Explanation
Distance = $$V_0 \times 1+\dfrac{V_0}{2}\times 1+\dfrac {V_0}{4}\times 1+.....$$
$$ = V_0 \times \left (1+\dfrac{1}{2}+\dfrac{1}{4}+...... \right ) = 2V_0$$
Given that:
$$2s = gt^{2}$$
$$s = \dfrac{1}{2} gt^{2}$$
Comparing this with the equation:
$$s = ut + \dfrac{1}{2} at^{2} $$
we get,
$$u = 0\ \& \ a=g$$
$$v = u + at = 0 + gt$$
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