Explanation
A force has magnitude 20N. Its one rectangular component is 12N, the other rectangular component must be:
For 1 vector it is never possible to have zero resultant.
For 2 vectors, it is possible when both vectors are exactly of same magnitude and direction of vectors are opposite to each other. But it is given that vectors are of unequal magnitude.
For 3 vectors, from triangle’s addition law it is possible to have zero resultant without having any 2 vectors with same magnitude.
Consider a given figure below:
In this figure, resultant of 3 vectors is zero without having same magnitude of any vectors.
Answer:
Hence, option B is the correct answer.
Calculate the angle between two vectors 2F and$$\sqrt 2 \,{\rm{F}}$$ so that the resultant force is $${\rm{F}}\sqrt {10} .$$
The speed of a projectile at the highest point becomes$$\dfrac{1}{\sqrt{2}}$$ times its initial speed. The horizontal range of the projectile will be
A particle is fired horizontally with a velocity $$98m{s^{ - 1}}$$ from the top of a tower 490m high. The time taken by the projectile to hit the ground is:$$:\left( {g = 9.8m/{s^2}} \right)$$
An object has a displacement from position vector $$ \vec{r_1} = (2\hat{i}+ 3\hat{j} )m$$to $$ \vec{r_2} = (4\hat{i}+ 6\hat{j})m$$ under a force $$\vec{F} = (3x^2\hat{i} + 2y \hat{j} )N,$$ then work done by the force is:
Given,
$$\vec{r}={{\vec{r}}_{o}}(1-at)t$$
Initially at $$t=0, $$ $$\vec{r}=0$$
After completing one rotation
Position vector, $$\vec{r}=0$$
$$ \vec{r}={{{\vec{r}}}_{o}}(1-at)t $$
$$ {{{\vec{r}}}_{o}}(1-at)t=0 $$
$$ t=\,\,0\,,\,\,\dfrac{1}{a} $$
Hence, at time $$t=\dfrac{1}{a}$$ particle return to starting point.
Two forces $$\widehat {\text{i}}{\text{ + }}\widehat {\text{j}}{\text{ + }}\widehat {\text{k}}\;{\text{N}}\;{\text{and}}\;\widehat {\text{i}}{\text{ + 2}}\widehat {\text{j}}{\text{ + 3}}\widehat {\text{k}}\;{\text{N}}$$ act on a particle and displace it from (2,3,4) to point (5,4,3). Displacement is in m. Work done is:
A body starts rotating from rest and completes 10 revolutions in 4 sec. Find its angular acceleration
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