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CBSE Questions for Class 11 Engineering Maths Permutations And Combinations Quiz 14 - MCQExams.com

What is the hundreds digits of ( 20 !-15!) ? 
  • 0
  • 1
  • 2
  • 4
  • 5
(513)+(503)+(493)+(483)+(473)+(474) is equal to (where (nr) denotes nCr
  • (521)
  • (522)
  • (523)
  • (524)
If n and r are positive integers such that r<n then nCr+nCr1 is equal to
  • 2nC2r1
  • n+1Cr
  • nCr+1
  • 2nCr
If xϵNandCx14CX1354Px22<0 then x is equal to 
  • 4,5,6,7,8,9,10
  • 3
  • 3x10
  • none of these
If  m  and  n  are positive integers more than or equal to  2,m>n,  then  (mn)!  is divisible by
  • (m!)n
  • (n!)m
  • (m+n)!
  • (mn)!
If nCr denotes the number of combinations of n things taken r at a time, then the expression + nCr1+2×nCr equals 
  • n+2Cr
  • n+2Cr+1
  • n+2Cr
  • n+2Cr+1
If 189C35+189Cx=190Cx, then x is equal to
  • 34
  • 35
  • 36
  • 37
In a village, there are 87 families of which 52 families have at most 2 children. In a rural development programme, 20 families are to be helped chosen for assistance, of which at least 18 families must have at most 2 children. In how many ways can the choice be made?
  •  52C18× 35C2+ 52C19× 35C1+ 52C20× 35C0
  •  52C18× 35C2+ 52C19× 35C1+ 52C20× 35C10
  •  52C18× 35C2+ 52C19× 35C1+ 52C2× 5C0
  •  52C18× 35C2+ 52C9× 35C10+ 52C20× 5C0
A sports team of 11 students is to be constituted, choosing at least 5 from class XI and at least 5 from class XII. If there are 20 students in each of these classes, in how many ways can the teams be constituted?
  • 2( 20C3× 20C7)
  • 2( 20C5× 20C6)
  • 2( 20C4× 20C8)
  • None of these
The number of five digit numbers in which digits decrease from left to  right, is 
  • 9C5
  • 10C5
  • 2×10C5
  • 10P5
If nCr+4nCr+1+6nCr+2+4nCr+3+nCr+4nCr+3nCr+1+3nCr+2+nCr+3=n+kr+k then the value of k is
  • 1
  • 2
  • 4
  • 5
The number of four -digit numbers strictly grater than 4321 that can be formed using the digits 0,1,2,3,4,5 (repetition of digits is allowed) is:
  • 288
  • 306
  • 360
  • 310
0:0:1


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