Processing math: 82%

CBSE Questions for Class 11 Engineering Physics Oscillations Quiz 16 - MCQExams.com

The total spring constant of the system as shown in the figure will be:
1512088_a10d842fa49d453eb42553090e257ca4.PNG
  • k12+k2
  • [12k1+1k2]1
  • 12k1+1k2
  • [2k1+1k2]1
A particles moves on the x-axis according to the equation x=x0sin2ωt. The motion is simple harmonic 
  • With amplitude x0
  • With amplitude 2x0
  • With time period 2πω
  • With time period πω
A particle moves in x-y plane according to the equation r=(ˆi+2ˆj) Acosωt. The motion of the particle is 
  • simple harmonic
  • uniformly accelerated
  • circular motion
  • projectile motion
A particle executes SHM in accordance with x = A sin ωt. If t1 is the time taken by it to reach from x = 0 to x = 3(A/2) and t2 is the time taken by it to reach from x = (3/2)A to x = A the value of t1/t2 is 
  • 2
  • 12
  • 3
  • 13
Equation of SHM is x=10sin10πt. Find the distance between the two points where speed is 50π cm/sec. x is in cm and t is in seconds
  • 10cm
  • 20cm
  • 17.32cm
  • 5(3+1)cm
The value of phase at   maximum displacement from  the mean position  of a particle in S.H.M. is 
  • π/2
  • π
  • Zero
  • 2π
On the basis of dimensions, decide which of the following relations for the displacement of a particle undergoing simple harmonic motion is not correct?
  • Y=asin2πt/Tcos2πt/T
  • Y = a sin Vt
  • y=aTsin(Kta)
  • Y=a2(sin2πtTcos2πtT)
A block of mass 1kg is connected with a massless spring of force constant 100N/m. At t=0, a constant force F=10N is applied on the block. The spring is in its natural length at t=0. The speed of particle at x=6cm from mean position is:
1702464_aaaefad632b94413803dab4a9ac13805.png
  • 4cm/s
  • 10cm/s
  • 80cm/s
  • 50cm/s
The period of oscillation of a simple pendulum of length L, suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination α, is given by:
  • 2π(Lgcosα)
  • 2π(Lgsinα)
  • 2π(Lg)
  • 2π(Lgtanα)
The equation of an SHM with amplitude A and angular frequency ω in which all the distances are measured from one extreme position and time is taken to be zero at the other extreme position is
  • x=Asinωt
  • x=A(cosωt+sinωt)
  • x=AAcosωt
  • x=A+Acosωt
A particle executing SHM has max acceleration 50cm/s2 , The time period of oscillation of 2 sec and initial displacement 2.5 cm from the equilibrium position.The equation of SHM is (take π2=10)
  • X=2.5sin(πt+π6)cm
  • X=5sin(πt2+π3)cm
  • X=5sin(πt+π3)cm
  • X=5sin(πt+π6)cm
Potential energy of a particle of mass is given by U=U0(1cosax). which of the following can be a possible expression for its time period 
  • 2πma2u0
  • 2πmau0
  • 2πmaU0
  • 2πmu0a
Between the plates of the capacitor with potential difference V across its plate such that upper plate is ve, a ball with positive charge 'q' and mass 'm' is suspended by a thread of length 'l'. If the electrostatic force acting on a ball is less than the gravitational force, what should be the period of the ball?
1702505_f52a9da963d54dba87ccb668a8034573.png
  • T=2π(lg)
  • 2π[1(g+qEm)]
  • T=2π[1(gqEm)]
  • 2π(lmgE)
A particle of mass m moves in  a one-dimensional potential energy U(x)=ax2+bx4, where a and 'b' are positive constants. the angular frequency of small oscillation about the minima of the potential energy is equal to
  • πa2b
  • 2am
  • 2am
  • a2m
A particle of mass 1 kg is moving where potential energy varies as displacement U=10(1cos2x) then:
  • time period for S.H.M. is 2π120
  • speed of particle is maximum at x=0
  • amplitude of oscillation is π4
  • time period for S.H.M. is 2π140
A particle of mass 2 kg is moving on a straight line under the action of force F=(82x)N. The particle is released at rest from x=6 m. For the subsequent motion select the correct options:
