Explanation
Find the distance between the points whose position vectors are given as follows
$$-2\hat i+3\hat j+5\hat k, 7\hat i-\hat k$$
Given that,
Dimensions of the hall x $$=24cm\times 8cm\times 6cm$$
Now Leght of the longest pole which can be accommodated in the hall x $$=\sqrt{{{24}^{2}}+{{8}^{2}}+{{6}^{2}}}=26cm$$
$$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$$
The coordinates are $$(-3, 6, 7)$$ and$$ (2, -1, 4)$$
$$d=\sqrt{(2-(-3))^2+((-1)-6)^2+(4-7)^2}$$
$$d=\sqrt{(5)^2+((-7)^2+(-3)^2}$$
$$d=\sqrt{25+49+9}$$
$$d=\sqrt{83}$$
$$d = 9.11$$
Please disable the adBlock and continue. Thank you.