Explanation
A body of mass $$1 kg$$ tied to one end of string is revolved in a horizontal circle of radius $$0.1 m$$ with a speed of $$3 evolution/sec$$, assuming the effect of gravity is negligible, then linear velocity, acceleration and tension in the string be :
Mass, $$m = 0.05\ kg$$ Initial velocity, $$u = 500\ m/s$$ Distance covered, $$S = 100 cm = 1\ m$$
Final velocity $$v=0$$
Now, from the equation of motion
$$ {{v}^{2}}-{{u}^{2}}=2as $$
$$ 0-{{\left( 500 \right)}^{2}}=2\times a\times 1 $$
$$ a=-125000\,m/{{s}^{2}} $$
Now, the average force exerted on the block
$$ F=ma $$
$$ F=0.05\times 125000 $$
$$ F=6.25\times {{10}^{3}} $$
$$ F=0.625\times {{10}^{4}}\,N $$
Hence, the average force is $$0.625\times {{10}^{4}}\,N$$
$$force = mass x acceleration$$
$$F = ma$$
$$F = 150/1000 x 20$$
$$F = 3N$$
$$Impulse = Force \times Time$$
$$Impulse = 3 \times 1 => 3 N s $$
Hence,
option $$A$$ is correct answer.
Given that,
Force $$F=100\,dyn$$
Mass $$m=5\,g$$
Time $$t=10\,s$$
Initial velocity $$u=0$$
Now, the acceleration is
$$ a=\dfrac{F}{m} $$
$$ a=\dfrac{100\times {{10}^{-5}}}{5\times {{10}^{-3}}} $$
$$ a=0.20\,m/{{s}^{2}} $$
Now, from equation of motion
$$ v=u+at $$
$$ v=0+0.20\times 10 $$
$$ v=2\,m/s $$
$$ v=200\,cm/s $$
Hence, the velocity produced is $$200\ cm/s$$
A 40 N block is supported by two ropes. One rope is horizontal and the other makes an angle of $${30^ \circ }$$ with the ceiling. The tension in the rope attached to the ceiling is approximately:
Impulse, $$I=\int{F(t).dt}=$$ Area of F and t graph.
Where,
$$ F=\,force $$
$$ t=\,time $$
$$I=\dfrac{1}{2}Ft=\dfrac{1}{2}\times 100\times \left( 10-1 \right)=450\,Ns$$
Hence, impulse is $$450\,Ns$$
Please disable the adBlock and continue. Thank you.