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CBSE Questions for Class 11 Engineering Physics Gravitation Quiz 16 - MCQExams.com
CBSE
Class 11 Engineering Physics
Gravitation
Quiz 16
The work done by external agent to shift a point mass from infinity to the centre of earth is :
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0%
=
0
=
0
0%
>
0
>
0
0%
<
0
<
0
0%
<
0
<
0
Explanation
Work done by external agent is
W
=
m
(
d
V
)
W
=
m
(
d
V
)
d
V
=
d
V
=
change in potential energy.
So,
W
=
m
(
V
2
−
V
1
)
W
=
m
(
V
2
−
V
1
)
.....(i)
At infinity
V
1
=
0
V
1
=
0
On the center of earth ,
V
2
=
−
3
G
M
2
R
V
2
=
−
3
G
M
2
R
...(ii)
Putting (i) equation in equation (ii) we get,
W
=
m
−
3
G
M
2
R
W
=
m
−
3
G
M
2
R
W
=
−
3
G
M
m
2
R
W
=
−
3
G
M
m
2
R
This shows that work done cannot be zero.
Here, Work done is negative
which results in
W
<
0
W
<
0
Option (C) is correct.
A body is thrown from the surface of the earth with a speed of
√
G
M
/
R
(
R
=
√
G
M
/
R
(
R
=
radius and
M
=
M
=
mass of earth). It rises to a maximum height of
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0%
R
/
2
R
/
2
0%
R
R
0%
4
R
4
R
0%
2
R
2
R
A capillary tube is immersed vertically in water and the height of the water column is X. When this arrangement is taken into a mine of depth d, the height of the water column is Y. If R is the radius of the earth, the ratio X/Y is
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0%
1
−
d
R
1
−
d
R
0%
1
1
+
d
R
d
R
0%
R
−
d
R
+
d
R
−
d
R
+
d
0%
R
+
d
R
−
d
R
+
d
R
−
d
The escape velocity of a body on the surface of the earth is
11.2
k
m
/
s
e
c
11.2
k
m
/
s
e
c
. If the mass and radius of a planet are
4
4
and
2
2
times respectively than that of earth. The escape velocity from the planet will be :
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0%
11.2
k
m
/
s
e
c
11.2
k
m
/
s
e
c
0%
1.112
k
m
/
s
e
c
1.112
k
m
/
s
e
c
0%
15.8
k
m
/
s
e
c
15.8
k
m
/
s
e
c
0%
22.4
k
m
/
s
e
c
22.4
k
m
/
s
e
c
The gravitational force in a region is given by
→
E
=
a
y
ˆ
i
+
a
x
ˆ
j
→
E
=
a
y
^
i
+
a
x
^
j
The work done by gravitational force to shift a point mass
m
m
from
(
0
,
0
,
0
)
(
0
,
0
,
0
)
to
(
x
0
,
y
0
,
z
0
)
(
x
0
,
y
0
,
z
0
)
is :
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0%
m
a
x
0
y
0
z
0
m
a
x
0
y
0
z
0
0%
m
a
x
0
y
0
m
a
x
0
y
0
0%
−
m
a
x
0
y
0
−
m
a
x
0
y
0
0%
z
e
r
o
z
e
r
o
The gravitational field in a region is
10
N
/
k
g
(
ˆ
i
−
ˆ
j
)
10
N
/
k
g
(
^
i
−
^
j
)
. The work done
by external agent
to shift slowly a particle of mass
1
k
g
1
k
g
from point
(
1
m
,
1
m
)
(
1
m
,
1
m
)
to a point
(
2
m
,
−
2
m
)
(
2
m
,
−
2
m
)
is :
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0%
40
j
o
u
l
e
40
j
o
u
l
e
0%
−
40
j
o
u
l
e
−
40
j
o
u
l
e
0%
z
e
r
o
z
e
r
o
0%
+
10
j
o
u
l
e
+
10
j
o
u
l
e
A body is projected vertically from the surface of the earth of radius
R
R
with velocity equal to half of the escape velocity. The maximum height reached by the body is?
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0%
R
/
5
R
/
5
0%
R
/
3
R
/
3
0%
R
/
2
R
/
2
0%
R
/
4
R
/
4
Two bodies each of mass
1
k
g
1
k
g
are at a distance of
1
m
1
m
. The escape velocity of a body of mass
1
k
g
1
k
g
which is midway between them is :
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0%
8
×
10
−
5
m
/
s
8
×
10
−
5
m
/
s
0%
2.31
×
10
−
5
m
/
s
2.31
×
10
−
5
m
/
s
0%
4.2
×
10
−
5
m
/
s
4.2
×
10
−
5
m
/
s
0%
z
e
r
o
z
e
r
o
A gravitational field is present in a region. A point mass is shifted from
A
A
to
B
B
, from different paths shown in the figure. If
W
1
,
W
2
W
1
,
W
2
and
W
3
W
3
represent work done by gravitational force for respective paths, then :
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0%
W
1
=
W
2
=
W
3
W
1
=
W
2
=
W
3
0%
W
1
>
W
2
W
3
W
1
>
W
2
W
3
0%
W
1
>
W
3
>
W
2
W
1
>
W
3
>
W
2
0%
none of these
During the compression of the spring the work done by the force of gravity is
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0%
M
g
x
M
g
x
0%
(
1
2
)
k
x
2
(
1
2
)
k
x
2
0%
−
(
1
2
)
k
x
2
−
(
1
2
)
k
x
2
0%
M
g
x
+
(
1
2
)
k
x
2
M
g
x
+
(
1
2
)
k
x
2
Acceleration due to gravity 'g' for a body of mass 'm' on earth's surface is proportional to (Radius of earth= R , mass of earth= M)
Report Question
0%
G
M
/
R
2
G
M
/
R
2
0%
m
0
m
0
0%
m
M
m
M
0%
1
/
R
3
/
2
1
/
R
3
/
2
An object of mass
m
m
is located on the surface of a spherical planet of mass
M
M
and radius
R
R
. The escape speed from the planet does not depend on which of the following?
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0%
M
M
0%
m
m
0%
the density of the planet
0%
R
R
0%
the acceleration due to gravity on that planet
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