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CBSE Questions for Class 9 Maths Statistics Quiz 1 - MCQExams.com
CBSE
Class 9 Maths
Statistics
Quiz 1
If x is the average(arithmetic mean) of $$5$$ consecutive odd integers, what is the median of integers?
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0%
$$0$$
0%
$$1$$
0%
$$x-2$$
0%
x
If x and y are both prime numbers such that x < y < 50 , then the maximum possible range of the data 4,6,8, x,y,16 is
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0%
44
0%
45
0%
48
0%
47
Upper limit of class interval $$75 - 85$$ is:
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0%
$$10$$
0%
$$-10$$
0%
$$75$$
0%
$$85$$
Explanation
The upper value of a class interval is called the upper limit of the class.
Hence, 75 is the lower limit, 85 is the upper limit
Which two class has same frequency ?
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$$0-10$$ & $$10-20$$
0%
$$10-20$$ & $$40-50$$
0%
both
0%
none of this
Which class has lowest frequency ?
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0%
$$0-10$$
0%
$$10-20$$
0%
$$20-30$$
0%
$$30-40$$
Explanation
Class
0
−
10
0−10
has lowest frequency i.e. $$1$$.
The difference between upper and lower limit is called
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0%
group
0%
class marks
0%
class size
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class internal
Explanation
Class size = Upper Limit- Lower limit
The class mark of $$ 95-100$$ is
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0%
$$100$$
0%
$$97.5$$
0%
$$95$$
0%
$$95.5$$
Explanation
Class mark of a given interval is given by the following formula:
Class-mark $$=\dfrac{\mathrm{Lower class}+\mathrm{Upper class}}{2}$$ $$=\dfrac{(95+100)}{2} = 97.5$$
In the class interval $$30-40$$, $$30$$ is
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0%
Frequency
0%
Range
0%
Upper limit
0%
Lower limit
Explanation
$$30$$-lower limit,
$$40$$-upper limit
Data available in unorganized form is called
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0%
out comes
0%
raw data
0%
class
0%
frequency
Explanation
Data available in
unorganized
form is called raw data
Size of the class $$180 - 195$$ is
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0%
$$180$$
0%
$$195$$
0%
$$15$$
0%
$$-15$$
Explanation
Size of class $$= 195 - 180 = 15$$
In the class interval $$35-46$$, the lower limit is _____
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0%
$$35$$
0%
$$38$$
0%
$$40$$
0%
$$43$$
Explanation
For the class interval, $$ 35 - 46$$
Lower limit $$= 35$$
Upper limit $$= 46$$
The mid-value of $$20-30$$ is _____
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0%
$$23$$
0%
$$22$$
0%
$$25$$
0%
$$26$$
Explanation
Mid value $$= \dfrac{\text{Lower Limit} + \text{Upper limit}}{2}$$
Mid Value $$= \dfrac{20 + 30}{2}$$
Mid Value $$= 25$$
The mean of $$x, y, z$$ is $$y$$, then $$x+z =$$
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0%
$$y$$
0%
$$2y$$
0%
$$3y$$
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$$zy$$
Explanation
The question tells us that the mean of $$x, y$$ and $$z$$ is $$y$$.
i.e. $$ \dfrac {x+y+z}{3} =y $$
i.e. $$x+z=3y-y$$
$$\rightarrow x+z=2y$$
Consider the data : $$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2.$$ The frequency of
$$2$$ is ..............
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0%
$$3$$
0%
$$4$$
0%
$$5$$
0%
$$6$$
Explanation
In the data series: $$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2$$
$$2$$ occurs $$5$$ times, hence its frequency is $$5$$
The mid-point of a class intervals is called:
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class interval
0%
class mark
0%
class limit
0%
upper limit
Explanation
Class mark is defined as the mean of the lower limit and upper limit.
Hence, the mid point of a class interval is called the class mark.
