Explanation
An ideal diatomic gas is heated at constant volume, the supplied being Q. The increase in rotational kinetic energy is
When $$2$$ grams of a gas $$A$$ is introduced in an evacuated flask kept at $$25 C$$; the pressure was found to be $$1atm$$ i.e.
The partial pressure of gas $$A=1atm$$.
And let moles be $$n_a=\dfrac{2}{M_{A}}$$
if $$3g$$ of another gas $$B$$ is then added to the same flask;
Partial pressure of gas $$B=1.5atm-1atm=0.5atm$$
moles of gas $$B=\dfrac{3}{M_{B}}$$
Again the temp and volume are constant therefore,
$$\dfrac{P_{1}}{n_{1}}=\dfrac{P_{2}}{n_{2}}$$
Hence, $$\dfrac{\dfrac{1}{2}}{M_{A}}$$ =$$\dfrac{\dfrac{0.5}{3}}{M_{B}}$$
$$M_{A}=\dfrac{0.5M_{B}}{3}\times2$$
$$\dfrac{M_{A}}{1}=\dfrac{M_{B}}{3}$$
or
$$\dfrac{M_{A}}{M_{B}}=\dfrac{1}{3}$$
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