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CBSE Questions for Class 11 Engineering Maths Complex Numbers And Quadratic Equations Quiz 12 - MCQExams.com
CBSE
Class 11 Engineering Maths
Complex Numbers And Quadratic Equations
Quiz 12
If $$z=\dfrac { \sqrt { 3 } +i }{ \sqrt { 3 } -i } $$, then the fundamental amplitude of z is
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$$-\dfrac { \pi }{ 3 } $$
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$$\dfrac { \pi }{ 3 } $$
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$$\dfrac { \pi }{ 6 } $$
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None of these
What will be quadratic equation in x when the roots have arithmetic mean A and the geometric mean G?
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$${ x }^{ 2 }+2Ax+{ G }^{ 2 }=0$$
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$${ x }^{ 2 }+{ G }^{ 2 }x+A=0$$
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$${ x }^{ 2 }+2Ax+{ G }^{ 2 }=0$$
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$${ x }^{ 2 }+Gx+A=0$$
Arg $$\left\{ sin\dfrac { 8\pi }{ 5 } +i\left( 1+cos\dfrac { 8\pi }{ 5 } \right) \right\}$$ is equal to
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$$\quad -\frac { 3\pi }{ 10 } $$
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$$\quad \frac { 3\pi }{ 10 } $$
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$$\quad \frac { 4\pi }{ 5 } $$
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$$\quad \frac { 3\pi }{ 5 } $$
Argument of the complex number $$\left( \dfrac { -1-3i }{ 2+i } \right) $$
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$${ 45 }^{ 0 }$$
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$$135^{ 0 }$$
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$$225^{ 0 }$$
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$$240^{ 0 }$$
In which quadrant of the complex , the point $$\dfrac { 1+2i }{ 1-i } $$ kies?
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Fourth
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First
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Second
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Third
The amplitude of $$\sin \dfrac { \pi }{ 5 } +i\left( 1-cos\dfrac { \pi }{ 5 } \right) $$ is
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$$\dfrac { 2\pi }{ 5 } $$
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$$\dfrac { \pi }{ 15 } $$
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$$\dfrac { \pi }{ 10 } $$
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$$\dfrac { \pi }{ 5 } $$
Principal value of amplitude of (1+i) is
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$$\dfrac { \pi }{ 4 } $$
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$$\dfrac { \pi }{ 12 } $$
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$$\dfrac { 3\pi }{ 4 } $$
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$$\pi $$
Out of the following the solution of the____________quadratic equation is position and rational.
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$$6{x^2} + 5x + 6 = 0$$
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$$6{x^2} - 13x + 6 = 0$$
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$$12{x^2} + 7x - 12 = 0$$
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$$2{x^2} + x - 3 = 0$$
If $$a+b+c=0$$ then the equation $$3{ ax }^{ 2 }+2bx+c=0$$ has
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imaginary roots
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real and equal root
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real and different roots
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rational roots
The principal amplitude of ($$sin40^o + i cos40^o)^5$$ is
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$$70^o$$
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$$-110^o$$
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$$110^o$$
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$$-70^o$$
The modulus of the complex number z such that $$\left | z+3-i \right |=1 $$ and arg $$z=\pi $$ is equal to
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1
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2
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9
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4
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3
If z is a complex number of unit modules and argument $$\theta $$, then the real part of $$\dfrac { z(1-\bar { z } ) }{ z(1+z) } $$ is :
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$${ -2sin }^{ 2 }\dfrac { \theta }{ 2 } $$
