Explanation
Velocity, as a vector, has both magnitude and direction.
It is given that
Mass of person $$m=60\,Kg$$
The person is travelling in a circular path of radius $$r=3\,m$$
Velocity of person is $$v=6\,m/s$$
Centripetal acceleration is
$$ {{a}_{c}}=\dfrac{{{v}^{2}}}{r} $$
$$ {{a}_{c}}=\dfrac{{{6}^{2}}}{3}=12\,m/{{s}^{2}} $$
Force
$$ F=ma $$
$$ =60\times 12 $$
$$ =720\,N $$
Take right side is toward positive, x-axis.
$${{\vec{F}}_{1}}=6(-\hat{i})\,N,\,{{\vec{F}}_{2}}=5\hat{i}\,N\,\,\,\,\,and\,\,\,{{\vec{F}}_{3}}=3(-\hat{i})\,N$$
$${{\vec{F}}_{net}}={{\vec{F}}_{1}}+{{\vec{F}}_{2}}+{{\vec{F}}_{3}}=-6\hat{i}+5\hat{i}-3\hat{i}=4\left( -\hat{i} \right)\,N$$
Hence, force is $$4\,N$$ toward left.
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