Explanation
$$\textbf{Step 1:}$$ $$\textbf{Relation between Electric field(E), Resistivity and Current density(J)} $$
$$ Req \ of \ AC = \dfrac{6\times6}{12} = 3$$$$ Req \ of \ AD = \dfrac{6\times6}{12} = 3$$$$ Req \ of \ AE = \dfrac{6\times6}{12} = 3$$$$ R_{AB} = \dfrac{6\times3}{9} = 2\Omega$$
Please disable the adBlock and continue. Thank you.