

Explanation

The required point is $P$ .

Here, the point lies on the $I$ st quadrant.

The point is at a distance of $2$ units right of the $y$ -axis.

So, its abscissa will be $2$ .

Also, the point is at a distance of $1$ unit above the $x$ -axis.

So, its ordinate will be $1$ .
Hence, the co-ordinates of the required point are $P(2,1)$ .

Therefore, option $D$ is correct.

Which of the point from given figure lies on

$x$ -axis?

0%
$P$
0%
$Q$
0%
$R$
0%
$S$

Explanation

Consider point is $P$ .

Here, the ordinate is $0$ or $y = 0$ .

Also, the point is at a distance of $2$ units right of the $y$ -axis.

So, its abscissa will be $+2$ .

Therefore, the point lies on the $x$ -axis.

Hence, the co-ordinates of the required point are $P(2,0)$ .

Consider point is $Q$ .

Here, the abscissa is $0$ or $x = 0$ .

Also, the point is at a distance of $3$ units above the $x$ -axis

So, its ordinate will be $+3$ .

Therefore, the point lies on the $y$ -axis.

Hence, the co-ordinates of the required point are $Q(0,3)$ .

Consider point is $R$ .

Here, the point is at a distance of $2$ units left of the $y$ -axis.

So, its abscissa will be $-2$ .

Also, the point is at a distance of $1$ unit above the $x$ -axis.

So, its ordinate will be $1$ .

Therefore, the point lies in the $\text{II}^{nd}$ quadrant.

Hence, the co-ordinates of the required point are $R(-2,1)$ .

Consider point is $S$ .

Here, the point is at a distance of $3$ units left of the $y$ -axis.

So, its abscissa will be $-3$ .

Also, the point is at a distance of $2$ unit below the $x$ -axis.

So, its ordinate will be $-2$ .

Therefore, the point lies on the $\text{III}^{rd}$ quadrant.

Hence, the co-ordinates of the required point are $S(-3,-2)$ .

Therefore, the only point that lies on the $x$ -axis is $P(2,0)$ .

Hence, option $A$ is correct.

In the graph, the coordinates of point

$S$ are _____.

0%
$(-2,-2)$
0%
$(-2,0)$
0%
$(2,-2)$
0%
$(2,2)$

Explanation

The required point is $S$ .

Here, the point lies on the $III$ rd quadrant.

The point is at a distance of $2$ unit left of the $y$ -axis.

So, its abscissa will be $-2$ .

Also, the point is at a distance of $2$ unit below the $x$ -axis.

So, its ordinate will be $-2$ .

Hence, the co-ordinates of the required point are $S(-2,-2)$ .

Therefore, option $A$ is correct.

What is the coordinate of point

$I$ ?

0%
$(3, 4)$
0%
$(3, -4)$
0%
$(4, 3)$
0%
$(-4, 3)$

Explanation

The required point is $I$ .

Here, the point is at a distance of $3$ units right of the $y$ -axis $\implies x=3$ .

Also, the point is at a distance of $4$ unit below the $x$ -axis $\implies y=-4$ .

Therefore, the co-ordinates of the required point are $I(3,-4)$ .

Hence, option $B$ is correct.

In the graph, the coordinates of point

$R$ are _____.

0%
$(1,1)$
0%
$(-1,-1)$
0%
$(-1,1)$
0%
$(1,-1)$

Explanation

The required point is $R$ .

Here, the point lies on the $II$ nd quadrant.

The point is at a distance of $1$ unit left of the $y$ -axis.

So, its abscissa will be $-1$ .

Also, the point is at a distance of $1$ unit above the $x$ -axis.

So, its ordinate will be $1$ .

Hence, the co-ordinates of the required point are $R(-1,1)$ .

Therefore, option $C$ is correct.

The points

$(-3, 2)$ and

$(2, -3)$ lie in the

0%
same quadrant
0%
$II$ and $III$ quadrant respectively
0%
$II$ and $IV$ quadrant respectively
0%
$IV$ and $II$ quadrants respectively

Explanation

Point: $(-3,2)$

$x$ co-ordinate:

$-$ ve

$y$ co-ordinate:

$+$ ve

So, this point lies in the

$II$ quadrant.

Point: $(2,-3)$

$x$ co-ordinate:

$+$ ve

$y$ co-ordinate:

$-$ ve

So, this point lies in the

$IV$ quadrant.

So, option

$C$ is correct.

Which point lies on the

$x$ -axis?

0%
$(0, 3)$
0%
$(-3, 0)$
0%
$(-5, -1)$
0%
$(4, -3)$

Explanation

We know, any point which lies on the

$x$ -axis will be of the form

$(x,0)$ , where

$x$ is any real number.

Here, only

$(-3,0)$ is of the form

$(x,0)$ , where

$x=-3$ .

Therefore, option

$B$ is correct.

Points

$(10, -9), (3, -2), (5, -7), (-3, -4)$

0%
lie in $II$ quadrant
0%
lie in $III$ quadrant
0%
lie in $IV$ quadrant
0%
don't lie in the same quadrant

The diagram shows the four quadrants P, Q, R and S on a Cartesian plane.
Which of the following points lie in quadrant S?
I (-1,2) II (-1,-2)
III (1,-2) IV (2,-1)

0%
I and II only
0%
I and IV only
0%
II and III only
0%
III and IV only

In order to get the precise position of a rook in a chessboard how many independent elements of information is needed?

0%
1
0%
3
0%
2
0%
none of these

If Rahul is sitting in the 6th column and 4th row, then the seating plan point to denote his position would be P(6,5)

0%
True
0%
False

In which quadrants do the given points lie.

(A)(4,-2)

(b)(-3,7)

(c)(-1,-2)

(D)(3,6)

0%
4,2,3,1
0%
3,2,1,4
0%
2,1,3,4
0%
4,1,2,3

The point

$\left( 3,4 \right)$ is at a distance of _________ from

$y$ -axis.

0%
$2$ units
0%
$3$ units
0%
$5$ units
0%
$1$ unit

Explanation

We know, in the $xy$ -plane, any point is of the form $(x,y)$ , where $x,y$ can be any non-zero number.

Here, the $x$ -coordinate or the abscissa is the perpendicular distance of the point from the $y$ -axis.

Also, the $y$ -coordinate or the ordinate is the perpendicular distance of the point from the $x$ -axis.

Here, the point is $(3,4)$ and the abscissa is $3$ .

Hence, the given point is at a distance of $3$ units from $y$ -axis.

Therefore, option $B$ is correct.

1158414_509250_ans_089b79f2885a40409472f1c19aea283e.png

Find the points which lie in the II quadrant

0%
$(-4, 3)$
0%
$(4, -8)$
0%
$(9, -5.5)$
0%
$\left (\dfrac {-9}{2}, 5.5\right )$

Explanation

The point which lies in II Quadrant

$=(-4,3)$

where

$x$ will be negative and

$y$ positive

Identify the true statement.

0%
The $X$ -axis is a vertical line
0%
The $Y$ -axis is a horizontal line
0%
The scale on both the axes must be the same in a Cartesian plane
0%
The point of intersection between the $X$ -axis and $Y$ -axis is called the origin

Explanation

The point of intersection between the X-axis and Y-axis is called the origin

$(0,0)$ .

The X-axis is the horizontal line and Y-axis is the vertical line.

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 6 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Coordinate Geometry Quiz 6 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

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