Explanation
Calculate $$\dfrac{u^3 }{ v^4}$$
For a complex number $$z=re^{\phi i}$$ the principal value of the square root is: $$pv\: \sqrt{z}=\sqrt{r}e^{i\phi/2}$$ with argument $$-\pi < 0 \leq \pi$$
Thus the principal value of $$arg(z)$$ lies in the interval: $$(-\pi,\pi]$$.
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