Explanation
By a load, when the metal wire is stretched, in the transverse length, the fractional change is proportional to the longitudinal length's fractional change.
Let the cross functional area be denoted as “$$A$$” and length is denoted as “l”. Wire's volume is shown as $$Al$$.
Let's assume that there is no lateral strain when there is an occurrence of longitudinal strain.
Volume increase can be shown as:
$$\triangle V = A \triangle l$$
$$\dfrac{ \triangle V}{V} = \dfrac{A\triangle l}{Al} = \dfrac{\triangle l}{l}$$
So, $$\dfrac{ \triangle V}{V}$$ is directly proportional to $$\dfrac{\triangle l}{l}$$
Option (A) is correct.
When external force is applied, work done is given by
Work done $$W=mg\Delta x$$
And
$$ {{W}_{2}}=\dfrac{1}{2}\times stress\times strain\times volume $$
$$ \dfrac{1}{2}\times Y\times {{(strain)}^{2}}\times V $$
$$ \dfrac{1}{2}\times Y\times {{(\dfrac{\Delta x}{L})}^{2}}\times AL $$
$$ \dfrac{Y\Delta {{x}^{2}}A}{2L} $$
So, total work done is
$$W=mg\Delta x+\dfrac{Y\Delta {{x}^{2}}A}{2L}$$
Given,
Radius of sphere, $$R$$
Mass placed on massless piston, $$M$$.
Area of piston, $$A$$
Change in pressure $$\Delta P=\dfrac{\Delta F}{A}=\dfrac{Mg-0}{A}=\dfrac{Mg}{A}$$
Volume of sphere, $$v=\dfrac{4}{3}\pi {{R}^{3}}$$
Small decrease in volume, $$-dv=d\left( \dfrac{4}{3}\pi {{R}^{^{3}}} \right)=4\pi {{R}^{2}}dR$$
Bulk modulus, $$B$$
$$ B=\dfrac{dp}{-\dfrac{dv}{v}}=\dfrac{\dfrac{Mg}{A}}{-\dfrac{4\pi {{R}^{2}}dR}{\dfrac{4}{3}\pi {{R}^{3}}}}=\dfrac{Mg}{-3A\dfrac{dR}{R}} $$
$$ -\dfrac{dR}{R}=\dfrac{Mg}{3AB} $$
Hence, fractional decrease in radius of sphere is $$\dfrac{Mg}{3AB}$$
The weight of suspended mass is given as,
$${W_1} = mg$$
The weight of the rod acting at the midpoint is given as,
$${W_2} = \dfrac{{mg}}{2}$$
The stress at the midpoint is given as,
$$\sigma = \dfrac{{{W_1} + {W_2}}}{A}$$
$$\sigma = \dfrac{{mg + \dfrac{{mg}}{2}}}{A}$$
$$\sigma = \dfrac{{3mg}}{{2A}}$$
A thick rope of rubber of density $$1.5 \times {10^3}{\text{kg/}}{{\text{m}}^{\text{3}}}$$ and Young's modulus $$5 \times {10^6}{\text{N/}}{{\text{m}}^2}$$ , $$8 m$$ length is hung from the ceiling of a room , the increases in its length due to its own weight is :
$$\left( {g = 10{\text{m/}}{{\text{s}}^{\text{2}}}} \right)$$
A massless and thin string is wrapped several times around a disc kept on a rough horizontal surface. A boy standing at a distance 'd' for the cylinder holds free end of the string pulls the cylinder towards him. If there is no slipping, length of the string passed through the hand of the boy while the cylinder reaches his hands is
An elastic string carrying a body of mass 'm' extends by 'e'. The body rotates in a vertical circle with critical velocity. The extension in the string at the lowest position is
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