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$${ 2sin }^{ 2 }\dfrac { \theta }{ 2 } $$
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$$1+cos\dfrac { \theta }{ 2 } $$
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$$1-cos\dfrac { \theta }{ 2 } $$
The amplitude of $$\dfrac {(1 + i\sqrt {3})}{\sqrt {3} + i}$$ is
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$$\dfrac {\pi}{3}$$
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$$\dfrac {\pi}{6}$$
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$$\dfrac {\pi}{4}$$
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$$\dfrac {2\pi}{3}$$
The nature of the roots of the quadratic equation $$2x^2
4x + 3 = 0$$ are
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real and distinct
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real and equal
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no real roots
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imaginary
Explanation
Given quadratic equation is,
$$2{ x }^{ 2 }+4x+3=0$$
$$\therefore a=2,b=4,c=3$$
Thus, discriminant of this equation is given by,
$$D={ b }^{ 2 }-4ac$$
$$\therefore D={ \left( 4 \right) }^{ 2 }-4\left( 2 \right) \left( 3 \right) $$
$$\therefore D=16-24$$
$$\therefore D=-8<0$$
Thus, roots of the equation are imaginary
If $${ z }_{ 1 },{ z }_{ 2 },{ z }_{ 3 },{ z }_{ 4 }$$ be the vertices of a square in Argand plane , then
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`$${ 2z }_{ 2 }=\left( 1-i \right) { z }_{ 1 }+\left( 1+i \right) { z }_{ 3 }$$
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$${ 2z }_{ 4 }=\left( 2-i \right) { z }_{ 1 }+\left( 2+i \right) { z }_{ 3 }$$
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$${ 2z }_{ 2 }=\left( 3-i \right) { z }_{ 1 }+\left( 3+i \right) { z }_{ 3 }$$
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$${ 2z }_{ 4 }=\left( 4-i \right) { z }_{ 1 }+\left( 4+i \right) { z }_{ 3 }$$
The complex numbers $${ z }_{ 1 },{ z }_{ 2 },{ z }_{ 2 }$$ satisfying $$\dfrac { { z }_{ 1 }+{ z }_{ 3 } }{ { z }_{ 2 }-{ z }_{ 3 } } =\dfrac { 1-i\sqrt { 3 } }{ 2 } $$
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If area zero
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right angled isosceles
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equilateral
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obtuse angled
If $$z(2 - 2i\sqrt {3})^{2} = i(\sqrt {3} + i)^{4}$$, then the amplitude of $$z$$ is
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$$\dfrac {\pi}{6}$$
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$$\dfrac {5\pi}{6}$$
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$$-\dfrac {\pi}{6}$$
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$$\dfrac {7\pi}{6}$$
If $$z_{1}=1+2i,z_{2}=1-3i$$ and $$z_{3}=2+4i$$ then, the points of the Argand diagram representing $$z_{1}z_{2}z_{3},2z_{1}z_{2}z_{3},-7z_{1}z_{2}z_{3}$$ are :
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Vertices of an isosceles triangle
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Collinear
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Vertices of a right angled triangle
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Vertices of a equilateral triangle
Explanation
$$\therefore z'_1=z_1z_2z_3=(1+2i)(1-3i)(2+4i)$$
$$\Rightarrow 2(1-3i+2i-6i^2)(1+2i)$$
$$\Rightarrow 2(1-i+6)(1+2i)$$ $$(\therefore i^2=-1)$$
$$\Rightarrow 2(7-i)(1+2i)\Rightarrow 2(7+14i-i-2i^2)=2(7+13i+2)=2(9+13i)$$
Therefore, $$z'_1=(18+26i),\,z'_2=(36+52i),\,z'_3=(-126-182i)$$
$$z'_1=z_1z_2z_3=18+26i$$
$$z'_2=2z_1z_2z_3=2z'_1$$
$$z'_3=-7z'_1z'_2z'_3=-7z'_1$$
$$\therefore \,z_1z_2z_3,\,2z_1z_2z_3,\,-7z'_1z'_2z'_3$$ are collinear
The roots of $$(x-41)^{49}+(x-49)^{41}+(x-2009)^{2009}=0$$ are
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all necessarily real
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non - real except one positive root
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nor - real except positive roots
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nonr real except for 3 roots of which exactly one is positive
The complex number $$z$$ satisfies $$z+|z|=2+8i$$. The value of $$|z|$$ is
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10
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13
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17
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23
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Practice Class 11 Engineering Maths Quiz Questions and Answers
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