Explanation
Now magnification is given by:
$$M=\frac{-v}{u}$$
And mirror formula
$$\frac{1}{v}$$+$$\frac{1}{u}$$=$$\frac{1}{f}$$
Multiply by $$u$$
$$\frac{u}{v}$$+$$\frac{u}{u}$$=$$\frac{u}{f}$$
$$\frac{u}{v}$$+$$1$$=$$\frac{u}{f}$$------------$$(1)$$
We know $$M=\frac{-v}{u}$$
$$\frac{1}{M}=\frac{-u}{v}$$
$$\frac{u}{v}=\frac{-1}{M}$$
Putting in $$(1)$$
$$\frac{-1}{M}$$+$$1$$=$$\frac{u}{f}$$
$$\frac{-1}{M}$$=$$\frac{u-f}{f}$$
So
$$M=\frac{f}{f-u}$$
Now $$u=-20$$
$$M= \frac{f}{f-(-20)}$$ and real image means M is negative
$$-3= \frac{f}{f+20}$$
$$-3f-60=f$$
$$f=-15 cm$$
$$M= \frac{-15}{-15+30}$$
$$M= -1$$
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