Explanation
The expression for the capillary rise in a tube is given by,
H = $$ \dfrac {2T cos \theta}{\rho gr} $$
where $$ \theta$$ is the contact angle and not the angle of tilt.
Thus, for all parameters constant,
at $$ 60^o $$
$$ l_1 = H cos 60^0 $$ = H/2
At $$ 45^o $$
$$ l_2 = H cos 45^0 $$ = $$ H/\sqrt 2 $$
Therefore the ratio of the 2 lengths is given by,
$$ l_1/l_2 = \dfrac {1}{\sqrt 2} $$
The ordinary pressure of the air surrounding us is 14.7 pounds per square inch, but the pressure can change when the wind blows or an object, like a car or airplane, accelerates.
One important principle to remember is that wherever the air pressure is higher, there will be a stronger force or push against an object. It’s also helpful to know that when an air particle speeds up, it actually “pushes” less. Imagine that fast-moving air particles are in so much of a hurry that they don’t have time to apply force. This principle is used in airplane wings to make planes fly. When a plane moves along the runway, the air above the wing speeds up more, lowering the pressure, so that the air below the wing can push the plane upward.
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