MCQ Questions for Class 9 Maths Statistics Quiz 9

If the two observations are

$10$ and

$0$ , their arithmetic mean is _______.

0%
$10$
0%
$0$
0%
$5$
0%
none of the above

Explanation

Arithmetic mean refers to the average amount in a given group of data. In this measure of central tendency, all the data are added up and then divided by the number of figures in the data in order to ascertain the mean.

Therefore,

Arithmetic mean

$= \dfrac{(10+0)}{2}$

$= \dfrac{10}{2}$

$= 5$

Consider the following observation relating to marks obtained by

$10$ students in CS Foundation Exam:

$201, 202, 207, 222, 276, 201, 246, 212, 285, 312$ .
Arithmetic mean

$=$ ?

0%
$206$
0%
$237.3$
0%
$217.2$
0%
$216.1$

Explanation

Mean refers to the average amount in a given group of data. In this measure of central tendency, all the data are added up and then divided by the number of figures in the data in order to ascertain the mean.

Mean

$\dfrac{(201+ 202+207+222+276+201+246+212+285+312}{10}$

$= 236.4$

The sum of first

$n$ natural numbers is given by the expression

$(2n^{2}+3n)$ . The mean of the given numbers is

0%
$\left(\dfrac{2}{n}+3\right)$
0%
$\left(2+\dfrac{3}{n}\right)$
0%
$(2+3n)$
0%
$(2n+3)$

In a school marks obtained by

$10$ students in mathematics test as given below:

$18, 12, 36, 24, 40, 60, 23, 09, 70, 62$
Find Range of this data :

0%
$23$
0%
$61$
0%
$09$
0%
$70$

Explanation

$Formula\,used$

$Range=highest\,value-\,lowest\,value$

$Given$

$marks\text{ obtained by 10 students as }$

$\text{18,12,32,24,40,60,23,09,70,62}$

$\text{Arrange the marks in increasing order as}$

$09,12,18,23,24,32,40,60,62,70$

$Range=70-09=61$

The mean of first ten prime numbers is

0%
$12$
0%
$12.9$
0%
$13$
0%
$14$

Explanation

First 10 prime numbers are

$2,3,5,7,11,13,17,19,23,29$

Formula used:

$Arithmetic\ mean= \dfrac{Sum\ of\ given\ numbers}{Total\ numbers}$

Apply the above formula, we get

Mean=

$\frac{2+3+5+7+11+13+17+19+23+29}{10}=12.9$

To draw a histogram to represent the following frequency distribution
Class Distribution:

$5-10$

$10-15$

$15-25$

$25-45$

$45-75$
Frequency:

$6$

$12$

$10$

$8$

$15$
The adjusted frequency for the for the class

$25-45$ is

0%
$6$
0%
$5$
0%
$3$
0%
$2$

The AM of first

$5$ whole numbers is:

0%
$1$
0%
$2$
0%
$3$
0%
$5$

Explanation

The first

$5$ whole numbers are

$0, 1, 2, 3, 4$ .

We know that,

$Arithmetic\ mean= \dfrac{Sum\ of\ given\ numbers}{Total\ numbers}$

Apply the above formula, we get

$Arithmetic\ mean= \dfrac{0+1+2+3+4}{5}$

$= \dfrac{10}{5}$

$= 2$

Hence, option

$(b)$ is correct.

The bar graph as shown in above figure represents the heights (in cm) of

$50$ students of Class

$XI$ of a particular school. Study the graph and answer the following questions:
State whether true or false:
The number of a student is the class is in the range of

$160-164$ cm is

$6$ .

0%
True
0%
False

Explanation

The given bar graph represents the height (in cm) of $50$ students of class $XI$ of a particular school.

We can prepare frequency table from given bar graph as follows:

Heights(in cm) No. of students

$140-144$ $7$

$145-149$ $11$

$150-154$ $17$

$155-159$ $9$

$160-164$ $6$

$165$ -

Total number of students $=50$ .

Here, the number of students belonging to

$160-164$ is

$6$ .

That is, the given statement is true and option

$A$ is correct.

The given bar graph represents the heights (in cm) of

$50$ students of Class

$XI$ of a particular school. Study the graph and answer the following question:
State true or false:
Number of students with maximum height (in cm) in the class is

$17$ .

0%
True
0%
False

Explanation

$\textbf{Step 1: Construct the frequency table.}$

$\text{The given bar graph represents the height (in cm) of }50$ $\text{students of class }XI$ $\text{of a particular school.}$

$\text{We can prepare frequency table from given bar graph as follows:}$

$\text{Heights(in cm)}$ $\text{No. of students}$

$140-144$ $7$

$145-149$ $11$

$150-154$ $17$

$155-159$ $9$

$160-164$ $6$

$\text{Total number of students }=50$ .

