MCQ Questions for Class 9 Maths Probability Quiz 3

A ball is drawn at random from a box containing 10 red, 30 white, 20 blue and 15 orange marbles. The probability of a ball drawn is red, white or blue .......

0%
$\dfrac 13$
0%
$\dfrac 35$
0%
$\dfrac 23$
0%
$\dfrac 45$

Explanation

Total number of balls in the box,

$n(S)=10+30+20+15=75$

Number of red balls, 10

Number of white balls, 30

Number of blue balls, 20

Hence the number of favourable outcomes for getting a red, white or blue ball is,

$n(E)=10+30+20=60$

Hence the probability of a ball drawn is red, white or blue is,

$\dfrac {n(E)}{n(S)}=\dfrac {60}{75}=\dfrac 45$

A die is thrown once. The probability of getting a number

$3$ or

$4$ is _________.

0%
$\displaystyle\frac{1}{3}$
0%
$\displaystyle\frac{2}{3}$
0%
$0$
0%
$1$

Explanation

Possible outcomes on rolling a dice are

$1,2,3,4,5,6$

Favourable outcome is to get either

$3$ or

$4$

Probability

$=$ Favourable Outcomes

$\div$ Total Outcomes

$= \dfrac{2}{6} = \dfrac{1}{3}$

When two dice are thrown simultaneously, the probability that the sum of the two numbers that turn up is less than

$11$ is:

0%
$\dfrac{11}{12}$
0%
$\dfrac{1}{12}$
0%
$\dfrac{2}{12}$
0%
$\dfrac{1}{8}$

Explanation

Given: two dice are thrown

To find: the probability that the sum of the two numbers that turn up is less than

$11$

According to the question

$n(S)=6\times 6=36$

Favourable outcomes for sum less than

$11$ is

$\{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), \\(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3),(5, 4), (5, 5), (6, 1), (6, 2), (6, 3), (6, 4)\}$

$\Rightarrow n(E)=33$

Hence, the probability of getting a total less than

$11$ is

$\dfrac {n(E)}{n(S)}=\dfrac {33}{36}=\dfrac {11}{12}$

A bag contains 100 tickets bearing numbers 1-A ticked is taken out randomly, find the probability of getting a ticket bearing a number which is the multiple of 25.

0%
$0.5$
0%
$0.04$
0%
$1.0$
0%
$0.05$

Explanation

Given that a bag contains

$100$ tickets having numbers from

$1$ to

$100$ .

To find out: The probability of getting a ticket having a number which is a multiple of

$25$ .

Hence, total number of tickets,

$n(S)=100$

Numbers from

$1$ to

$100$ which are multiples of

$25$ :

$25,\ 50,\ 75,\ 100$

Hence, total number of favourable outcomes,

$n(E)=4$ .

We know that, probability

$=\dfrac{n(E)}{n(S)}$

$\therefore \$ The probability of getting a ticket having a number which is a multiple of

$25=\dfrac {4}{100}$

$=0.04$

Hence, the required probability is

$0.04$ .

A pair of dies is thrown, find the probability of getting a total of numbers is more than

$10$ .

0%
$1/5$
0%
$1/12$
0%
$1/4$
0%
$2/7$

When two dice are thrown simultaneously the probability that the sum of the two numbers that turn up is more than

$11$ is:

0%
$\dfrac{11}{12}$
0%
$\dfrac{1}{36}$
0%
$\dfrac{2}{12}$
0%
$\dfrac{1}{8}$

Explanation

Given: two dice are thrown

To find the probability that the sum of the two numbers that turn up is more than

$11$

According to the question sample spaces

$n(S)$ are

$(6\times 6)$ i.e.

$36$

Favorable outcomes for sum more than

$11$ is

$\{(6, 6)\}$

$\Rightarrow n(E)=1$

Hence, the probability of getting a total more than

$11$ is,

$\dfrac {n(E)}{n(S)}=\dfrac {1}{36}$

A coin is tossed

$12$ times and the outcomes are observed as shown below : The chance of occurrence of head is

0%
$\dfrac {1}{2}$
0%
$\dfrac {5}{12}$
0%
$\dfrac {7}{12}$
0%
$\dfrac {5}{7}$

Explanation

Probability is given by,

$\displaystyle P(A)$

$=\dfrac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$

Coin tossed =

$12$ times.

Head occurred on tossing coin=

$5$ times.

Therefore. the chance of occurrence of head=

$\dfrac{ No.\quad of\quad times\quad head \quad appeared}{No.\quad of\quad times \quad coin\quad tossed}$

$= \dfrac{5}{12}$

Archaeological survey indicates that the odd of occurring earthquake in Greater Himalayan region due to Tehri Dam are

$5$ to

$7$ . What is the probability of earthquake in Greater Himalayan region?

0%
$\dfrac{11}{12}$
0%
$\dfrac{5}{7}$
0%
$\dfrac{7}{12}$
0%
$\dfrac{5}{12}$

Explanation

The odd of occurring earthquake

$=5$ to

$7$

$\therefore$ Total probability

$=5+7$

$=12$

Probability of earthquake

$=\dfrac{5}{12}$

CBSE Questions for Class 9 Maths Probability Quiz 3 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

CBSE Questions for Class 9 Maths Probability Quiz 3 - MCQExams.com

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Practice Class 9 Maths Quiz Questions and Answers

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