CBSE Questions for Class 11 Engineering Maths Trigonometric Functions Quiz 17 - MCQExams.com

The general solution of the equation

t a n 3 θ = - 1

$\displaystyle tan 3\theta = -1$ is

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$\displaystyle \theta = \frac{n\pi}{3} + \frac{\pi}{4}, n \in I$
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$\displaystyle \theta = \frac{2n\pi}{3} + \frac{\pi}{4}, n \in I$
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$\displaystyle \theta = \frac{n\pi}{3} \pm \frac{\pi}{4}, n \in I$
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none of these.

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