Explanation
F∝Δl
F1∝l1−l
Where l, is the original length of the wire
F2∝l2−l
F1F2=l1−ll2−l
F1l2−F1l=F2l1−F2l
(F2−F1)l=F2l1−F1l2
l=F2l1−F1l2F2−F1
Hint: Young's Modulus is the ratio of stress and strain.
Solution:
Step1: Observe the given diagram,
Step:2 Use Young’s modulus equation
Using Young’s modulus equation we have,
Y=F×lA×Δl.....(1)
Where, Y=Young’s modulus, F=Applied force, l=Initial length, A=Square area & ΔL= Elongation.
So, we have slope, F(load)Δl(elongation)=Y×Al
Hence, slope∝A or slope∝r2
It is clear that, for thinnest wire slope is minimum i.e. wire ‘OA’ is thinnest.
Hence, option (A) is correct.
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