Explanation
The force exerted by two springs attached in parallel to a wall and a mass exert a force
$$ k_{eq}=k_{1}x+k_{2}x$$
on the mass. Thus, the effective spring constant is given by
Given,
A S.H.M have amplitude A.
So, its total Initial Kinetic Energy of the system is $$\dfrac{1}{2}m{{\omega }^{2}}A$$
Energy given to the system is $$\dfrac{1}{2}m{{\omega }^{2}}A$$. This energy gets added to system energy.
Total final Kinetic energy is = Total initial kinetic energy + added kinetic energy
$$ \dfrac{1}{2}m{{\omega }^{2}}A{{'}^{2}}=\dfrac{1}{2}m{{\omega }^{2}}{{A}^{2}}+\dfrac{1}{2}m{{\omega }^{2}}{{A}^{2}} $$
$$ A'=A\sqrt{2} $$
Hence, New amplitude is $$A\sqrt{2}$$
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