$\textbf{Step 2: Find number of students with maximum height.}$

$\text{Here, the maximum range of height is}$

$160-164 cm.$

$\text{And the number of students belonging to this group is }6$ .

$\text{Therefore, there are 6 students in the class in the range of maximum height of the class.}$

$\textbf{Hence, the given statement is false and option B is correct.}$

In a bar graph, each bar (rectangle) represents only one value of the numerical data.

0%
True
0%
False

The marks (out of

$10$ ) obtained by

$28$ students in a
Mathematics test is listed below:

$8, 1, 2, 6, 5, 5, 5, 0, 1, 9, 7, 8, 0, 5, 8, 3, 0, 8, 10, 10, 3, 4, 8, 7, 8, 9, 2, 0$
The number of students who
scored marks less than

$4$ is

0%
$15$
0%
$13$
0%
$12$
0%
$10$

Explanation

We are looking for students with marks less than

$4$ i.e marks equal to

$0,1,2,3$

There, are

$10$ numbers less than

$4$ in given list.

So, the number of students who obtained marks less than

$4$

$10$ .

hence, option

$D$ is correct.

In a bar graph, bars of uniform width are drawn
vertically only.

0%
True
0%
False

In a bar graph, the gap between two consecutive bars may not be the same.

0%
True
0%
False

The following bar graph represents the data for different sizes of shoes worn by the students in a school. Read the graph and state whether true or false:
The total number of students wearing shoe sizes

$5$ and

$8$ is
the same as the number of students wearing shoe size

$6$ .

0%
True
0%
False

Explanation

The given bar graph represents different shoe size worn by the students in a school.

We can prepare frequency table from given bar graph as follows:

Shoe size No. of students

$4$ $250$

$5$ $200$

$6$ $300$

$7$ $400$

$8$ $150$

Total number of students $=1300$ .

Here, the total number of students wearing shoe size $5$ and $8$

$=$ Number of students wearing shoe size $5$ $+$ Number of students wearing shoe size $8$

$=200+150=350$ students.

Also, Number of students wearing shoe size $6=300$ students.

Since, $350\ne300$ ,

we can say that the total number of students wearing shoe size $5$ and $8$ is not same as the number of students wearing shoe size $6$ .

That is the given statement is false and option $B$ is correct.

Some integers are marked on a board. The range of these integers is

0%
31
0%
37
0%
20
0%
3

Explanation

The highest observation is

$20$

Lowest observation

$= -17$

The difference between the highest and lowest observations in a given data is called its Range.

Range = Highest – lowest

Therefore,

Range =

$20-(-17)= 20+17=37$

The range of the data :

$21,6,17,18,12,8,4,13$ is

0%
17
0%
12
0%
8
0%
15

Explanation

In given data, the highest observation is

$21$ and the lowest one is

$4$ .

Range

$=$ Highest observation

$-$ lowest observation

$=21-4=17$

Hence, option (A) is the correct answer.

The range of the data

$30,61,55,56,60,20,26,46,28,56$ is

0%
$26$
0%
$30$
0%
$41$
0%
$61$

Explanation

Range of Data= Maximum value - Minimum value

$= 61-20=41.$

The range of the data

$2,5,4,3,7,6$ would change if 2 was subtracted from each value in the data.

0%
True
0%
False

Explanation

We know that,

Range= Highest observation- Lowest observation

For original data,

Range

$=7-2=5$

After subtraction 2 from each value,

The data becomes

$0,3,2,1,5,4$

$\therefore$ Range

$= 5-0= 5$

Therefore, the range is the same for both cases.

Upper limit of class interval

$75-85$ is

0%
$10$
0%
$-10$
0%
$75$
0%
$85$

Size of the class

$150 -175$ is

0%
$150$
0%
$175$
0%
$25$
0%
$-25$

Explanation

We know that,

Size of a class

$=$ Upper limit

$-$ Lower limit

$\therefore$ Size of the class

$150-175$

$= 175-150\\=25$ .

Hence, option (C) is correct.

Listed below are the temperatures in

$^oC$ for

$10$ days.

$-6,-8,0,3,2,0,1,5,4,4$
What is the range of the data?

0%
$8$
0%
$13^0 C$
0%
$10^o C$
0%
$12^o C$

Explanation

Range of data is

$13^o C$ is
Range of data= Maximum temperature- Minimum temperature

$= 5-(-8)=5+8=13$ .