The formula $$\dfrac{Upper\ class\ limit + Lower\ class\ limit }{2}$$ is known as
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0%
Class mark
0%
Class interval
0%
Upper limit
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Lower limit
Explanation
True. Class Mark is given by $$\dfrac{Upper class limit + Lower class limit }{2}$$
A class interval of a data has $$15$$ as the lower limit and $$25$$ as the size then the class mark is :
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0%
$$26.5$$
0%
$$27$$
0%
$$27.5$$
0%
None of these
Explanation
Given,
Lower limit $$= 15$$
Size of class interval $$= 25$$
Upper limit $$= \text{lower limit }+ \text{ size} = 15 + 25$$ = $$40$$
Class mark is calculated from mean of lower and upper limit.
Class mark $$ =\dfrac{ \text{lower limit }+ \text{upper limit }}{2}$$
$$= \dfrac{15 + 40}{2}$$
$$=27.5$$
$$0-10, 10-20, 20-30 ...$$ so on are the classes, the lower boundary of the class $$20-30$$ is _____
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$$20$$
0%
$$21$$
0%
$$18$$
0%
$$22$$
Explanation
Lower boundary means the lower limit of the class interval.
The lower limit of $$20 - 30$$ is $$20$$.
Which one of the following groups has different class size from others?
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$$120 - 125$$
0%
$$243 - 249$$
0%
$$141.5 - 146.5$$
0%
$$315.5 - 320.5$$
Explanation
Class size $$=$$ Upper limit $$-$$ lower limit
All other classes have a class size $$= 5$$ except, $$243-249$$ which has a size of $$6$$
Lower class limit of $$15 -18$$ is _____
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0%
$$15$$
0%
$$18$$
0%
$$15$$ or $$18$$
0%
None of these
Explanation
We need to find lower class limit of $$15-18$$.
Thus, $$15$$ is lesser in $$(15-18) $$, so answer is $$15$$.
The number of times a particular item occurs in a class interval is called its:
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0%
mean
0%
frequency
0%
cumulative frequency
0%
none of these
Explanation
The number of times a particular item is occurs in a class interval is called its frequency.
For, example the data set is $$1,2,3,3,5,6,12,14,23,12,22,16,18$$. In the data set the frequency of the class interval $$10-15$$ is $$3$$ i.e., the values in the class interval are $$12,14,12$$
In the class interval $$35 - 46$$, the lower limit is _____
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0%
$$35$$
0%
$$46$$
0%
Can't determine
0%
None of these
Explanation
For the class interval $$35 - 46$$, the lower limit is $$35$$ and upper limit is $$46$$
In an examination, $$10$$ students scored the following marks in Mathematics: $$35, 19, 28, 32, 63, 02, 47, 31, 13, 98$$. Its range is
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$$2$$
0%
$$96$$
0%
$$98$$
0%
$$50$$
Explanation
Range $$=$$ Maximum value of the variable $$-$$ Minimum value of the variable
$$= 98 - 2 = 96$$
The mean of $$x + 3, x + 5, x + 7, x + 9$$ and $$x + 11$$ is
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0%
$$2x+7$$
0%
$$x+8$$
0%
$$x+7$$
0%
None of these
Explanation
The observations are : $$x+3,x+5,x+7,x+9, x+11$$
Mean = $$\dfrac{sum}{number \quad of \quad observations}$$ = $$\dfrac{x+3,x+5,x+7,x+9, x+11}{5}$$ = $$\dfrac{5x + 35}{5} = x + 7$$
What is the difference of frequencies of the intervals 30-40 and 40-50 ?
