Explanation
Given,
λ=hceV where, V=potential
λ α 1V
10−10 α 1150 ...... (1)
λ α 1600 ...... (2)
Divide (2) by (1)
λ10−10=150600=14
⇒λ=0.25×10−10m =0.25 Ao
For perfect gas,
Kinetic Energy of n molecule, K.E=n(12KBT)
Where, KB is Boltzmann constant
If there is no loss of energy.
Total kinetic energy of mixture is sum of each gas kinetic energy.
ntotalK.Etotal=n1K.E1+n2K.E2+n3K.E3
(n1+n2+n3)(12KBT)=n1(12KBT1)+n2(12KBT2)+n3(12KBT3)
T=n1T1+n2T2+n3T3n1+n2+n3
From ideas gas equation
PV=nRT
PV=mMoRT
m=PVMoRT
In first event
m1=P1VMoRT1
6 gram=PVMoR×400
PVMoR=400×6 . ..... (1)
In the second event when hole is made:
m2=P2VMoRT2
m2=P2VMoR×300 =1300×2PVMoR
m2=1300×2×(400×6)=4 gram
Leak out oxygen is (6gram−4gram) = 2gram
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