Explanation
We know that for the vehicle bankingon a curved path, $$tan\theta=\dfrac{v^{2}}{rg}$$.
Here, the vehicle moves with velocity$$v$$ and radius of curvature $$R$$ and width is b.
So, here $$\theta$$ is small (refer figure) and thus, $$sin\theta=\dfrac{h}{b}=tan\theta$$.
Now, we can equate $$\dfrac{h}{b}=\dfrac{v^{2}}{Rg}$$$$\Rightarrow h= \dfrac{bv^{2}}{Rg}$$, will be the required elevation between the outer and inner edges of the road.
A stationary ball weighing $$0.25\ kg$$ acquires a speed of $$10 \ m/s$$ when hit by a hockey stick. The impulse imparted to the ball is:
$$A\ and \ B: \left| { a }_{ tangential } \right| = g$$ which is maximum and radial acceleration is between\ maximum and minimum when string makes $${ 90 }^{ 0 }$$.
$$\Rightarrow$$ A is not correct, B is correct. C is not correct as tangential acceleration and radial acceleration can become equal multiple times in a circular motion.D is correct because radial acceleration becomes maximum at the bottom most point where tangential acceleration is zero.
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