Explanation
Two particles A and B, initially at rest, moves towards each other under a mutual force of attraction. At the instant when the speed of A is $$u$$ and the speed of B is $$2 u$$, the speed of centre of mass is
We have
torque $$=\tau=rF\sin { 90° } =\cfrac{ LF }{ 4 } $$
And perpendicular axis theorem gives us
$$I={ I }_{ 2 }={ I }_{ x }+{ I }_{ y }=\cfrac{ M{ L }^{ 2 } }{ 12 } $$
Angular acceleration,
$$\alpha =\cfrac{ \tau }{ I } =\cfrac{ LF }{ 4 } \times \left( \cfrac{ 12 }{ M{ L }^{ 2 } } \right) =\cfrac{ 3F }{ ML } $$
If $$\theta$$ is the angle rotated in time $$t$$, and initial angular velocity $${ w }_{ 0 }$$being zero we have
$$\theta ={ w }_{ 0 }t+\cfrac{ 1 }{ 2 } \alpha { t }^{ 2 }=\cfrac{ 3F{ t }^{ 2 } }{ 2ML } $$
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