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CBSE Questions for Class 9 Maths Probability Quiz 3 - MCQExams.com
CBSE
Class 9 Maths
Probability
Quiz 3
A ball is drawn at random from a box containing 10 red, 30 white, 20 blue and 15 orange marbles. The probability of a ball drawn is red, white or blue .......
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0%
$$\dfrac 13$$
0%
$$\dfrac 35$$
0%
$$\dfrac 23$$
0%
$$\dfrac 45$$
Explanation
Total number of balls in the box, $$n(S)=10+30+20+15=75$$
Number of red balls, 10
Number of white balls, 30
Number of blue balls, 20
Hence the number of favourable outcomes for getting a red, white or blue ball is, $$n(E)=10+30+20=60$$
Hence the probability of a ball drawn is red, white or blue is, $$ \dfrac {n(E)}{n(S)}=\dfrac {60}{75}=\dfrac 45$$
A die is thrown once. The probability of getting a number $$3$$ or $$4$$ is _________.
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0%
$$\displaystyle\frac{1}{3}$$
0%
$$\displaystyle\frac{2}{3}$$
0%
$$0$$
0%
$$1$$
Explanation
Possible outcomes on rolling a dice are $$1,2,3,4,5,6$$
Favourable outcome is to get either $$3$$ or $$4$$
Probability $$=$$ Favourable Outcomes $$\div$$ Total Outcomes $$= \dfrac{2}{6} = \dfrac{1}{3}$$
When two dice are thrown simultaneously, the probability that the sum of the two numbers that turn up is less than $$11$$ is:
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0%
$$\dfrac{11}{12}$$
0%
$$\dfrac{1}{12}$$
0%
$$\dfrac{2}{12}$$
0%
$$\dfrac{1}{8}$$
Explanation
Given: two dice are thrown
To find: the probability that the sum of the two numbers that turn up is less than $$11$$
According to the question $$n(S)=6\times 6=36$$
Favourable outcomes for sum less than $$11$$ is $$\{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), \\(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3),(5, 4), (5, 5), (6, 1), (6, 2), (6, 3), (6, 4)\}$$
$$\Rightarrow n(E)=33$$
Hence, the probability of getting a total less than $$11$$ is $$\dfrac {n(E)}{n(S)}=\dfrac {33}{36}=\dfrac {11}{12}$$
A bag contains 100 tickets bearing numbers 1-A ticked is taken out randomly, find the probability of getting a ticket bearing a number which is the multiple of 25.
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0%
$$0.5$$
0%
$$0.04$$
0%
$$1.0$$
0%
$$0.05$$
Explanation
Given that a bag contains $$100$$ tickets having numbers from $$1$$ to $$100$$.
To find out: The probability of getting a ticket having a number which is a multiple of $$25$$.
Hence, total number of tickets, $$n(S)=100$$
Numbers from $$1$$ to $$100$$ which are multiples of $$25$$:
$$25,\ 50,\ 75,\ 100$$
Hence, total number of favourable outcomes, $$n(E)=4$$.
We know that, probability $$=\dfrac{n(E)}{n(S)}$$
$$\therefore \ $$ The probability of getting a ticket having a number which is a multiple of $$25=\dfrac {4}{100}$$
$$=0.04$$
Hence, the required probability is $$0.04$$.
A pair of dies is thrown, find the probability of getting a total of numbers is more than $$10$$.
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0%
$$1/5$$
0%
$$1/12$$
0%
$$1/4$$
0%
$$2/7$$
When two dice are thrown simultaneously the probability that the sum of the two numbers that turn up is more than $$11$$ is:
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0%
$$\dfrac{11}{12}$$
0%
$$\dfrac{1}{36}$$
0%
$$\dfrac{2}{12}$$
0%
$$\dfrac{1}{8}$$
Explanation
Given: two dice are thrown
To find the probability that the sum of the two numbers that turn up is more than $$11$$
According to the question sample spaces $$n(S)$$ are $$(6\times 6)$$ i.e. $$36$$
Favorable outcomes for sum more than $$11$$ is $$\{(6, 6)\}$$
$$\Rightarrow n(E)=1$$
Hence, the probability of getting a total more than $$11$$ is,
$$\dfrac {n(E)}{n(S)}=\dfrac {1}{36}$$
A coin is tossed $$ 12 $$ times and the outcomes are observed as shown below : The chance of occurrence of head is
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0%
$$ \dfrac {1}{2} $$
0%
$$ \dfrac {5}{12} $$
0%
$$ \dfrac {7}{12} $$
0%
$$ \dfrac {5}{7} $$
Explanation
Probability is given by,
$$\displaystyle P(A)$$$$=\dfrac{\text{no. of possible outcomes}}{\text{No. of total outcomes}}$$
Coin tossed = $$ 12 $$ times.
Head occurred on tossing coin= $$ 5 $$ times.
Therefore. the chance of occurrence of head= $$ \dfrac{ No.\quad of\quad times\quad head \quad appeared}{No.\quad of\quad times \quad coin\quad tossed} $$
$$ = \dfrac{5}{12} $$
Archaeological survey indicates that the odd of occurring earthquake in Greater Himalayan region due to Tehri Dam are $$5$$ to $$7$$. What is the probability of earthquake in Greater Himalayan region?
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0%
$$\dfrac{11}{12}$$
0%
$$\dfrac{5}{7}$$
0%
$$\dfrac{7}{12}$$
0%
$$\dfrac{5}{12}$$
Explanation
The odd of occurring earthquake $$=5$$ to $$7$$
$$\therefore$$ Total probability $$=5+7$$
$$=12$$
Probability of earthquake $$=\dfrac{5}{12}$$
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