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$$5$$
0%
$$20$$
0%
$$15$$
0%
$$25$$
Explanation
$$\Rightarrow$$ In given histogram we can see, frequencies of the class intervals $$30-40$$ and $$40-50$$ are $$25$$ and $$10$$.
$$\Rightarrow$$ Difference of frequencies of the intervals $$30-40$$ and $$40-50$$ $$=25-10=15$$
The range of the data $$7, 13, 6, 25, 18, 20 , 16 $$ is _____
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0%
$$13$$
0%
$$19$$
0%
$$20$$
0%
$$25$$
Explanation
The data is: $$7,13,6,25,18,20,16$$
Lowest value $$= 6$$
highest value $$= 25$$
Range $$=$$ Highest Value $$-$$ Lowest value $$= 25 - 6 = 19$$
Construct a frequency distribution table for the data, taking class-intervals 4-6, 6-8, ............., 14-16.
11.5
4.5
7.4
9.8
4.6
14.2
6.6
15.5
6.3
6
5.3
8.25
6.4
15.3
4.3
14.4
7.8
8.3
8.4
6.5
8.9
11.7
4.7
12.2
9.2
12.5
15.2
5.8
10.8
9.9
9.4
7.7
10.5
15.8
8.9
10.5
12.7
8.8
10.1
5.5
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C.I.
Tally Marks.
Frequency
4-6
6-8
8-10
10-12
12-14
14-16
$${||||}\! \! \! \! \! \! {\diagdown}\: ||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: {||||}\! \! \! \! \! \! {\diagdown}$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
|||
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
7
8
10
6
3
6
0%
C.I.
Tally Marks.
Frequency
4-6
6-8
8-10
10-12
12-14
14-16
$${||||}\! \! \! \! \! \! {\diagdown}\: ||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: {||||}\! \! \! \! \! \! {\diagdown}$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
|||
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
7
10
8
6
3
6
0%
C.I.
Tally Marks.
Frequency
4-6
6-8
8-10
10-12
12-14
14-16
$${||||}\! \! \! \! \! \! {\diagdown}\: ||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: {||||}\! \! \! \! \! \! {\diagdown}$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
|||
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
6
8
10
8
3
3
0%
None of these
Explanation
Crete class interval in $$4 - 6$$, $$6 - 8$$ and so on and count the number of terms in between these intervals:
C.I.
Tally Marks.
Frequency
4-6
6-8
8-10
10-12
12-14
14-16
$${||||}\! \! \! \! \! \! {\diagdown}\: ||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |||$$
$${||||}\! \! \! \! \! \! {\diagdown}\: {||||}\! \! \! \! \! \! {\diagdown}$$
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
|||
$${||||}\! \! \! \! \! \! {\diagdown}\: |$$
7
8
10
6
3
6
The difference between the greatest and the least value of the observations is known as
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0%
M.D.
0%
S.D.
0%
Range
0%
Variance
Explanation
The difference between the greatest and the least value of the observations is defined as $$Range$$.
How many articles have cost Rs. $$50$$ ?
Cost (in Rs.) :
$$10 - 20$$
$$20-30$$
$$30-40$$
$$40-50$$
$$50-60$$
$$60-70$$
Frequency :
$$22$$
$$18$$
$$35$$
$$115$$
$$38$$
$$22$$
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0%
$$22$$
0%
$$38$$
0%
$$35$$
0%
$$115$$
Explanation
The frequency distribution table is -
Cost (in Rs.) Class Interval
No. of articles(freq)
$$10$$ to $$20$$
$$22$$
$$20$$ to $$30$$
$$18$$
$$30$$ to $$40$$
$$35$$
$$40$$ to $$50$$
$$115$$
$$50$$ to $$60$$
$$38$$
$$60$$ to $$70$$
$$22$$
The articles which cost Rs.$$50 = 38$$
Class mark of a class is obtained by using
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0%
Upper limit
0%
$$\dfrac {1}{2}$$ [Upper limit - Lower limit]
0%
$$\dfrac {1}{2}$$ [Upper limit + lower limit]
0%
$$\dfrac {1}{2}$$ [Upper limit + Lower limit] $$-1$$
Explanation
Class mark is the mean of the upper limit and lower limit of the class.
i.e. Class Mark $$=\dfrac {1}{2}$$ [upper limit + lower limit]
Hence, option C is correct.
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