Explanation
Y=FlAΔl
Δl=FlAY
=80×lr(22)2×10−6×2×1011
=5.0×10−4m
=0.5 mm
B=−VdPdV
Thus, ΔV=−pVB or V′−V=−pVB
Or, V′=V(1−pB)
Now, ρ′=mV′=mV(1−pB)=ρ(1−pB)
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