Explanation
It is given that $$U={{U}_{0}}V$$
For a diatomic molecule, internal energy is given by
$$ U=\dfrac{5}{2}nRT $$
$$ {{U}_{0}}V=\dfrac{5}{2}nRT $$
Taking derivative on both sides.
$$ {{U}_{0}}\dfrac{dV}{dT}=\dfrac{5}{2}R n $$
$$ {{C}_{v}}=\dfrac{5}{2}R\,\,\,\,\,(\because \dfrac{{{U}_{0}}dU}{ndT}={{C}_{v}}) $$
Hence, molar heat capacity is $$[\dfrac{5}{2}R]$$.
The temperature of a gas is due to
When the volume of a gas is decreased at constant temperature the pressure increases because the molecules
The graph between temperature and pressure of a perfect gas is
The graph drawn between pressure and temperature at constant volume for a given mass of different molecular weights $$M_{1}$$ and $$M_{2}$$ are the straight lines as shown in the figure then
At constant pressure, density of a gas is :
Hint: Density of a substance is given by $$\rho = \dfrac{m}{V}$$ , where $$m$$is the mass of the substance and $$V$$ is its volume.
Correction Option: B
Explanation for correct option:
$$ \Rightarrow PV \alpha nRT$$
$$ \Rightarrow PV = \dfrac{m}{M} RT$$, where $$m$$ and $$M$$ are weight and molecular weight of the gas.
$$ \Rightarrow P = \dfrac{m}{V}\dfrac{{RT}}{M}$$
Here, $$\rho = \dfrac{m}{V}$$ and $$R' = \dfrac{R}{M}$$, where $$R'$$ is the specific gas constant for the gas.
$$ \Rightarrow P = \rho R'T$$
$$ \Rightarrow \rho = \dfrac{P}{{R'T}}$$
$$\therefore \rho \alpha \dfrac{1}{T}$$
Hence, at constant pressure, density of a gas is inversely proportional to absolute temperature.
Universal gas constant per molecule is called
All gasses deviate from gas laws at
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An ideal gas is that which
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