Explanation
Solution:
Hint:
· Find the magnitude of velocity by applying the Kinetic energy formula.
· Find the distance for two revolutions.
· Apply third equation of motion to find the acceleration.
Step 1: Find the velocity of the particle from the given kinetic energy.
12mv2=8×10−4
Here, m is the mass of the particle and v is the velocity.
12×10×10−3×v2=8×10−4
v=0.4m/s
Step 2: Write the total distance covered.
s=2(2πr) ( particle covered two revolutions)
Here, s is the total distance covered.
Step 3: Apply the third equation of motion.
v2−u2=2as (Where v is final velocity, u is initial velocity (given u=0), a is acceleration and s is distance)
⇒(0.4)2=2×a×(4π×6.4×10−2)
∴a=0.1m/s2
Hence, option (a) is the correct answer.
The velocities are given as,
dxdt=6
vx=6
dydt=6
vy=8−10t
The velocity at projection is given as,
v(t)=vxˆi+vyˆj
v(t)=6ˆi+(8−10t)ˆj
v(0)=6ˆi+8ˆj
|v(0)|=√62+82
|v(0)|=10m/s
The velocity of projection is 10m/s.
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