Explanation
Distance = V_0 \times 1+\dfrac{V_0}{2}\times 1+\dfrac {V_0}{4}\times 1+.....
= V_0 \times \left (1+\dfrac{1}{2}+\dfrac{1}{4}+...... \right ) = 2V_0
Given that:
2s = gt^{2}
s = \dfrac{1}{2} gt^{2}
Comparing this with the equation:
s = ut + \dfrac{1}{2} at^{2}
we get,
u = 0\ \& \ a=g
v = u + at = 0 + gt
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