The range of the data

$3,7,1,-2,2,6,-3,-5$ would change if 8 was added to each value in the data.

0%
True
0%
False

Explanation

We know that,

Range= Highest observation- Lowest observation

For original data,

Range

$=7-(-5)= 7+5=12$

After adding 8 to each value,

The data becomes

$1,15,9,6,10,14,5,3$

$\therefore$ Range

$= 15-3=12$

Therefore, the range is the same for both cases.

The following pictorial representation of data is a histogram.

0%
True
0%
False

Explanation

We know, histogram is a graphical representation of data using bars of equal width and no gaps between them. The height of the bars gives the frequency of the particular class interval.

Then clearly, the given pictorial representation of data is a histogram.

That is, the given statement is true.

Hence, option

$A$ is correct.

Consider the following distribution:

More than or equal to 0	63
More than or equal to 10	58
More than or equal to 20	55
More than or equal to 30	51
More than or equal to 40	48
More than or equal to 50	42

The frequency of the class 30-40 is

0%
3
0%
4
0%
48
0%
51

Explanation

Marks Obtained	Number of students	Cumulative Frequency
$0-10$	$(63-58)=5$	$5$
$10-20$	$(58-55)=3$	$3$
$20-30$	$(55-51)=4$	$4$
$30-40$	$(51-48)=3$	$3$
$40-50$	$(48-42)=3$	$6$
$50<$	$42=42$	$42$

Hence, frequency in the class interval

$30-40$ is

$3$ .

Observe the adjoining bar graph, showing the number of one-day international matches played by cricket teams of different countries. Choose the correct answer from the given four options:
How many matches did South Africa play?

0%
$16$
0%
$18$
0%
$20$
0%
$24$

Explanation

The given bar graph represents the number of matches played by cricket teams of different country.

We can prepare frequency table from given bar graph as follows:

Country No. of matches

India $30$

Pakistan $24$

West Indies $20$

England $28$

South Africa $18$

Australia $32$

Sri Lanka $24$

Clearly, the number of matches played by South Africa is $18$ .

Hence, option $B$ is correct.

0%
$6$
0%
$12$
0%
$24$
0%
$30$

Explanation

The given bar graph represents the number of matches played by cricket teams of different country.

We can prepare frequency table from given bar graph as follows:

Country No. of matches

India $30$

Pakistan $24$

West Indies $20$

England $28$

South Africa $18$

Australia $32$

Sri Lanka $24$

Total number of students $=176$ .

Then, the number of more matches played by India than Pakistan

$=$ Number of matches played by India $-$ Number of matches played by Pakistan

$=30-24=6$ matches.

That is, India played $6$ matches more than Pakistan.

Hence, option $A$ is correct.

0%
India
0%
England
0%
Pakistan
0%
Australia

Explanation

The given bar graph represents the number of matches played by cricket teams of different country.

We can prepare frequency table from given bar graph as follows:

Country No. of matches

India $30$

Pakistan $24$

West Indies $20$

England $28$

South Africa $18$

Australia $32$

Sri Lanka $24$

Total number of students $=176$ .

The country that played maximum number of matches will have the highest number of matches.

Clearly, the maximum number of matches are played by Australia $(32)$ .

Hence, option $D$ is correct.

0%
$4 : 5$
0%
$5 : 4$
0%
$4 : 3$
0%
$7 : 6$

Explanation

The given bar graph represents the number of matches played by cricket teams of different country.

We can prepare frequency table from given bar graph as follows:

Country No. of matches

India $30$

Pakistan $24$

West Indies $20$

England $28$

South Africa $18$

Australia $32$

Sri Lanka $24$

Total number of students $=176$ .

Then, the ratio of number of matches played by India to the number of matches played by Sri Lanka

$=\dfrac{\text{Number of matches played by India}}{\text{Number of matches played by Sri Lanka}}$

$=\dfrac{30}{24}=\dfrac{5}{4}=5:4$ .

Hence, the required ratio is $5:4$ .

Therefore, option $B$ is correct.

What is the class-mark of class

$25-35$ ?

0%
$25$
0%
$35$
0%
$60$
0%
$30$

Explanation

Class-mark of

$25-35$

$=\dfrac {25+35}{2}=30$

Hence, option D

Marks obtain by five students in math are

$20, 25, 15, 35$ and

$30$ its range will be :

0%
$15$
0%
$20$
0%
$25$
0%
$30$

Explanation

Range = Maximum value - minimum value

$= 35 - 15 = 20$
Thus (B) is correct

CBSE Questions for Class 9 Maths Statistics Quiz 9 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Statistics Quiz 9 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

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