Explanation
$$ \begin{array}{l} L_{0}=3 m, \quad A=2 \times 10^{-6} \mathrm{~m}^{2} \\ \Delta l=3 \times 10^{-3} \mathrm{~m}, \quad y=20 \times 10^{10} \mathrm{Nm}^{-2} \end{array} $$
$$ \begin{aligned} \text { Energy stored in wire } &=\frac{1}{2} \times \text { Stress } \times \text { Strain } \times \text { (Volume of wire) } \\ & \text { or, } \frac{1}{2} \times(\text { Strain })^{2} \times \text { Young's modulus } \times \text { Volume } \\ &=\frac{1}{2} \times\left(\frac{3 \times 10^{-3}}{3}\right)^{2} \times\left(20 \times 10^{10}\right) \times\left(3 \times 2 \times 10^{-6}\right) \mathrm{J} \\ &=0.6 \mathrm{~J} \end{aligned} $$
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