  • equilibrium position at x=4
  • amplitude =2 m
  • time to go from x=2 m to 4 m  is  π/2
  • energy of S.H.M. =4 J
A block of mass m is pushed against a spring whose spring constant is k fixed at one end with a wall. The block can slide on a frictionless table as shown in figure. If the natural length of spring is L0 and it is compressed to half its length when the block is released, find the velocity of the block, when the spring has natural length.
1744138_ef7694f29c304c1980dd75563667eb38.png
  • mk0.L02
  • 3k0m.L02
  • k0m.L
  • k0Lm
A ball is hung vertically by a thread of length l from a point P of an inclined wall that makes an angle β with the vertical. The thread with the ball is then deviated through a small angle α(α>β) and set free. Assuming the wall to be perfectly elastic, the period of such pendulum is:
1743929_dc413bbda9034d5b84d789d1eba77e52.png
  • 2lg[sin1(βα)]
  • 2lg[π2+sin1(βα)]
  • 2lg[cos1(αβ)]
  • 2lg[cos1(βα)]
The new angular frequency of the system will be:
  • 10 rad/sec
  • 15 rad/sec
  • 20 rad/sec
  • none of these
If an impulse J is applied at the centre of oscillation in the plane of oscillation, then angular velocity of the rod will be
  • 4JML
  • 2JML
  • 3J2ML
  • JML
The amplitude of oscillation is
  • 32πm
  • 3 m
  • 1πm
  • 1.5 m$
A spring balance has a scale that can read from 0 to 50 kg . The length of the scale is 20 cm. A body suspended from this balance when displaced and released oscillates harmonically with a time period of 0.6 s. The mass of the body is ( take g=10 m/s2)
  • 10 kg
  • 25 kg
  • 18 kg
  • 22.8 kg
For the above question locate the centre of oscillation.
  • L4 from O (down)
  • L4 from O (up)
  • 2L3 from O (down)
  • 7L12 from O (down)
New equation for position of the combined body is
  • (10+3sin5t) cm
  • (103sin5t) cm
  • (10+3cos10t) cm
  • (103cos10t) cm
New amplitude of oscillation is
  • 3 cm
  • 20 cm
  • 10 cm
  • 100 cm
A particle performs simple harmonic motion with amplitude A and time period T. The mean velocity of the particle over the time in interval which it travels a distance of A/2 starting from executing position is 
  • \dfrac{A}{T}
  • \dfrac{2A}{T}
  • \dfrac{3A}{T}
  • \dfrac{A}{2T}
Mark out the correct statement(s).
  • The block-bullet system performs SHM about y=mg/k
  • The block-bullet system performs oscillatory motion but not SHM about y=mg/k.
  • The block-bullet system perform SHM about y=4\ mg/3k.
  • The block bullet system performs oscillatory motion but not SHM about y=4\ mg/3k
Determine the velocity of particle at t=5\ s
  • -0.4\ m/s
  • 0.5\ m/s
  • -0.25\ m/s
  • none\ of\ these
A particle executing harmonic motion is having velocities v_1 and v_2 at distances in x_1 and x_2 from the equilibrium position. The amplitude of the motion is 
  • \sqrt{\dfrac{v_1^2x_2-v_2^2x_1}{v_1^2+v_2^2}}
  • \sqrt{\dfrac{v_1^2x_1^2-v_2^2x_2^2}{v_1^2+v_2^2}}
  • \sqrt{\dfrac{v_1^2x_2^2-v_2^2x_1^2}{v_1^2-v_2^2}}
  • \sqrt{\dfrac{v_1^2x_2^2+v_2^2x_1^2}{v_1^2+v_2^2}}
The velocity of the particle when it reaches B will be
  • zero
  • 3\sqrt{gl}
  • 2\sqrt{gl}
  • \sqrt{gl}
Motion of an oscillating liquid column in a U-tube is 
  • Periodic but not simple harmonic.
  • non-periodic.
  • Simple harmonic and time period is independent of the density of the liquid.
  • Simple harmonic and time-period is directly proportional to the density of the liquid.
A particle doing simple harmonic motion, amplitude = 4\ cm, time period = 12\ sec. The ratio between time taken by it in going from its mean position to 2\ cm and from 2\ cm to extreme position is
  • 1
  • 1/3
  • 1/4
  • 1/2
0:0:1


Answered Not Answered Not Visited Correct : 0 Incorrect : 0

Practice Class 11 Engineering Physics Quiz Questions and Answers