Explanation
By using Bernoulli’s principle
The velocity of the liquid coming out is given as,
v=√2gh
The mass of the liquid will be
m=ρAV
The change in momentum will be
P=mv
The force will be proportional of v2 which in turn is proportional to h
The difference in pressure is given as,
ΔP=ρgh
0.1×105=ρgh
The velocity of water flow is given as,
v=√2g×0.1×105103×g
v=√20m/s
Given , angle of contact (θ)=140°
Radius of tube (r)=1mm=10⁻³m
Surface tension (S)=0.465N/m
Density of mercury(ρ)=13.6×10³kg/m³
Height of liquid rise or fall due to surface tension (h)
=2Scosθ/rρg=2×0.465×cos140°/1×10⁻³×13.6×10³×9.8
=2×0.465×(−0.7660)/10⁻³×13.6×10³×9.8
=−5.34mm
Hence, the mercury level will depressed by 5.34mm.
A glass capillary is put in a trough containing one of these for liquids it is observed that the meniscus is convex. the liquid in the trough is Ethyl alcohol.
v1= velocity of surface of liquid
v2= velocity of liquid far om orifice
Acc. to continuity theorem.
Av1=av2⇒Av1a=v2
⇒av2A=v1
Acc. to Bernoulli's Theorem
P0+ρgh+12ρv21=P0+ρg(0)+12ρv2L
ρgh+12ρ[a2v21A2−v21]=0
v212[A2−a2A2]=gh
v1=√2gh√A2A2−a2
Answer: √2gh√A2A2−a2
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